a group of five students is being selected for a leadership group. they are being selected from a group of 12 nominees.

The sample standard deviation is 0.03

As per the given data, a quality engineer has taken the 20 samples in which each containing of 100 batteries.

The total number of the defective batteries which are observed over the 20 samples is 200.

Here we have to calculate the value of the sample standard deviation

The number of samples, k = 20

The number of batteries in each sample:

The sample size = 100

The total number of batteries of the sample are:

The total number of samples, [tex]$\sum{n=20 \times 100=2000}$[/tex]

[tex]& \bar{n}=\sum_\frac{n}{k}} \\[/tex]

= [tex]$\frac{2000}{20}[/tex]

= 100

The total number of defective batteries = 200

Now we can calculate the proportion of the deflective battery:

Therefore, [tex]$\bar{p}=$[/tex] The total number of defectives ÷ The total number of samples

= [tex]$\frac{200}{2000}[/tex]

= 0.10

The standard deviation, [tex]$\sigma_{\mathrm{p}}=\sqrt{\frac{\bar{p} \bar{q}}{\bar{n}}}$[/tex]

= [tex]$ \sqrt{\frac{0.1 \times 0.9}{100}} \\[/tex]

= [tex]& \sqrt{0.0009} \\[/tex]

=  0.03

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The total time elapsed on the astronauts' chronometers is 20 years. This is calculated by subtracting the time spent traveling to and from the distant planet (2 * 10 years = 20 years) from the total time elapsed on Earth (26 years).

This result takes into account the time dilation effect of special relativity, which states that time passes more slowly for a moving object relative to a stationary observer. Since the astronauts were traveling at high speeds for much of their journey, the time elapsed on their chronometers would be less than the time elapsed on Earth.

The total time elapsed on the astronauts' chronometers is 20 years. This is calculated by subtracting the time spent traveling to and from the distant planet (2 * 10 years = 20 years) from the total time elapsed on Earth (26 years).

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The sample mean is 358.54, and the sample median is 365. To keep the median unchanged, we could increase or decrease the largest value by up to 49 seconds. The values of mean and the median in minutes are 5.97 and 6.08.

The sample mean can be calculated as follows:

mean = (sum of all observations) / (number of observations)

mean = (373 + 370 + 364 + 366 + 364 + 325 + 339 + 393 + 356 + 359 + 363 + 375 + 424 + 325 + 394 + 402 + 392 + 369 + 374 + 359 + 356 + 403 + 334 + 397) / 26

mean = 358.54

The median can be calculated by arranging the observations in order and finding the middle value. With 26 observations, we'll find the average of the two middle values.

median = (364 + 366) / 2 = 365

To keep the median unchanged, we need to maintain the same number of observations on either side of the median. In this case, with 26 observations, there are 13 observations on either side of the median. To keep the median unchanged, we need to keep the range of the data the same, which means the difference between the maximum and minimum values should remain the same.

The range of the data is 424 - 325 = 99 seconds.

So, to keep the range the same, the largest value could be increased or decreased by up to half of the range, which is:

99 seconds / 2 = 49 seconds.

To express the observations in minutes, we'll divide each observation by 60.

mean in minutes = 358.54 / 60 = 5.97

median in minutes = 365 / 60 = 6.08

So, the values of mean and the median in minutes are 5.97 and 6.08, respectively.

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Your question is incomplete, but I suppose the question was:

"A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) to complete the escape: 373 370 364 366 364 325 339 393 356 359 363 375 424 325 394 402 392 369 374 359 356 403 334 397

a. Calculate the values of the sample mean and median.

b. By how much could the largest time, currently 424, be increased without affecting the value of the sample median? By how much could this value be decreased without affecting the value of the sample median?

c. What are the values of mean and the median when the observations are re-expressed in minutes?"

