a football is thrown upward at some angle above the horizontal. if we neglect air friction, then we can conclude that the acceleration vector of the football is

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Answer 1

if we neglect air friction, then we can conclude that the acceleration vector of the football is  not accelerating horizontally.

The acceleration vector of the football, neglecting air friction, is directed downward with a constant magnitude of 9.8 m/s^2, which is equal to the acceleration due to gravity. This is because the only force acting on the football is gravity, which pulls it toward the center of the earth, and the direction of the acceleration is equal to the direction of the gravitational force. So, the acceleration vector of the football is given by:

a = (0, -9.8 m/s^2)

where the x-component is 0, because the football is not accelerating horizontally, and the y-component is -9.8 m/s^2 because the acceleration is directed downward.

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Related Questions

a. a spaceship has a rest mass of 500,000 tons. if you could measure its mass when it was traveling at half the speed of light, what would it be? b. a fly has a mass of 1 gram at rest. how fast would it have to be traveling to have the mass of a large suv, which is about 3000 kilograms?

Answers

(a) The mass when a 500,000 tons spaceship traveling at half the speed of light = 250,000tons/c

(b) The velocity of the fly (that has a mass of 1 gram at rest), if have the mass of a large suv, which is about 3000 kilograms = 3000000 m/s

Equation that shows how momentum is directly related to an object's mass (m) and speed (v). The momentum of a large, swift object is greater than that of a small, slower object.

p = m x v

Where,

p = momentum

m = mass (kh)

v = the speed

Hence, the mass of the spaceship:

p = (500,000 tons x 1 m/s)

= 250,000tons/c

(b)

The velocity of the fly:

p = 1g x 1 m/s

Hence,

The velocity = 3000000 m/s

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A loudspeaker on a tall pole broadcasts sound waves equally in all directions. What is the speaker�s power output if the sound intensity level is 107dB at a distance of 17m ?

Answers

The speaker's power output is P = 4 * pi * r*2 * I = 4 * pi * 17*2 * 10*10.7 * I0 if the sound pressure level is 107dB at a distance of 17m.

How is the volume of a sound measured?

A sound's intensity is calculated by dividing its power, expressed in Watts, by the square meters it covers. The intensity of any given sound is related to the intensity at the hearing threshold by the loudness of the sound. Decibels are used to quantify it (dB).

The following equation describes the relationship between distance (r), sound intensity level (L), and sound intensity (I):

L = 10 log10 (I/I0), where I0 denotes the reference intensity (10^-12 W/m^2) and I is the intensity of the sound wave at a distance of r from the source.

Finding the strength of the sound wave at a distance of 17 meters is necessary before applying the power formula (P), which is represented by:

P = 4 * pi * r^2 * I

To find I, we can rearrange the intensity equation as follows:

I = 10^(L/10) * I0

Putting the values in this equation as substitutes:

I = 10^(107/10) * I0 = 10^10.7 * I0

Finally, we can determine the power output using this value of I:

P = 4 * pi * r*2 * I = 4 * pi * 17*2 * 10*10.7 * I0.

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Solve for w.
-w+150 = 220

Answers

Answer:

w = -70

Explanation:

[tex]-w+150 = 220[/tex]

[tex]-w = 70[/tex]

[tex]w = -70[/tex]

Answer: w = -70

Explanation:

   To solve, we will isolate with inverse operations.

Given:

   -w + 150 = 220

Subtract 150 from both sides of the equation:

   -w = 70

Divide both sides of the equation by -1:

   w = -70

if the charge q is displaced from the center a small distance x as shown in the figure, will it undergo simple harmonic motion when released?

Answers

A ring with a radius of R is evenly covered in positive charge Q. At a distance of x from the centre, a particle with mass m and a negative charge q is positioned on its axis.

What is the distribution of positive charge Q?

A ring with a radius of R is uniformly covered with a positive charge Q. At the centre of the ring is a small test charge, q.

