Using the Venn sets, the amounts are given as follows:
a) 1358 students.
b) 688 students.
c) 1758 students.
d) 746 students.
e) 371 students.
f) 771 students.
What are the Venn Sets?For this problem, we consider the following sets:
Set A: students taking History.Set B: students taking Dance.Set C: Students taking Psychology.235 students said they were taking all three courses, hence:
(A ∩ B ∩ C) = 235.
457 students said they were taking Dance and Psychology, hence:
(B ∩ C) + (A ∩ B ∩ C) = 457
(B ∩ C) = 222.
466 students said they were taking Psychology and History, hence:
(A ∩ C) + (A ∩ B ∩ C) = 466
(A ∩ C) = 231.
474 students said they were taking Dance and History, hence:
(A ∩ B) + (A ∩ B ∩ C) = 474
(A ∩ B) = 239.
1012 students said they were taking Psychology, hence:
C + (A ∩ C) + (B ∩ C) + (A ∩ B ∩ C) = 1012
C + 231 + 222 + 235 = 1012
C + 688 = 1012
C = 324.
987 students said they were taking Dance, hence:
B + (A ∩ B) + (B ∩ C) + (A ∩ B ∩ C) = 987
B + 239 + 222 + 235 = 987
B + 696 = 987
B = 291.
921 students said they were taking History, hence:
A + (A ∩ B) + (A ∩ C) + (A ∩ B ∩ C) = 921
A + 239 + 231 + 235 = 921
A + 705 = 921
A = 216.
The number of students who took no courses is given as follows:
None + A + B + C + (A ∩ B) + (A ∩ C) + (B ∩ C) + (A ∩ B ∩ C) = 2129
None + 216 + 291 + 324 + 239 + 231 + 222 + 235 = 2129
None + 1758 = 2129
None = 2129 - 1758
None = 371.
For item a, the amount is:
Dance + None = 987 + 371 = 1358 students.
For item b, the amount is:
(B ∩ C) + (A ∩ B ∩ C) + (A ∩ C) = 457 + 231 = 688 students.
For item c, the amount is the total subtracted by none, hence:
2129 - 371 = 1758 students.
For item d, the amount is:
A + B + (A ∩ B) = 216 + 291 + 239 = 746 students.
For item e, the amount is of 371, as we found previously.
For item f, the amount is:
A + C + (A ∩ C) = 216 + 324 + 231 = 771 students.
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Translate the sentence into an equation.
Nine more than the product of a number and 6 is equal to 4.
Use the variable x for the unknown number.
Answer:
(6x) + 9 = 4
Step-by-step explanation:
Times means 'The answer when you multiply' So we are working in multiplication. ( x )
6x is the multiplication.
It says 'more than' which means adding to our answer. So we add 9. So far our equation is: (6x) + 9 (Brackets are needed as we are multiplying 6 by x and not multiplying 6 by x+9)
Lastly, it says the answer must be 4 so we add that at the end. So the answer is:
(6x) + 9 = 4
16. Audrey and Ginnie volunteer each
month to drive meals to elderly
people. The first month they volun-
teered, they delivered a total of 60
meals. The next month they delivered
1
33 percent more than they did the
first month. The third month they de-
livered twice as many meals as the
first two months combined. How
many meals did the two girls deliver
in the third month?
(J) 80
(K) 90
(L) 160
(M) 280
Answer:
280. Answer choice D
Step-by-step explanation:
1st month: 60 meals
2nd month: 33% more than 1st month - 80 meals
(1 + (33/100)) * 60 = (1.33)(60) = 79.8 meals (Round to 80 meals)
3rd month: 2(60+80) = 280 meals
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(M) 280
Step-by-step explanation:
The first month the girls delivered 60 meals. For the second month 133% of 60 is (60 x 1.33) 79.8 which is ~ 80 meals. 80 + 60 = 140, 140 x 2 = 280
The answer is (M) 280
Calculators were purchased at $100 per dozen and sold at $30 for three calculators. What is the profit on six dozen calculators?
The profit is $
Answer:
30x100= 3000
Step-by-step explanation:
Consider a sample with data values of 10, 20, 12, 17, and 16. Compute the z-score for each of the five observations. If required enter negative values as negative numbers (to 2 decimals).
Z-score of 10 is -1.25; Z-score of 20 is 1.25; Z-score of 12 is -0.75; Z-score of 17 is 0.50; and Z-score of 16 is 0.25.