The exact values of the remaining trigonometric functions of θ are:

sin(θ) = √(1/64)

cos(θ) = -8

tan(θ) = -8√(1/64)

csc(θ) = 1

cot(θ) = -√(1/64) / 8

Given that sec(θ) = -8 and sin(θ) > 0, we can find the exact values of the remaining trigonometric functions using the Pythagorean identity:

sec^2(θ) = 1/sin^2(θ)

Substituting the value of sec(θ), we have:

(-8)^2 = 1/sin^2(θ)

64 = 1/sin^2(θ)

sin^2(θ) = 1/64

sin(θ) = ±√(1/64)

Since sin(θ) > 0, we take the positive square root:

sin(θ) = √(1/64)

Next, we use the reciprocal identity for cosecant:

csc(θ) = 1/sin(θ)

Substituting the value of sin(θ), we have:

csc(θ) = 1/√(1/64) = 8√(1/64) = 8/√(64) = 8/8 = 1

Next, we use the reciprocal identity for cotangent:

cot(θ) = 1/tan(θ)

We can find the value of tan(θ) using the definition:

tan(θ) = sin(θ) / cos(θ)

Substituting the values of sin(θ) and cos(θ), we have:

tan(θ) = √(1/64) / (-8) = -√(1/64) / 8

Finally, we use the reciprocal identity for a tangent:

tan(θ) = 1/cot(θ)

Substituting the value of cot(θ), we have:

tan(θ) = -8√(1/64)

Therefore, the exact values of the remaining trigonometric functions of θ are:

sin(θ) = √(1/64)

cos(θ) = -8

tan(θ) = -8√(1/64)

csc(θ) = 1

cot(θ) = -√(1/64) / 8

The complete question is:-

Find the exact value of each of the remaining trigonometric functions of

θ. Rationalize denominators when applicable.

secθ=−8, given that sinθ>0

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The required value of the x in the given circle is given as,
5. x = 9   6. x = 4  7. x = 5  8. x = 8

Orientation of the one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as the angle.

Here,
5.
For the given circle,
The sum of all sections should be equal to 360°.
65 + 34 + 41 + 16 +6x + 150 = 360
x = 9

Similarly,
6. x = 4
7. x = 5
8. x = 8

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The range of possible numbers will be  (-∞ , 16.6] as per the given conditions.

In mathematics, inequalities specify the connection between two non-equal numbers. Equal does not imply inequality. Typically, we use the "not equal sign ()" to indicate that two values are not equal. But several inequalities are utilized to compare the numbers, whether it is less than or higher than.

Given, I’m thinking of a number. When you multiply it by 5 and subtract 3 you will get a number less than 80.

Let "x" be the number

Thus from the given expression

=> 5*x - 3 < 80

add 3 on both sides

=> 5x -3 + 3 < 80 +3

=> 5x < 83divide by 5 into both sides

=> x < 83/5

=> x < 16.6

thus the range of x for the given Condition will be (-∞ , 16.6]

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P(A) is the probability of observing 3 on first trial. P(B) is probability of observing 3 after at least 2 trials. P(A U B) is total probability of observing 3.

(a) The probability of observing a 3 on the first trial is 1/6. So, p(a) = 1/6.

(b) The probability of not observing a 3 on the first trial is 5/6.

If a 3 is not observed on the first trial, then the same experiment will be repeated with a 5/6 chance of not observing a 3 again.

This can be represented as (5/6)^2.

The probability of not observing a 3 on the first two trials is (5/6)^2.

So, the probability of observing a 3 on the third trial is

1 - (5/6)^2

This can be represented as

1 - (5/6)^n     where n is the number of trials

The probability of requiring at least two trials to observe a 3 is the sum of the probabilities of observing a 3 on the third, fourth, fifth, etc. trials. This is equivalent to the sum of an infinite geometric series. The sum can be calculated using the formula

S = a/(1 - r)        where S is the sum, a is the first term, and r is the common ratio.

In this case, a = 1 - (5/6)^2 and r = 5/6. So, the sum is S = (1 - (5/6)^2)/(1 - 5/6) = 6/36 = 1/6. Therefore, p(b) = 1/6.

(c) The probability of observing a 3 on the first trial or at least two trials is the sum of p(a) and p(b). So, p(a or b) = p(a) + p(b) = 1/6 + 1/6 = 1/3.

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The solution to 2log9(x)=log9+ log9(x-2) is 4.

Two or more expressions with an Equal sign is called as Equation.

The given equation is 2log9(x)=log^9(8)+log9(x-2)

Above equation can be written as below

Log₉x² = log₉8 + log₉(x-2)

Loga+Logb=Log ab from properties of logarithms

Log₉x² = log₉(8×(x-2))

Log₉x² = log₉8x-16

Log₉x² - log₉8x-16 = 0

Loga-logb=log(a/b)

Log₉(x²/(8x-16)) = 0

x²/(8x-16) = 9°

x² = 1 × 8x-16

x²-8x+16 = 0

x²-4x-4x+16 = 0

(x-4)(x-4) =0

x=4

Hence,  the solution to 2log9(x)=log9+ log9(x-2) is 4.