Then. If q > 0 and is displaced in the plane of the ring away from the centre, it will be pushed back in that direction.

Charge q will return to its original place after travelling once around a circle with radius r.

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a hall probe gives a reading of \(1.5\mu v\) for a current of 2 a when it is placed in a magnetic field of 1 t. what is the magnetic field in a region where the reading is for 1.7 a of current?

Answers

The magnetic field in the region where the reading is for 1.7 A of current is 3.4 T.

The voltage produced by a Hall probe is proportional to the product of the magnetic field, the current, and a constant known as the Hall coefficient, denoted by "R_H". Mathematically, the relationship can be expressed as:

V = R_H * I * B

Where V is the voltage, I is the current, and B is the magnetic field.

We know the Hall coefficient and the magnetic field for a current of 2 A:

V = 1.5 * 10^(-6) V

R_H = V / (I * B) = 1.5 * 10^(-6) V / (2 A * 1 T)

Next, we can use the value of the Hall coefficient to find the magnetic field for a current of 1.7 A:

B = V / (R_H * I) = 1.5 * 10^(-6) V / (R_H * 1.7 A)

B = (1.5 * 10^(-6) V) / (R_H * 1.7 A) = (1.5 * 10^(-6) V) / (V / (2 A * 1 T) * 1.7 A)

B = (1.5 * 10^(-6) * 2 * 1 * 1.7) / (10^(-6)) = 2 * 1.7 T = 3.4 T

A magnetic field is a force field that is created by a magnetic object or a current-carrying conductor. It is an invisible field that exerts a force on charged particles in motion and causes them to move in a circular path around the magnetic object or conductor. The direction of the magnetic field is determined by the right-hand rule, which states that if you point your thumb in the direction of the current flow and your fingers in the direction of the magnetic field, your thumb will be pointing in the direction of the north pole of the magnetic object.

The strength of the magnetic field is measured in units of Tesla (T) or Gauss (G). A magnetic field is a vector area, which means that it has both significance and path. The magnetic field can interact with other magnetic fields, causing them to attract or repel each other.

Magnetic fields have many practical applications, such as in electric motors, generators, and MRI machines. They are also present in the Earth's atmosphere and play a crucial role in shielding the planet from harmful solar radiation. The study of magnetic fields is a branch of physics known as electromagnetism, which explores the relationship between electricity and magnetism.

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what is the primary form of useful energy output in the case of a car?

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In the case of an automobile, the engine's rotational power, which is transmitted to the wheels, is the main source of usable mechanical energy production.

How is energy created?

Energy is a phrase used to define a characteristic of issue and non-matter fields; energy is not created of anything. For instance, matter is considered to have angular momentum while it is moving.

What does physics use as an example of energy?

Kinetic energy is the energy that has been transformed into motion. Kinetic energy is the force that moves a pendulum. Gravitational potential is the power that an object has as a function of its position. Thus illustrate, because to the effects of gravity, a ball lying on even a table contains potential energy in respect to the ground.

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a closed system allows for the exchange of ___ with the surroundings.

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According to the stated situation, a closed system permits energy transfer to the environment.

What distinguishes surrounds from surrounding?

The word "surrounding" refers to a certain thing's outside surroundings. The term "encircling" may be used as an adjective or an adjective. For instance, in the sentence Skye is around Meena, the word serving as a verb. The term "surroundings" refers to all of the places that are close to a person.

What are some illustrations of environments?

The term "surrounding" refers to anything that is located in close proximity to a certain person, location, or object. Things that might be referred to as encircling your house include the lawn and plants that are found all around it.

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et's compare two telescope's ability to see dimmer objects. one telescope has a a 150mm mirror and the second telescope has a 250 mm mirror. which one can see dimmer objects?

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Reflectors and refractors are the two primary categories of optical telescopes. Refractors utilise a lens to focus light, while reflectors use a mirror.

Can larger telescopes see objects that are fainter?