How do we calculate the Z-scores of each observation?To calculate this, we use the following notations and formulas:
Mean = (sum of the values) / n
Variance = ((Σ(x - mean)^2) / (n - 1)
SD = Standard deviation = Variance^0.5
Z-score = (x - Mean) / SD
Where;
n = number of obsrvations = 5
x = each observation
We now proceed as follows:
Mean = (10 + 20 + 12 + 17 + 16) / 5 = 15
Variance = ((10-15)^2 + (20-15)^2 + (12-15)^2 + (17-15)^2 + (16-15)^2) / (5-1) = 64 / 4 = 16
SD = Variance^0.50 = 16^0.5 = 4
Z-score of 10 = (10 – 15) / 4 = –1.25
Z-score of 20 = (20 - 15) / 4 = 1.25
Z-score of 12 = (12 - 15) / 4 = –0.75
Z-score of 17 = (17 - 15) / 4 = 0.50
Z-score of 16 = (16 - 15) / 4 = 0.25
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About 2 in every 400 people have an extra rib. If there are 580 people in Antoine's middle school, predict how many people have an extra rib.
2.9% of the people in Antonie's middle school have an extra rib
How to calculate the number of people with an extra rib ?Ribs are curved bones that are located in the chest, they help to protect the delicate organs in that part of the body.
About 2 in every 400 people have an extra rib
There are 580 people in Antoine's middle school
The number of people with an extra rib cage can be calculated as follows
= 580 × 2/400
= 1160/400
= 2.9
Hence 2.9% people have an extra rib cage.
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Jane and Jim spend the same amount of money today. If Jim spent 5.25 on food and rode the train three times and Jane spent 12.45 on food and rode the roller coaster twice, then how much does a token cost?
The cost of a Token from the question is; $7.2
How to solve Algebra Word Problems?
We are told that Jane and Jim spend the same amount of money today.
Now, Jim spent 5.25 dollars on food and rode the train 3 times, and Jane spent 12.45 dollars on food and rode the roller coaster twice.
Assuming cost of a token is T, the the algebraic expression formed is;
5.25 + 3T = 12.45 + 2T.
3T - 2T = 12.45 - 5.25
T = $7.2
Thus, we conclude that the cost of a Token is; $7.2
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How many jelly beans are in a 2-liter jar? HELP ME PLEASE
1. The number of sample size 1 jelly beans in a 2-liter jar is 645.
2. The number of sample size 2 jelly beans in a 2-liter jar is 640.
3. The number of sample size 3 jelly beans in a 2-liter jar is 637.
What is a mathematical operation?A mathematical operation is an expression involving the use of mathematical operands and operators to compute values.
Mathematical operations use variables, numbers, and operators (addition, subtraction, division, and multiplication).
Data and Calculations:Total weight = 1,150g
Weight of the jar = 440g
The total weight of the jelly beans = 710g (1,150 - 440)
Sample Size 1: the number of jelly beans = 645 (710/22.0 x 20)
Sample Size 2: the number of jelly beans = 640 (710/22.2 x 20)
Sample Size 3: the number of jelly beans = 637 (710/22.3 x 20)
Thus, the number of jelly beans in a 2-liter jar depends on the sample size of the jelly beans.
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the question is in the picture below
Answer: Answer 2, Triangle A is dilated from the origin by a scale of 1/2 to obtain triangle B
Step-by-step explanation:
Write the ratio as a fraction in lowest terms.
48 minutes to 3 hours
Answer: 4/15
Step-by-step explanation:
3 hours=
3*60 minutes=180 minutes
48:180=
(24*2):(90*2)=
(12*2*2):(45*2*2)=
(4*3*2*2):(15*3*2*2)=4/15
Determine if each statement is TRUE or FALSE.
15. LAGF and LBGE are vertical angles..
Answer:
TRUE
Step-by-step explanation:
na sa inyo na answer
Answer:
Add your questions
Step-by-step explanation:
Triangle PQR has vertives P(2, -4), Q(4, -5), and R(7, -2). It is translated 6 units left and 3 units up to produce Triangle P'Q'R'. Complete table.
The coordinates of the triangle P'Q'R' is P'(x, y) = (- 4, - 1), Q'(x, y) = (- 2, - 2) and R'(x, y) = (1, 1), respectively.
What are the locations of the vertices of the triangle after applying rigid transformations?
