A cook checks the temperature of soup being held for service and it is 130 fahrenheit to cook reheats the suit to 165 this is example of:________

The specific set of equations that describe motion in terms of acceleration, displacement, time, and velocity are given as,

v = u + at.

v² = u² + 2as.

s = ut + ½at²

where, v is final velocity, u is initial velocity, t is time , s is displacement , a is acceleration. The above equation shows the equations of linear motion .

The acceleration is defined as ,the change in velocity (Δv) over the change in time (Δt), The unit is [tex]m/s^{2}[/tex]

acceleration (a) = Δv/Δt.

The velocity is defined  as the rate of change of displacement .The unit is given by m/s.

Δv= Δx/Δt

In the above equation, Δv is change in velocity,  Δx & Δt are the change in distance and time respectively.

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The Mass of chlorine gas is [tex]2.60[/tex] × [tex]10^{3}[/tex] [tex]g Cl_{2}[/tex]

Mass of [tex]P_{4}=455 g[/tex]

Phosphorus and Chlorine gas are the reactants.

Phosphorus pentachloride is the product.

[tex]_P_{4}(S)+_Cl_{2}(g) ------- > _PCl_{5}(S)[/tex]

Place 1,10 and 4 as the coefficients of [tex]P_{4} ,Cl_{2} ,[/tex] and [tex]PCl_{5}[/tex]

[tex]_P_{4}(S)+10Cl_{2}(g) ------- > 4PCl_{5}(S)[/tex]

Multiply the calculated number of moles of [tex]Cl_{2}[/tex] by its molar mass. The molar  mass of [tex]Cl_{2}[/tex] is 70.90 g/mol.

Mass of [tex]Cl_{2}[/tex] needed = 36.7232 mol [tex]Cl_{2}[/tex] × [tex]\frac{70.90 g Cl2}{1 mol Cl2}[/tex] = [tex]2.60[/tex]×[tex]10^{3}[/tex] [tex]g Cl_{2}[/tex]

Fertilizers are the principal application for phosphorus, which is used in the form of concentrated phosphoric acid. Additionally, insecticides, detergents, plasticizers, and baking powder all contain phosphorus-based chemicals.

Phosphate is a key component of fertilisers and supports high crop yields. It is essential to the entire agriculture sector and cannot be easily replaced. Phosphate rock mining, however, is occurring at an unsustainable rate. By utilising microorganisms to precipitate the phosphorus, some researchers are attempting to recover phosphorus from wastewaters.

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The integral as a limit of Riemann sums using right endpoints is =lim (n→∞) n ∑i=1[(ln(1+(4+8i/n)2)−sin(4+8i/n))8/n].

The definite integral is defined here in terms of its limit.

So the definite integral goes as follows.

∫f(x)dx= lim(n→∞) n∑i=1 f(xi)Δx.

Where, for each positive integer n, we let Δx=(b−a) /n

And in case of i=1,2, 3..., n, we let xi=a+iΔx.

For Δx

For each n, we get

Δx=(b−a)/n= (12−4)/n=8/n

For xi

Xi = a+iΔx = 4+i8/n=4+8i/n

For f(xi)

∫124 [ln(1+x2) −sin x] dx

=lim (n→∞) n ∑i=1[(ln(1+(4+8i/n)2)−sin(4+8i/n))8/n]

The Riemann integral, developed by Bernhard Riemann, was the first exact formulation of the integral of a function over an interval in the field of mathematics known as real analysis.

It was presented to the faculty at the University of Göttingen in 1854, but it wasn’t until 1868 that it was published in a journal.

The Riemann integral can be found using the calculus fundamental theorem for a variety of functions and real-world situations, or it can be roughly approximated using numerical integration.

The Riemann integral can be thought of as the limit of a function’s Riemann sums as the finer the partitions are.

The function is referred to as being integrable if the limit exists (or more specifically Riemann-integrable). By making the partition fine enough, the Riemann sum can be brought as close as desired to the Riemann integral.

The mesh of the partitions must, among other things, get smaller and smaller until, at the limit, it is zero.

If this were not the case, then on specific subintervals, we would not be receiving a fair approximation to the function. Actually, this is sufficient to define an integral.

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The density of galena is 7.56 g/cm³.