Compared to tiny telescopes, large telescopes can collect more light. Dimmer objects become visible in more light, and there is more light available for analysis. To gather enough light to perform spectroscopic analysis on an extremely dim object.

one telescope has = 150mm

second telescope has = 250mm

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a golf ball of mass 0.043 kg is hit off the tee at a speed of 41.8 m/s. the golf club was in contact with the ball for 5.13 ms. find the impulse imparted to the golf ball.

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When a golf ball of mass 0.043 kg is struck off the tee at a speed of 41.8 m/s, the impulse given to the golf ball is 1.78 Ns.

What is force?

A force is an effect in physics that may modify the velocity of an item. A force can cause a mass item to change its velocity, or accelerate. Intuitively, force may be characterized as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Here,

The impulse imparted to the golf ball can be calculated as the product of the force applied and the time of contact:

impulse = force * time

Since force is equal to mass times acceleration, we can write:

impulse = m * a * t

where m is the mass of the ball (0.043 kg), a is the acceleration imparted by the club, and t is the time of contact (5.13 ms).

Since the time of contact is short, we can assume that the acceleration is constant, so we can use the equation for impulse-momentum to find the acceleration:

impulse = m * Δv

where Δv is the change in velocity of the ball.

Since the ball starts at rest, its initial velocity is 0 m/s and its final velocity is 41.8 m/s, so Δv = 41.8 m/s.

Substituting the given values into the equation, we get:

impulse = 0.043 kg * 41.8 m/s = 1.78 Ns

So, the impulse imparted to the golf ball is 1.78 Ns when a golf ball of mass 0.043 kg is hit off the tee at a speed of 41.8 m/s.

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tonya wants to estimate what proportion of her school’s seniors plan to attend the prom. she interviews an srs of 50 of the 750 seniors in her school and finds that 36 plan to go to the prom.

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According to the information provided, it should be highlighted that the 750 seniors in the school and made up population of interest, and interest parameter is percentage of seniors who intend to attend prom.

Additionally, a strictly random sample is required in order to create a confidence interval. Additionally, the sample size should be examined to see if it adequately represents the population.Using the z crucial of 1.645, a 90% confidence interval will be built. The sample fraction in this case will be:

= 36/50 = 0.72

Q = 1 - 0.72 = 0.28

n = 50

As a result, the confidence interval will be equal to 50 squared times the combination of 0.72 and 0.28. This amounts to 0.0635.

For a big sample randomly selected among 750 seniors, the interval here on context suggests that we are 90% certain that the fraction of those who desire to attend the prom falls within the interval.

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if a feeder supplied by a 4,160-volt system is protected at 400 amperes, what is the minimum-size aluminum equipment grounding conductor required for the circuit?

Answers

The minimum-size aluminum equipment grounding conductor required for the circuit would be 4 AWG.

The grounding conductor is necessary to ensure that the electrical system is properly grounded. This is an important safety measure that helps to ensure that any electricity that may leak or escape from the system is safely discharged into the ground, rather than being allowed to flow into the building or the surrounding area. It is also important for the proper functioning of the electrical system, as it helps to ensure that the system is properly balanced and that the voltage levels remain stable. The grounding electrode conductor (GEC) needs to be sized in order to be used for a single service.

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if the intensity remains the same but the frequency is doubled to 512 hz , how does this affect the pressure amplitude?

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If the intensity remains the same but the frequency is doubled to 512 Hz , then the pressure amplitude must remain unchanged as well.

What happens to pressure amplitude when frequency is doubled?

The pressure amplitude and the frequency are independent properties of a sound wave, and a change in one does not necessarily affect the other. The intensity of a sound wave is proportional to the square of the pressure amplitude, so if the frequency is doubled and the intensity remains the same, then the pressure amplitude must remain unchanged as well.

In other words, if I = kA^2, where I is the intensity, A is the pressure amplitude, and k is a constant, then if I remains constant, A must remain constant even if the frequency is changed.

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the electrostatic force may be written as . in principle, if we set up an experiment with two charged objects and measure the force between them at various distances, the result should follow this theory. if we plot the data as vs. , how should the graph appear?

