A large beaker of water is filled to its rim with water. a block of wood is then carefully lowered into the beaker until the block is floating. in this process, some water is pushed over the edge and collects in a tray. the weight of the water in the tray is?

Answers

Answer 1

Weight of water = V * 1000 kg/m^3 * 9.8 m/s^2 = V * 98000 N/m^3

What is weight?

The weight of an object is described as the force acting on the object due to gravity.

The weight of the water pushed over the edge of the beaker will be equal to the buoyant force acting on the floating block of wood, hence the buoyant force is equal to the weight of the water displaced by the block.

We can calculate using the following formula:

Weight of water = Volume of water displaced * Density of water * g

We do not have the values of V

Weight of water = V * 1000 kg/m^3 * 9.8 m/s^2 = V * 98000 N/m^3

In conclusion, this weight will be in Newtons, which is the unit of force. \

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Related Questions

we can only do ideal calculations when we are at standard temperature and pressure.

Answers

False. Not only at standard temperatures and pressures, but also at any other temperature and pressure, ideal computations can be performed.

What are the typical pressure and temperature?

STP, or standard temperature and pressure, refers to the nominal atmospheric conditions at sea level. The temperatures and pressures are 0 ° Celsius and 1 atmosphere, respectively.

What purpose does STP serve in chemistry?

The term for standard temperature & pressure in chemistry is STP. STP is most frequently used when calculating gas properties, like gas density. A standard pressure equals 1 atm, and the standard temperature equals 273 K (0° C or 32° F).

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The complete question is-

We can only do ideal calculations when we are at standard temperature and pressure.

Group of answer choices

A) True

B) False

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