We need to know about the density to solve this problem. Density can be described as how much the mass is in a volume unit. It can be written

ρ = m / V

where ρ is density, m is mass and V volume

From the question above, we know that

m = 12.4 g

V = 1.64 cm³

By substituting the given parameter, we can calculate the density

ρ = m / V

ρ = 12.4 / 1.64

ρ = 7.56 g/cm³

Hence, the density of galena is 7.56 g/cm³.

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Answer:

heliocentrism, a cosmological model in which the Sun is assumed to lie at or near a central point (e.g., of the solar system or of the universe) while the Earth and other bodies revolve around it.

The speed when it collides with a metal atom = 27.5m/s

A particle or item in motion has a form of energy called kinetic energy. When work, which entails the energy transfer is done on an object by applying a net force, that object acquires kinetic energy.

In the electric field, the electron loses potential energy while gaining kinetic energy. You may calculate the kinetic energy as

[tex]K=\frac{m_e v^2}{2}=e E d[/tex]

Here,

[tex]\text { } m_e=9.11 \cdot 10^{-31} \mathrm{~kg}[/tex] is the mass of the electron;

[tex]e=1.6 \cdot 10^{-19} C[/tex] is the charge of the electron;

E is the electric field;

The distance that an electron travels is called d;

When we solve for the electron's speed, we arrive at:

[tex]v=\sqrt{\frac{2 e E d}{m_e}}[/tex]

Calculate yields:

[tex]v=\sqrt{\frac{2 \cdot 1.6 \cdot 10^{-19} C \cdot 0.060 N / C \cdot 3.6 \cdot 10^{-8} \mathrm{~m}}{9.11 \cdot 10^{-31} \mathrm{~kg}}} \approx 27,5 \mathrm{~m} / \mathrm{s}[/tex]

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One-half second after starting from rest, a freely falling object will have a speed of about 5 m/s.

Falling things include goods, tools, garbage, and rubbish that are blown, dropped, or displaced from heights.

Physical science research frequently involves the study of gravity. Of course, what makes things fall is the force of gravity. A force of attraction between two objects is constant. This pulling force is similar to the pull of gravity.

given free fall from rest i.e.

initial velocity u=0 m/s

acceleration  a = 10m/s2

time t=0.5 seconds

we know final velocity v = u + at = 0 + (10 *0.5) = 5m/s

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Answer:

Potential

Explanation:

hope this helps

The difference quotient that best approximates the instantaneous rate of change is 1.

Average rate of change is rate at which one value within a function changes in relationship to another. The average rate of change is usually used to determine slope of a graphed function.

Let's explore how to find average rate of change and use linear and nonlinear functions to demonstrate it.

The average rate of change the formula is used to find the slope of a graphed function. To find average rate of change, divide the change in y-values by the change in x-values.

Finding average rate of change is particularly useful for determining changes in measurable values like average speed or average velocity.

We can define average rate of change of a function f(x) in interval [a, b] as:

[tex]r=\frac{f_{b}-f_{a} }{b-a}[/tex]

Particularly, if we want to find an approximation of rate of change for a particular value x', we can choose:

a < x' < b

Such that a and b are close to x'.

Then if we want to find the instantaneous rate of change of g at x = 0, we need to find the values of a and b really close to zero.

Looking at the table, we can choose:

a = -0.001

b = 0.001

(are two closer ones to zero)

Then rate of the change can be written as:

[tex]f(x)=\frac{g(0.001)-g(-0.001)}{0.001-(-0.001)}=\frac{2.001-1.999}{0.002}=1[/tex]

From that, we can conclude that a good approximation of instantaneous rate of change is 1.

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Answer:

approx  33 ft

Explanation:

 One atmosphere of pressure is added per 33 ft of depth

Water has the maximum specific heat capacity of any fluid.

The amount of heat that one gram of a material needs either absorb or lose in order to alter its temperature by a degree Celsius is known as specific heat. This equates to one caloric, or 4.184 Joules, for water.

Although the hydrogen bonds in water are much too weak to be compared to intra - molecular bonds like covalently or ionic bonds, they are nevertheless strong enough to require a lot of energy to break. Water boils at 100°C for this reason.

Many people believe hydrogen bonding is the cause of water's high specific heat.