Answers

The idea that two metals will transmit electrons to one another when they come into contact, creating an electrical triple layer and an attractive force, is where the electrostatic hypothesis got its start.

In layman's words, what is electrostatic force?

Electrostatic force is the force a charged body applies to another charge or uncharged body as a result of that body's charge. ​Examples: 1. Paper fragments are drawn to plastic that has been touched by wool, hair, or fur. 2.

What kind of force is electrostatic?

Examples of electrostatic interaction are: With the aid of a comb, we can create electrostatic force when we run a paper piece through the oils in our heads. When one balloon is brushed with hair, the other balloon becomes drawn to it.

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If we quadruple the energy in a vessel of gas, what happens to the velocity of the gas particles?A) The velocity doublesB) The velocity quadruplesC) The velocity halves D) The velocity stays the same

Answers

If we quadruple the energy in a vessel of gas, the thing that happens to the velocity of the gas particles is: B) The velocity quadruples.

What is velocity quadruples?

According to the ideal gas law, PV = nRT,

where:

P = pressure

V =  volume

n = number of moles of gas

R = gas constant

T = temperature (in kelvin)

If we quadruple the energy in a vessel of gas, this would result in a corresponding increase in temperature (T) of the gas. As a result, the velocity of the gas particles would increase. The root mean square velocity (u) of a gas particle can be expressed as:

u = √(3RT/M)

where:
M = molar mass of the gas

Since T has increased, the velocity of the gas particles would also increase by a factor of √(T2/T1). If T has quadrupled, the velocity of the gas particles would also quadruple.

Therefore the correct option is B.

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two large parallel conducting sheets are charged with equal but opposite charges. what is the electric field in the space between the sheets?

Answers

The electric field in the space between the two parallel conducting sheets is zero.

This is because the electric field is generated by the difference in charge between two points, and because the two sheets have equal and opposite charges, the electric field between them is zero.

electric field : A physical field created by electrically charged objects is known as an electric field. It has an impact on how charged items behave when they are close to the field. Other charged things are affected by the electric field by being drawn to or repelled by it. Electric charges or shifting magnetic fields can produce electric fields.

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the initial kinetic energy of the neutron is 1.10 10-13 j. find its final kinetic energy and the kinetic energy of the carbon nucleus after the collision.

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Its final kinetic energy and the kinetic energy of the carbon nucleus after the collision is 28%.

You can determine the after-collision velocities for two particles (masses m1 and m2, beginning velocities u and u next) in [1] for a completely elastic head-on collision:

[tex]v_{1}[/tex] = ([tex]u_{1}[/tex]×([tex]m_{1}[/tex] - [tex]m_{2}[/tex]) + 2×[tex]\frac{m_{2}\times u_{2} }{m_{1}+m_{2}}[/tex]

[tex]v_{2}[/tex] = ([tex]u_{1}[/tex]·( [tex]m_{2}[/tex]- [tex]m_{1}[/tex]) + 2×[tex]\frac{m_{1}\times u_{1} }{m_{1}+m_{2}}[/tex]

Let subscript 1 stand for a proton and subscript 2 for a nucleus. Since the nucleus was initially at rest, or u=0, its subsequent velocity is given by:

[tex]v_{2}[/tex]  = 2×[tex]\frac{m_{1}\times u_{1} }{m_{1}+m_{2}}[/tex]= 2×[tex]\frac{ u_{1} }{1+\frac{m_{2}}{m_{1}} }[/tex]

Therefore, the nucleus's kinetic energy following the collision is:

[tex]E_{2}[/tex] = [tex]\frac{1}{2}\times m_{2} \times v_{2} ^{2}[/tex] = 2×[tex]\frac{ u_{1}^{2} \times m_{2} }{1+(\frac{m_{2}}{m_{1}})^2 }[/tex]

The amount of kinetic energy from the neutrons that is transmitted to the nucleus is:

f =[tex]\frac{E_{2} }{E_{1} }[/tex]