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Yes, the function f(x) = 3 sin(2x) is periodic. The smallest positive period of this function is 2π/2 = π.

f(x) = 3 sin(2x) This is because the function is sinusoidal and the period of a sinusoidal function is 2π/n,

where n is the coefficient in front of the x (which in this case is 2). Thus, the period of f(x) = 3 sin(2x) is 2π/2 = π.

This means that the function will repeat itself after every π units. To verify this, we can plug in x = 0 and x = π into the equation and see that we get the same value, 3 sin(2(0)) = 3 sin(0) = 0 and 3 sin(2(π)) = 3 sin(2π) = 0, showing that the function repeats itself after every π units.

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The sequence of the grains should be from smallest to largest as follows:

1. Breccia, Siltstone

2. Conglomerate

3. Sandstone

4. Shale

A sequence is an enumerated group of items in mathematics where repetitions are permitted and order is important.

It has members, just like a set does.

The length of the sequence is determined by the number of items.

You should be familiar with the following four main categories of sequences: arithmetic sequences, geometric sequences, quadratic sequences, and special sequences.

So, because the grain size of breccia and siltstone is the same, they should be assigned the same number.

- A cement-like substance holds angular shards of varying sizes together to form a rock called breccia.

- It can also be generated from volcanic ash or other materials but is often formed from angular shards of other rocks.

- A sedimentary rock called siltstone is made up of clay-sized particles and often has smaller grains than sandstone.

- A cementing substance holds rounded or sub-rounded grains and pebbles together to form the sedimentary rock known as a conglomerate.

- Sand-sized particles make up the sedimentary rock known as sandstone, which is often created from quartz grains.

- The last sedimentary rock is shale, which typically has a grain size lower than sandstone and is made up of clay-sized particles.

Therefore, the sequence of the grains should be from smallest to largest as follows:

1. Breccia, Siltstone

2. Conglomerate

3. Sandstone

4. Shale

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Complete question:

points question at position 6 put the following rocks into proper order, from smallest grains (1) to largest (4). note: there are a pair of rock types that have the same grain size. give them the same number.

A) Breccia

B) Conglomerate

C)Sandstone

D) Shale

E) siltstone

a) The sample is a systematic sample., b) It may not be representative of all people in line for the roller coaster., c) The sampling frame is all the people who are willing to wait in line for the roller coaster.

a) A systematic sample is a sample where individuals are selected from a larger population at regular intervals or through a set pattern. In this case, the amusement park is selecting every 15th person in line, making it a systematic sample.

b) The sample may not be representative of the population of people in line for the roller coaster because by only including every 15th person, certain groups of people who are similar may be overrepresented or underrepresented in the sample, potentially leading to a biased representation of the opinions of the people waiting in line.

c) The sampling frame for this survey is the population of people waiting in line for the roller coaster. This is the group of individuals from which the sample will be taken. In this case, the sampling frame is not limited to just the patrons of the park, or all the people who go to amusement parks, but is specifically focused on the people waiting in line for the roller coaster.

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When a journal entry contains a debit to inventory, a corresponding credit to an offsetting account, such as Cost of Goods Sold (COGS), is required.

A journal entry that contains a debit to inventory requires a corresponding credit to an offsetting account, such as Cost of Goods Sold (COGS). The formula for the entry would be:

Debit Inventory

Credit Cost of Goods Sold (COGS)

The calculation would depend on the cost of the inventory, the quantity purchased and the applicable tax rate. For example, if the cost of the inventory is $5,000, the quantity purchased is 500 and the applicable tax rate is 5%, the journal entry would look like this:

Debit Inventory $5,000

Credit Cost of Goods Sold (COGS) $4,750 ($5,000 x 95% = $4,750)

In this example, the total cost of the inventory was $5,000, but the credit to COGS was calculated by multiplying the cost of the inventory ($5,000) by 95% (the applicable tax rate of 5% was subtracted). The resulting amount of $4,750 was the amount credited to COGS.

In summary, when a journal entry contains a debit to inventory, a corresponding credit to an offsetting account, such as Cost of Goods Sold (COGS), is required. The formula for the entry is: Debit Inventory, Credit Cost of Goods Sold (COGS). The calculation for the entry depends on the cost of the inventory, the quantity purchased and the applicable tax rate.