In this problem we know the three vertices of a triangle on a Cartesian plane and we must determine the coordinates of its image by applying rigid transformations. According to the statement, the vertices of the image are obtained by applying a translation formula:
P'(x, y) = P(x, y) + T(x, y) (1)
Where:
P(x, y) - Original pointP'(x, y) - Resulting point T(x, y) - Translation vectorIf we know that P(x, y) = (2, - 4), Q(x, y) = (4, - 5), R(x, y) = (7, - 2) and T(x, y) = (- 6, 3), then the coordinates of the vertices of the image are:
P'(x, y) = (2, - 4) + (- 6, 3)
P'(x, y) = (- 4, - 1)
Q'(x, y) = (4, - 5) + (- 6, 3)
Q'(x, y) = (- 2, - 2)
R'(x, y) = (7, - 2) + (- 6, 3)
R'(x, y) = (1, 1)
The coordinates of the triangle P'Q'R' is P'(x, y) = (- 4, - 1), Q'(x, y) = (- 2, - 2) and R'(x, y) = (1, 1), respectively.
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A number is chosen at random from 1 to 10. Find the probability of selecting number 4 or smaller numbers
The probability of selecting number 4 or smaller numbers 2 / 5 .
Probability could be a live of the chance of an occasion to occur. several events can not be expected with total certainty. we are able to predict solely the possibility of an occasion to occur i.e. however doubtless they're to happen, using it. likelihood will direct from zero to one, wherever zero suggests that the event to be Associate in Nursing not possible one and one indicates a definite event.The likelihood formula is outlined because the chance of an occasion to happen is adequate the quantitative relation of variety|the amount|the quantity} of favourable outcomes and also the total number of outcomes.Probability of event to happen P(E) = variety of favourable outcomes/Total variety of outcomes
We have given number from 1 to 10.
The number which are smaller than four and equal to 4 = 4
Total number of outcomes = 10
Probability = 4 /10
= 2 / 5
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is 1/8 equivalent to 2/12
Answer:
No
Step-by-step explanation:
Check by changing to a common denominator
The winning times for the 200-meter dash can be approximated by f(x)=-0.05577x+146.2, where x is the year what is the slope of f
The slope of f is m= -0.05577.
Given : The winning times for the 200-meter dash can be approximated by f(x) = - 0.05577x+146.2 , where x is the year.
To find : The slope of f
Solution : Using slope intercept form a linear function is represented as
y = mx+b
where, m is the slope and b is the y-intercept.
We can write the function as f(x) = - 0.05577x+146.2
Comparing with slope intercept form,
m= -0.05577 and y-intercept = 146.2
Therefore, The slope of f is m= -0.05577
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Which expression is equivalent to (a2/3 1/31/22
OA 7/665/6
OB. 44/32/3
Oca1/261/2
C.
OD. a4/361/6
OE.al/361/6
Answer:
E. a^(1/3)b^(1/6)
Step-by-step explanation:
You want an expression equivalent to (a^(2/3)b^(1/3))^(1/2).
Rules of exponentsThe applicable rules of exponents are ...
(a^b)^c = a^(bc)
(ab)^c = (a^c)(b^c)
ApplicationThe given expression simplifies to ...
[tex](a^{2/3}b^{1/3})^{1/2}=a^{(2/3)(1/2)}b^{(1/3)(1/2)}=\boxed{a^{1/3}b^{1/6}}[/tex]
Marie is having trouble finding the answer to a math problem, so she asks her older brother for
help. He gives her a hint that the correct answer is a rational number. Assuming the hint is
accurate, which value is most likely the correct answer?
OA 1.4142135623...
OB. 2.7182818284..
OC 3.1415926535.
OD 4.1818181818...
The number 4.1818181818... is a rational number because the number is terminating. Then the correct option is D.
What is a rational number?If the value of a numerical expression is terminating then they are the rational number then they are called a rational number and if the value of a numerical expression is non-terminating then they are called an irrational number.
Let's check all the options, then we have
A 1.4142135623..., the number is an irrational number because the number is non-terminating.
B. 2.7182818284..., the number is an irrational number because the number is non-terminating.
C 3.1415926535..., the number is an irrational number because the number is non-terminating.
D 4.1818181818..., the number is a rational number because the number is terminating.
The number 4.1818181818... is a rational number because the number is terminating. Then the correct option is D.
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Represent the following sentence as an algebraic expression, where "a number" is the
letter x. You do not need to simplify.
The product of 3 and the difference of 5 and a number.
The sentence "5 is subtracted from the square of a number" represented as an algebraic expression is x² -5.
Algebraic expressions: what are they?
A group of integers or variables combined using the operations +, -, o, or constitute an expression. algebraic expressions with variables, numbers, and mathematical operators, as opposed to arithmetic expressions that simply contain numbers and mathematical operators.Given,
Let the number be x and 3 is subtracted from a number.