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Answer: applied

Explanation:

If John is 20.0 meters away from me and he is running away from me at 5.0 m/s. I sprint at 7.0 m/s to catch up. Then, I will take 10 seconds to reach him.

We know that,

Speed = Distance / Time

Time = Distance / Speed

Given that,

My speed = 7 m/s

John's speed = 5 m/s

Distance I need to cover to catch up John = ( 20 + x ) m

Distance John will cover before I catch up to him = ( x ) m

Since the time taken by both of us to reach that point is same,

( 20 + x ) / 7 = x / 5

100 + 5x = 7x

2x = 100

x = 50 m

Time required = Distance / Speed = 50 / 5        

Time required = 10 seconds  

It will take me 10 seconds to reach John.

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In the sample, 15 women have body temperatures that are lesser than 98 degrees Fahrenheit.

The correct option is D.

In mathematics, and much more specifically through the graph theory, a chart is a structure that essentially consists of a set of objects, some of which are paired together to form "related" objects. The related pairs of vertices are known as edges, and the objects are equivalent to mathematical abstractions known as vertices.

Graphs are frequently used to visually represent data relationships. Data that are too numerous or complex to be adequately described in the text and in a smaller amount of space are presented using graphs.

Graphs come in a variety of shapes and sizes, including connected and disconnected graphs, bipartite graphs, weighted graphs, directed and undirected graphs, and simple graphs.

As we can see in the graph:

In class limit 96-97 = 3

In class limit 97-98 = 12

Therefore, 3+12 = 15

Approximately 15 women.

In the sample, 15 women have body temperatures that are lesser than 98 degrees Fahrenheit.

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I understand that the question you are looking for is:

This histogram shows body temperatures, in degrees Fahrenheit, for 65 healthy adult women. frequency 40 97 98 99 temperature 100 101 Approximately how many women in the sample have a body temperature lower than 98 degrees Fahrenheit?

A. 45

B. 50

C. 20

D. 15

sine wave or sinusoidal wave -

sine wave can be described as a geometric waveform that oscillates periodically.

It retains its wave shape when added to the another sine wave of the same frequency.

It is a continuous wave.

the general form of sine wave is

y = asin(bx)

where

amplitude is the maximum displacement from its mean position to extreme position.

Periodicity is a repeating continuous pattern which determine its wavelength and frequency.

Frequency of sine wave.

1kHz that is sine wave goes through thousand complete cycle in one second.

Speed of sine wave.

Speed = frequency x wavelength

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Answer: no

Explanation: every action has an equal and opposite reaction

According to the given statement the value of :

a -  [tex]\overrightarrow{\mathrm{A}}=\mathrm{A}_{\mathrm{x}} \hat{\mathrm{i}}+\mathrm{A}_{\mathrm{y}} \hat{\mathrm{j}}=-3.00 \hat{\mathrm{i}}+2.00 \hat{\mathrm{j}}[/tex]

b - θ is in the second quadrant so θ = 180⁰ + (-33.7⁰) = 146⁰

c-[tex]\overrightarrow{\mathrm{B}}=3.00 \hat{\mathrm{i}}+6.00 \hat{\mathrm{j}}[/tex]

In science, anything that has both a direction and a magnitude is referred to as a vector. They are typically represented by pointing arrows, the length of which denotes the size of the vector.

The component description of  A is just restated to constitute the answer to part (a):

A[tex]_x[/tex] = -3.00 , A[tex]_y[/tex] = 2.00

(a) [tex]\overrightarrow{\mathrm{A}}=\mathrm{A}_{\mathrm{x}} \hat{\mathrm{i}}+\mathrm{A}_{\mathrm{y}} \hat{\mathrm{j}}=-3.00 \hat{\mathrm{i}}+2.00 \hat{\mathrm{j}}[/tex]

(b) [tex]|\overrightarrow{\mathrm{A}}|[/tex] =  √(A[tex]_z[/tex]² + A[tex]_y[/tex]²) = √( (-3.00)² + (2.00)²) = 3.61

θ = tan -1 [tex]\left(\frac{\mathrm{A}_{\mathrm{y}}}{\mathrm{A}_{\mathrm{x}}}\right)[/tex] = tan-1 [tex]\left(\frac{2.00}{-3.00}\right)[/tex] = -33.7⁰