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The reasoning based on the information will be:

a) Deductive reasoning.

b) Deductive reasoning.

Deductive reasoning follows a top-down method, whereas inductive reasoning follows a bottom-up method. While deductive thinking involves drawing conclusions by moving from general premises to specific conclusions, inductive reasoning involves moving from the specific to the general.

A specific conclusion is reached by the logical process of inductive reasoning, which combines several premises that are all generally accepted as true or discovered to be true. Applications that involve prediction, forecasting, or behavior use inductive reasoning frequently. In both cases, deductions were made based on the information.

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The value of Sinθ 1/√197, cos θ = 14/√197, csc θ = H/P =√197, sec θ =√197/14, Cot θ = 14

Trigonometric functions are real functions in mathematics that connect an angle of a right-angled triangle to ratios of two side lengths. They are widely utilised in all geosciences, including navigation, solid mechanics, celestial mechanics, geodesy, and many more.

Trigonometry employs six fundamental trigonometric functions. These ratios are trigonometric functions. The sine function, cosine function, secant function, co-secant function, tangent function, and co-tangent function are the six fundamental trigonometric functions. The ratio of sides of a right-angled triangle is the basis for trigonometric functions and identities.

if triangle is form,

Then Perpendicular(P) = 1 and Base(B) = 14

Then Hypotenuse(H) = √(12 + 142)= √197

Then , sin θ = P/H = 1/√197

cos θ = B/H = 14/√197

csc θ = H/P = √197/1 = √197

sec θ = H/B =√197/14

Cot θ = B/P = 14/1 = 14

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The complete question should be:

use the definition or identities to find the exact value of each of the remaining five trigonometric functions of the acute angle, given that tan θ = 1/14 ,

Compared to your regular wage without overtime, this would push your monthly budget up by $607.63.

In a budget, projected expenses are stated together with suggestions for how to fund them. A budget can show a surplus of resources for future use or a deficit where expenses are greater than income or other resources.

Surplus Budget, Balanced Budget, and Deficit Budget are 3 types of annual governmental budgets based on estimation. A balanced budget is one in which the revenues are larger than the expenses or equal to them. In the above link, you can read about the Highlights of the Union Budget for UPSC.

Let's calculate the regular earnings for 40 hours of work first:

Regular earnings = $11.75 x 40 hours = $470

Next, let's calculate the overtime earnings:

Overtime rate = $11.75 x 1.5 = $17.63

Overtime earnings = $17.63 x 20 hours = $352.60

Now let's add the regular earnings and overtime earnings to get the total gross pay for the month:

Total gross pay = $470 + $352.60 = $822.60

Now let's calculate the deductions:

FICA = $822.60 x 7.65% = $63.17

Federal tax withholding = $822.60 x 10.75% = $89.11

State tax withholding = $822.60 x 7.5% = $61.69

Total deductions = $63.17 + $89.11 + $61.69 = $214.97

So, the net pay for the month (total gross pay minus total deductions) would be:

Net pay = $822.60 - $214.97 = $607.63

Therefore, working 20 hours of overtime would increase your budget by $607.63.

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Based on the provided information, standard error is 0.138, z-score is 2.898, and p value is 0.0013995.

The standard error of a statistic refers to the standard deviation of its sampling distribution or an estimate of that standard deviation. It indicates how different the population mean is likely to be from a sample mean. Standard error of two samples is given by:

SE = √((S1^2)/n1+(S2^2)/n2)

In the given case s1 = 0.5, n1 = 40, s2 = 0.8, and n2 = 50. Hence,

SE = √(〖0.5〗^2/40+〖0.8〗^2/50)=0.138

Z-score for two samples is given by:

z = ((x1-x2)/SE) where x1 and x2 are sample means

In the given case x1= 5.35 and x2 = 4.95. Hence,

z = ((x1-x2)/SE) = (5.35-4,95)/0.138=2.898

The p -value from the table is when p(x >z) = 0.0013995.

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A. The pair of segments that is parallel will be AB & EF, DH & CG, and BC & FG. Then the correct option is A.

B. The line G and line K will be a skew line. Then the correct option is B.

One of the first areas of mathematics is geometry, along with maths. It is preoccupied with spatial characteristics including the separation, form, size, and relative placement of objects. A geometer is a mathematician who specializes in shape.