= [ 2×[tex]\frac{ u_{1}^{2} \times m_{2} }{1+(\frac{m_{2}}{m_{1}})^2 }[/tex] / [ [tex]\frac{1}{2}\times m_{1} \times u_{1} ^{2}[/tex] ]

= 4[tex]\frac{\frac{m_{2} }{m_{1} } }{1+(\frac{m_{2} }{m_{1} })^2}[/tex]

= 4×[tex]\frac{12 }{1+12^2}[/tex]

= 0.28

= 28%

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during the stance phase of running a 140 lb runner, exerts an average vertical force of 1150 n. what is the average vertical acceleration of the runner? think about what this means in terms of the vertical velocity of the runner at foot contact and toe-off.

Answers

The runner accelerates on average at 4.5 m/s2. The rocket's vertical acceleration (av) is then calculated using the formula av = [T - W] / m.

What is the maximum height's vertical acceleration?

In falling object, the substance or body is launched into the air and only experiences a vertical downward acceleration (g) at each time. The projectile will therefore experience an acceleration in the vertical downward direction of 9.80 m/s2 at its highest point.ΣFy=ma 1150-623N Ma a = F/m=527=8.3m/52 63.6

How do you determine a runner's power?

P is equal to ECOR*v+0.5*cdA*v3/m. The most crucial factor in determining a runner's caliber is their specific power P/m. While ordinary runner could have a value of around 3 Watts/kg, world-class runner may have a particular power of more over 6 Watts/kg.

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when the wave goes across the boundary from string 1 to string 2, the frequency is unchanged. what happens to the velocity? when the wave goes across the boundary from string 1 to string 2, the frequency is unchanged. what happens to the velocity? the velocity increases. the velocity stays the same. the velocity decreases.

Answers

The velocity of the sinusoidal wave decreases when it travels from string 1 to string 2 because the linear density of string 2 is different, causing the wave to slow down. Thus, Option C holds the truth.

When a sinusoidal wave travels from one string to another with a different linear density, its velocity changes due to the change in tension and mass per unit length of the string. The velocity of the wave is proportional to the square root of the tension divided by the mass per unit length.

If the linear density of string 2 is higher than that of string 1, the wave will slow down as it travels across the boundary because the increased mass per unit length will result in a decrease in velocity. Conversely, if the linear density of string 2 is lower, the velocity of the wave will increase as it travels across the boundary.

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how does the magnitude of the work done on the system compare to magnitude of the net heat entering the system?

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The magnitude of the work done on a system and the magnitude of the net heat entering the system are both forms of energy, but they represent different types of energy transfer.

Work is done on a system when an external force causes a displacement of the system. This can result in a transfer of energy to or from the system, depending on the direction of the displacement and the force. The magnitude of the work done on the system is given by the product of the force and the distance over which it acts.

On the other hand, heat is a form of energy that is transferred from a hotter object to a cooler object. It is related to the random motion of particles within a substance and is transferred from areas of higher temperature to areas of lower temperature.

In general, the magnitude of the work done on a system and the magnitude of the net heat entering the system are not directly comparable because they represent different types of energy transfer.

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in the arrhenius equation, the collision frequency and molecular orientation are incorporated in the value of_______

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The Arrhenius equation takes into account both of the postulates of the collision theory of reaction rates. The frequency factor A is proportional to the frequency of collisions with the right orientation.

The Arrhenius equation is given by k = Ae^(-Ea/RT), where A is the frequency or preexponential component and e^(-Ea/RT) is the percentage of collisions with energy sufficient to break through the activation barrier at temperature T. The pre-exponential factor, also referred to as A, is the frequency factor. This is essentially a constant discovered through experimentation. It typically represents the frequency of molecular collisions during a process. Arrhenius investigated how temperature affected reaction rates and proposed that the rate constant changes exponentially with temperature.