Represent it in expression.
Step 2
3 is subtracted from a number means 3 is subtracted from x.
Here we have to subtract 3 from x. It can be represented as = x - 3
Let the number be x.
In this exercise, you're required to write an algebraic expression to represent the word problem (sentence). Also, the number would be denoted by the letter x and no need for further simplification of the algebraic expression.
Translating the word problem (sentence) into an algebraic expression, we have;
Square of a number (x) = x²
Subtracting 5 from the the square of x, we have x² -5 .
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If you double a number and then subtract eight the result is 18. Which equation below could be used to represent the situation?
Answer: 2x - 8= 18
2x - 8=18
2x=26
x= 13
Simplify the quantity 10 minus three fourths times the square root of 16 end quantity squared plus the quantity 2 minus 7 end quantity squared.
a. 1,394
b. 1,344
c. 74
d. 24
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Simplifying the quantity 10 minus three fourths times the square root of 16 end quantity squared plus the quantity 2 minus 7 end quantity squared is: c. 74.
ExpressionThe given expression:
(10 - 3/4 × ✓16)² + (2 - 7)²
Hence,
Now let simplify the expression
(10 - 3/4 × ✓16)² + (2 - 7)²
=(10 - 3)² + (-5)²
= 7² + 5²
= 49+ 25
= 74
Therefore simplifying the quantity 10 minus three fourths times the square root of 16 end quantity squared plus the quantity 2 minus 7 end quantity squared is: option c. 74.
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Find all points having a -coordinate of whose
distance from the point is .
The points which are a distance of 13 units from (12,5) are (0,0)and (24,0).
The distance between two point with co-ordinates ([tex]x_1,y_1[/tex]) and ([tex]x_2,y_2[/tex]) is calculated by the distance formula [tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
All points on the x-axis have their y-coordinates equal to 0. So let the point (a,0) be a point on the x-axis such that the distance from (12,5) to (a,0) is 13 units.
Let us substitute the values into the distance formula to calculate the values of a so that we can find the two points.
[tex]13=\sqrt{(12-a)^2+(5-0)^2}[/tex]
Squaring both sides we get:
[tex]or,13^2=144-24a+a^2+25\\or,169-144-25-24a+a^2\\or,a^2-24a=0\\or,a(a-24)=0[/tex]
Now either a=0 or (a-24)=0
Therefore either a=0 or a=24.
Therefore the two points (0,0) and (24,0) .
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A flight averages 460 miles per hour. The return flight averages 500 mph because of a tailwind. The total flying time is 4 hours and 48 minutes. How long is each flight
The first flight is 2 hours and second flight is 2 hours and 48 minutes
The two distances are the same (out and back),
so set them equal.
That distance is cover by having one is (rate)(time) equal to other is (rate)(time).
Let,
One time is “x” and the other is “4.8-x.”
One average rate is 460 per hour
and the other average rate is 500 per hour.
we know , Speed = [tex]\frac{distance}{time}[/tex]
so , distance = speed × time
put in this formula we get the value of X
⇒460 x = 500 (4.8 -x)
⇒460 x = 2400 - 500x
⇒900 x = 2400
⇒x = 2.5 hours for the slower plane.
⇒4.8- x = 2.3 hours for the faster plane.
The formula speed = distance ÷ time can be rearranged, just like any other equation.
Here detail explanation about relation between speed distance and time :
The formula can be rearranged in three ways:
speed = distance ÷ time
distance = speed × time
time = distance ÷ speed
To calculate one of the variables (speed, distance or time) we need the other two.
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1: Find the slope:
Y
-9
X
-1
0
1
2
-3
39 what’s the slope
Answer:
Step-by-step explanation:
83.9
Slopes vs. gradients vs. % grades
Slope
Angle (degrees) Gradient Grade (%)
40 1 83.9
41 1 86.9
42 1 90.0
PLEASE HELPE ME FAST
Answer:
S would now only be 3 units from R instead of 6 units from R. Move S three units to the left.
Step-by-step explanation:
Find the x- and y-intercepts of the graph of the equation. (If an
(a)
X^2-xy+4y=49
Answer:
x=±7; y=12.25.
Step-by-step explanation:
1) x-interception:
(y=0): x²=49, ⇒ x=±7;
2) y-interception:
(x=0): 4y=49; ⇒ y=12.25.