A.  The parallel edges of the rectangular is given below.

AB = CD = EF = GH

AE = DH = CG = BF

BC = AD = EH = FG

The pair of segments that is parallel will be AB & EF, DH & CG, and BC & FG. Then the correct option is A.

B.  The line G and line K will be a skew lines. Then the correct option is B.

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The value of 'z' in the equation [tex]25^{(z + 4)} = 125[/tex] is, z = - 2.5.

Some common rules of exponents are

xᵃ×xᵇ = xᵃ⁺ᵇ.

xᵃ/xᵇ = xᵃ⁻ᵇ.

Addition and subtraction of exponents are only possible for the same base value and when the base is different and both have the same exponent we just multiply the bases and write the exponent.

Given, An exponential equation [tex]25^{(z + 4)} = 125[/tex].

We know, 5² = 25 and 5³ = 125.

Therefore, [tex](5^2)^{(z + 4)} = 5^3[/tex] , Having the same base we can equate the exponents.

2(z + 4) = 3.

2z + 8 = 3.

2z = - 8 + 3.

2z = - 5.

z = - 2.5.

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There are 280 students attending the play.

Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.

Both linear equations with one variable and those with two variables exist.

Given  student tickets cost $6 each and adult tickets cost $11 each,

let a number of students be x and the number of tickets be y

total tickets sold = 400

x + y = 400

and total amount made = $3000

so 6x + 11y = 3000

from equation 1,

y = 400 - x

substitute in the equation,

6x + 11y = 3000

6x + 11(400 - x) = 3000

6x + 4400 - 11x = 3000

-5x = 3000 - 4400

-5x = -1400

x = 1400/5

x = 280

and y = 400 - 280

y = 120

Hence 280 students attended the play.

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The correct selling price of an item will be $12.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that a  store is instructed by corporate headquarters to put a markup of ​25% on all items. An item costing ​$24 is displayed by the store manager at a selling price of ​$6.

The selling price will be calculated as:-

Selling price = 25% of 24 + $6

Selling price = 6 + 6

Selling price = $12

Hence, the selling price of the item is $12.

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Answer:

84m²

Step-by-step explanation:

Area if a parallelogram is base×height

base=7m

height=12m

area=7m×12m=84m²

1. An equation that represents "the amount of tax on an item of price p",

t = p x X / 100

2. Marta does pay on an item whose price is $20, $1.6

Percentage is a way to express a number as a fraction of 100. It is often used to represent ratios and proportions in a more convenient and understandable form, especially in financial and statistical contexts. For example, 50% means 50 per 100, or half of a given quantity. It is denoted using the symbol "%".

Given that,

Tax rate = 8%

1. Let's assume that the sales tax rate is X%.

Then, the equation that represents the amount of tax (t) Marta pays on an item whose price is p can be written as:

t = p x X / 100

2. If the price of the item is $20, the amount of tax Marta pays can be calculated as follows:

t = $20 x X / 100

t = $20 x 8 / 100

t = $1.6

So, Marta pays $1.6 in sales tax on an item whose price is $100.

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The probability of selecting an 8 is [tex]\frac{4}{52}[/tex] since there are 4 total 8's available (8 of hearts/spades/diamonds/clubs) out of 52 cards. This simplifies to [tex]\frac{1}{13}[/tex]. The probability of selecting a face card is [tex]\frac{12}{52}[/tex] since there are 4 Jacks, 4 Queens, and 4 Kings. This simplifies to [tex]\frac{3}{13}[/tex].  1 - [tex]\frac{3}{13}[/tex] = [tex]\frac{13}{13}[/tex] - [tex]\frac{3}{13}[/tex] =[tex]\frac{10}{13}[/tex].

There are four suits (hearts, spades, diamonds, and clubs), each with 13 cards from Ace to King, in a conventional 52-card deck of playing cards. As a result, there are four of each potential card.

(A) The probability of selecting an 8 is  [tex]\frac{4}{52}[/tex] since there are 4 total 8's available (8 of hearts/spades/diamonds/clubs) out of 52 cards. This simplifies to [tex]\frac{1}{13}[/tex].

(B) The probability of selecting a face card is [tex]\frac{12}{52}[/tex] since there are 4 Jacks, 4 Queens, and 4 Kings. This simplifies to [tex]\frac{3}{13}[/tex].