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a ball starts from rest and accelerates at 0.495 m/s2 while moving down an inclined plane 9.85 m long. when it reaches the bottom, the ball rolls up another plane, where, after moving 13.4 m, it comes to rest. what is the speed of the ball at the bottom of the first plane?

Answers

The speed of the ball at the bottom of the first plane is 1.67 m/s

The speed of the ball at the bottom of the first plane can be calculated using the kinematic equation:

v = v0 + at

Where v is the final velocity (speed), v0 is the initial velocity (0 m/s since the ball started from rest), a is the acceleration (0.495 m/s^2), and t is the time elapsed. To find the time elapsed, we can use the distance traveled and the acceleration:

d = v0t + 0.5at^2

Rearranging for time and substituting the values, we get:

t = sqrt(2d/a) = sqrt(2 * 9.85 m / 0.495 m/s^2) = 3.36 s

Now that we have the time elapsed, we can use the kinematic equation to find the velocity:

v = v0 + at = 0 m/s + (0.495 m/s^2) * (3.36 s) = 1.67 m/s

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if the field of view is 0.45 mm (millimeters) in diameter and three cells can fit lengthwise across the field of view, how long is one cell?

Answers

If the field of the view is 0.45 mm in the diameter and the three cells can fit lengthwise across the field of the view, The long is one cell is 150 micron.

The diameter of the field = 0.45 mm

The  three cells can be fit lengthwise across the field of the view.

The diameter in micron is as follows :

0.45 mm = 0.45 × 1000 micron = 450 micron

In 450 micron = 3 cells

The length of the cell = 450 micron / 3

The length of the cell = 150 micron

Thus, The length of the cell is 150 micron.

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What is the force experienced by a person whose momentum changes by 7kgm/s in 6s?
Give your answer to 1 decimal place.

Answers

Answer:

[tex]1n[/tex]

The answer is 1N.

Explanation:

Greetings!!

Given values :-

momentum(p)= 7kgm/s

time(t)= 6s

Required values:-

force(F)=?

solution:-

Firstly, recall the momentum-force equation

p=F.t

substitute known variables into the equation

(7)=F(6)

solve for force

F= 1.167N

1.167 Rounded to the Nearest Whole Number

Therefore, we have to round down: the whole number ones place value of 1.167, 1, remains 1, and the decimal point and all digits (. 167) are removed. 1.167 rounded to the nearest whole number = 1.

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when brass of length 100cm at 50degreeCelcius is heated it's length changes to 100.054cm at ________ temperature. Take the linear expansivity of brass to be 1.8x10raise to power -5 per Kelvin​

Answers

Answer:

80

Explanation:

PLEASE HELP ME!! I JUST NEED TO FND WHICH EVENT GOES TO EITHER ERA. I AM SO DESPERATE THAT IT IS WORTH 40 POINTS!!

Answers

Answer:

1-6 goes to the cenozoic era. 7-12 goes to the paleozoic era.13-16 goes to the Mesozoic era 17-20 goes to the Precambrian Time

air a high pressure at the surface. moves across moves towards rises above converges into sinks above question content arearising air creates what type of pressure system at the surface? high converging reciprocal low diverging question content arearain often occurs at areas of low surface pressure. true false

Answers

Pressure is a key meteorological factor that governs weather patterns and sheds light on their intensities, especially those of tropical cyclones.

Where air is present, there is a high surface pressure?

High air pressure areas are referred to as high pressure systems. A low-pressure system's center keeps its pressure lower than its surroundings. The air where the winds meet rise in the atmosphere as they blow in the location of a low-pressure area.

Why does the pressure rise?

Why does blood pressure rise.Usually, high blood pressure comes on gradually. Unhealthy lifestyle decisions, such as not engaging in adequate regular physical activity, can contribute to it. Obesity and certain medical problems like diabetes might raise one's risk of acquiring high blood pressure.

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a horizontal force of 94.7 n is applied to a 32.5 kg crate on a rough, level surface. if the crate accelerates at 1.23 m/s2, what is the magnitude of the force of kinetic friction (in n) acting on the crate?