What are the possible values of x for the following functions? F(x)=2-x / x(x-1)
Answer:
[tex]x \in \mathbb{R}-\{0,1\}[/tex]
Step-by-step explanation:
The denominator cannot be 0 (since division by 0 is undefined), meaning x cannot be 0 or 1.
So, the domain is
[tex]x \in \mathbb{R}-\{0,1\}[/tex]
What number multiplied by 7/9 as a product of one
Answer:
★ How to do :-
Here, we are given with a fraction in which we are asked to find the second number in which we get it's product when multiplied as one. We aren't given with the appropriate first number but it's written in thr form of multiplication. If we multiply those numbers, we'll get the value of the first number. After finding the first number, we shift thr obtained value from LHS to RHS. We should always remember that while shifting the numbers, the sign of the appropriate number changes. So, let's solve!!
\:
➤ Solution :-
{\tt \leadsto 3 \: \bigg( \dfrac{7}{9} \bigg) \times x = 1}⇝3(97)×x=1
First, multiply the numbers on LHS.
{\tt \leadsto \bigg( \dfrac{3}{1} \times \dfrac{7}{9} \bigg) \times x = 1}⇝(13×97)×x=1
First solve the bracket on LHS.
{\tt \leadsto \dfrac{21}{9} \times x = 1}⇝921×x=1
Shift the first fraction from LHS to RHS, changing it's sign.
{\tt \leadsto x = 1 \div \dfrac{21}{9}}⇝x=1÷921
Take the reciprocal of second fraction and multiply both the fractions.
{\tt \leadsto x = \dfrac{1}{1} \times \dfrac{9}{21}}⇝x=11×219
Multiply the fractions now.
{\tt \leadsto x = \dfrac{9}{21}}⇝x=219
\:
{\red{\underline{\boxed{\bf So, \: the \: other \: number \: is \: \dfrac{9}{21}}}}}So,theothernumberis219
\:
Verification :-
{\tt \leadsto 3 \: \bigg( \dfrac{7}{9} \bigg) \times x = 1}⇝3(97)×x=1
Substitute the value of x.
{\tt \leadsto 3 \: \bigg( \dfrac{7}{9} \bigg) \times \dfrac{9}{21} = 1}⇝3(97)×219=1
Multiply the numbers on LHS in the bracket.
{\tt \leadsto \bigg( \dfrac{7 \times 3}{9 \times 1} \bigg) \times \dfrac{9}{21} = 1}⇝(9×17×3)×219=1
Multiply the numerators and denominators.
{\tt \leadsto \dfrac{21}{9} \times \dfrac{9}{21} = 1}⇝921×219=1
Multiply the numbers on LHS.
{\tt \leadsto \dfrac{21 \times 9}{9 \times 21} = 1}⇝9×2121×9=1
Multiply the numerators and denominators.
{\tt \leadsto \dfrac{189}{189} = 1}⇝189189=1
Write the fraction in lowest form on LHS.
{\tt \leadsto 1 = 1}⇝1=1
So,
{\sf \leadsto LHS = RHS}⇝LHS=RHS
\:
Hence verified !!
36+29+14 joshua rewrote the ecpression as 36+14+29. What property fid joshua use to rewrite the expession
Answer:
Commutative property because it states that the numbers can be moved around or swapped from their position without making any difference to the answer.
What is the measurement of the angle shown below?
Answer:
the answer is 150°
Step-by-step explanation:
because the angle is obtuse angle so obtuse angle measures between 90° and 180° so the rest choices are not correct.
Suppose the time it takes me to drive from my apartment to campus on any given day is uniformly distributed between 16 and 20 minutes. What is the mean amount of time it takes me to drive to campus?
Question 4 options:
20 minutes
24 minutes
12 minutes
18 minutes
16 minutes
Given that the between 16 and 20 minutes driving times to the campus is uniformly distributed, the mean driving time is 18 minutes
The correct option is therefore;
18 minutes How can the mean of a uniform distribution be found?The time it takes to drive from the apartment to the campus = Between 16 and 20 minutes
The nature of the distribution of the travel time = Uniform distributionThe mean of a continuous uniform distribution between two boundaries, a and b is given by the formula;
[tex] \mu = \frac{a+b}{2} [/tex]
The mean amount of time it takes to drive to campus is therefore;
[tex] \mu = \mathbf{\frac{16+20}{2}} = 18 [/tex]
The correct mean driving time is the option;
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For the third week of July, Barbara Watson worked 55.50 hours. Barbara earns $10.40 an hour. Her employer pays overtime for all hours worked in excess of 40 hours per week and pays 1.5 times the hourly rate for overtime hours.