(C) The probability of NOT selecting a face card is [tex]\frac{40}{52}[/tex] since there are 4 of each card from Ace through 10 that are not face cards. This simplifies to 10/13. The solution to part B's question can be used as another way to approach this issue. If the probability of selecting a face card is 3/13, then the probability of NOT selecting a face card has to be 1 - [tex]\frac{3}{13}[/tex] = [tex]\frac{13}{13}[/tex] - [tex]\frac{3}{13}[/tex] =[tex]\frac{10}{13}[/tex]. Recall that you must deduct from 1 since the probability of all conceivable outcomes must add up to 1, or 100%.

Therefore, the probability of selecting an 8 is [tex]\frac{4}{52}[/tex] since there are 4 total 8's available (8 of hearts/spades/diamonds/clubs) out of 52 cards. This simplifies to [tex]\frac{1}{13}[/tex]. The probability of selecting a face card is [tex]\frac{12}{52}[/tex] since there are 4 Jacks, 4 Queens, and 4 Kings. This simplifies to [tex]\frac{3}{13}[/tex]. the probability of NOT selecting a face card has to be 1 - [tex]\frac{3}{13}[/tex] = [tex]\frac{13}{13}[/tex] - [tex]\frac{3}{13}[/tex] =[tex]\frac{10}{13}[/tex].

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Therefore , the solution of the given problem of linear equation comes out to be monthly amount she applies to it is $550.

Using the formula y=mx+b, a simple regression curve is constructed. The slope is B, and the y-intercept is m. Even if y or y are separate portions, the foregoing sentence is frequently referred to as a "mathematical formula merging many variables." In bivariate linear equations, there are only two variables. Application problems involving linear equations have no known solutions.

Here,

Given :

=> $150 extra in her debt

her debt be x

y be the amount she already pays

=> amount left

=> x - y - 150

=> x- (y+150)

Let x be 1000

y be 300

=> 1000 -(300+150)

=> 1000 -450 = 550

Thus,

monthly amount she applies to it is $550

Therefore , the solution of the given problem of linear equation comes out to be monthly amount she applies to it is $550.

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The area of the right triangle is 80.5 square units.

The area of a triangle is described as the total region that is enclosed by the three sides of any particular triangle.

In the right triangle, one of the legs is equal to 7, as the side length of the square inscribed in it.

We will use the Pythagorean theorem to find the length of the other leg and the calculation is shown below:

a^2 + b^2 = c^2

7^2 + b^2 = 24^2

49 + b^2 = 576

b^2 = 527

b = √t(527) = 23

The area of the right triangle is then:

A = (1/2)ab = (1/2) * 7 * 23 = (1/2) * 161 = 80.5 square units

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The image of the point b(7/2 , -6/5) is (7/18,-2/15)

A Cartesian coordinate system in a plane is a coordinate system that specifies each point uniquely by a pair of numerical coordinates,

Given here: A dilation has center (0,0) and image of the point b (7/2,-6/5)

Now it is given that the scale factor is 1/9

Thus the image of the given point is

x=7/2×1/9

x=7/18

y=-6/5×1/9

y=-2/15

Thus the image is (7/18,-2/15)

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The graph of the function is V-shaped, vertex domain and range are (-3,0), all the real values and [0, ∞);

The absolute value function, with vertex (h,k), is defined as follows:

y = |x - h| + k.

The features of the function are given as follows;

Vertex: (h,k).

Domain: All real values;

Range: [k, ∞).

Given;

g(x) = |× + 31|

Therefore, for the first item of the function is |x + 3|, since we just have to identify the features;

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The values of a and b, considering the range of the function, are given as follows:

The range of a function is the set that contains all the output values that can be assumed by the function.

Hence, considering the graph, the range of a function is given by the values of y from the graph.

The minimum and maximum value of the function are given as follows:

Hence the values of a and b are given as follows:

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The values of x are 13 and 11

Algebraic expressions are expressions having terms, variables, coefficients, constants and factors.

They are also made up of arithmetic operations.

Given that;

(x - 1)²= 50

expand the bracket

x² - x - x + 1 = 50

collect like terns

x² - 2x + 1 = 50

x² - 2x - 49

Factorize the expression

(x² - 13x) + (11x - 49)

Factor the common terms

x(x - 13) + 11(x - 13)

x = 13. x = -11

Hence, the values are 13 and 11

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