Answers

Answer:

The magnitude of the force of kinetic friction is 54.725 Newtons

Explanation:

We can use Newton's Second Law of Motion to evaluate the force of friction.

Newton's Second Law states

[tex]F_n_e_t=ma[/tex]

The formula for friction force is

[tex]F_{F}=\mu F_N[/tex]

[tex]F_N[/tex] is the normal force

The formula for normal force on a level surface is

[tex]F_N=mg[/tex]

In this example we have positive horizontal force and the force due to friction opposing the motion of the crate.

Let [tex]F_H[/tex] represent the horizontal force.

Therefore we can say the net force in this example is

[tex]ma=F_H-F_F[/tex]

Solving for [tex]F_F[/tex] gives us

[tex]F_F=F_H-ma[/tex]

In this example we are given

[tex]F_H=94.7\\m=32.5\\a=1.23[/tex]

Lets substitute our known values into our equation.

[tex]F_F=94.7-32.5*1.23[/tex]

Evaluate and simplify.

[tex]F_F=94.7-39.975[/tex]

[tex]F_F=54.725[/tex]

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Did ancient stargazers know that the planets were planets, or did they think they were stars?

Answers

Ancient stargazers did not know that the planets were planets. They thought they were stars because they move against the background of fixed stars.

What do stargazers do?

Stargazers are people who observe and study celestial objects and phenomena in the night sky, such as stars, planets, galaxies, nebulae, etc. They can be professional astronomers or hobbyists.

How can one do stargazing?

Stargazing can be done with the bare eye, binoculars, or telescopes. Stargazers can engage in a variety of activities, including observing celestial objects, tracking the movements of the planets, making sketches or photographs of the night sky.

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what magnitude of force, in newtons, must an 97.5-kg grouper exert to stay submerged in salt water (with density 1025 kg/m3) if its body density is 1015 kg/m3?

Answers

The force which is exerted by an object that is submerged in a fluid can be calculated using the equation of buoyant force:

Fb = ρf * V * g

where:

Fb = buoyant force

ρf = density of the fluid (1025 kg/m3 for salt water)

V = volume of the object

g = acceleration due to gravity (9.8 m/s^2)

As the density of the grouper (1015 kg/m3) is less than the density of the fluid (1025 kg/m3), the following object will experience an upward buoyant force.

So to stay submerged, the grouper must exert a force which is equal to the buoyant force in the opposite direction, that is downward.

Therefore, to find the volume of the grouper:

V = m / ρb

where:

m = 97.5 kg (mass of the grouper)

ρb = 1015 kg/m3 (density of the grouper)

Substituting the values into the equation:

V = 97.5 kg / 1015 kg/m3 = 0.096 m^3

Next, calculating the buoyant force:

Fb = ρf * V * g

= 1025 kg/m3 * 0.096 m^3 * 9.8 m/s^2

= 967.68 N

The magnitude of the force the grouper must exert to stay submerged is equal to the buoyant force:

F = 967.68 N

So, the grouper must exert a force of 967.68 N to stay submerged in salt water.

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while traveling outside the united states, you feel sick. a companion gets you a thermometer, which says your temperature is 39. what scale is that on? what is your fahrenheit temperature? should you seek medical help?

Answers

It is recommended to get medical help if you have a temperature of 39°C (102.2°F), as this is considered a fever and it is crucial to identify the reason and get the right care.

The explanation for the given question is:

If your temperature is greater than 100.4°F (38°C), you have a fever. 39 degrees Celsius is comparable to 102.2 degrees Fahrenheit. It's possible that your temperature was recorded in Celsius by the thermometer. If you are feeling ill when traveling outside of the United States, it is advised to seek medical assistance since a temperature of 39°C is regarded as a fever. To identify the source of your fever and obtain the appropriate care if required, it is essential to keep an eye on your symptoms and seek medical guidance. Don't forget to stay hydrated and get plenty of rest.

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