θ is in the second quadrant so θ = 180⁰ + (-33.7⁰) = 146⁰

(c) R[tex]_x[/tex] = 0, R[tex]_y[/tex] = -4.00 and [tex]\overrightarrow{\mathrm{R}}=\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}[/tex]   thus [tex]\overrightarrow{\mathrm{B}}=\overrightarrow{\mathrm{R}}-\overrightarrow{\mathrm{A}}[/tex]   and

B[tex]_x[/tex] = R[tex]_x[/tex] -A[tex]_x[/tex] = 0-(-3.00) = 3.00,

B[tex]_y[/tex] = R[tex]_y[/tex] - A[tex]_y[/tex] = -4.00-2.00= -6.00

therefore [tex]\overrightarrow{\mathrm{B}}=3.00 \hat{i}+6.00 \hat{j}[/tex].

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The complete question is -

Vector  A  has a negative x component 3.00 units in length and a positive y component 2.00 units in length. (a) Determine an expression for  A in unit-vector notation. (b) Determine the magnitude and direction of  A. (c) What vector  B  when added to  A  gives a resultant vector with no x component and a negative y component 4.00 units in length.

Most polycrystalline materials consist of randomly arranged crystals or "grains." Although individual grains have different orientations and behave anisotropic ally by themselves that's why the properties of polycrystalline materials are most often isotropic.

Polycrystalline materials, or polycrystals, are solids that are made out of numerous crystallites of shifting size and direction. Most materials are polycrystalline, made of countless crystallites kept intact by meager layers of shapeless strong. Most inorganic solids are polycrystalline, including all normal metals, numerous earthenware production, shakes, and ice. The crystallite size can be determined from the full width at half most extreme force (FWHM) estimated on the adjusted diffraction profile. The guideline of crystallite size estimations by x-beam diffraction depends on the way that the Fourier change of various size crystallites shifts contrarily with the size of the crystallite.

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This system's potential energy changed by 40 J.

Energy = charge * potential difference

=> Energy = (8v)*5

=> Energy = 40 J

Hence the answer is 40 J.

Potential difference, often known as voltage, is equal to the amount of current times the resistance. One Joule, or one Volt, of energy is required for one Coulomb of charge to flow from one place in a circuit to the another.

V=U q, The change in the potential energy of a charge q transported from point A to point B, divided by the charge, is what is used to determine the electric potential difference between points A and B, or VBVA. The joules per coulomb unit of the potential difference is called the volt (V).

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The approximate angular separation of the sun and the full moon is 180°

The full moon is opposite the sun in the sky, and rises as the sun sets is may be understand as ,the Moon can be seen in the day light  sky at any phase except for the new moon, when it's invisible to us, and full moon, when it's below the horizon during the day. The crescent through quarter phases are high in the sky during the day, but the daytime gibbous phases can be glimpsed only just before the Sun sets

In the crescent  phase, the lit-up part of the Moon increases from 0.1% to 49.9%. is growing, while crescent refers to the curved sickle shape.

The gibbous moon is the phase of moon in that appears more than half lighted but less than full.

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According to the calculation the volume of gold = 115.79ml

density is the mass of the material substance per unit volume. d = M/V, in which d is density, M is weight, and V is volume, is the formula for density.

The formula for calculating density is the weight of such an object multiplied by its volume. The mathematical formula for this is d = m/v, where s t stands for density, m for mass, and v for the volume of the item.

Mass of gold nugget =  2.20 kg

                                  = 2.20 x 1000

                                  = 2200g

Density of a gold = 19 g/cm^3

                            =  19 g /mL

Substituting the value in the formula:

Density = Mass / Volume.

volume = mass / density

volume = 2200 g / 19 g/mL

             = 115.79ml

According to the calculation the volume of gold = 115.79ml

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weight of sweets and candy is 1.6kg

It is given that a total weight of 2 kg is allowed by the postal service

The weight of cookies is given to be 400gm

we know that 1kg =1000gm

400gm= 400/1000 gm =0.4kg

Therefore weight of sweets and candy that Amy can send=

total weight- weight of cookies

=2kg - 0.4kg

=1.6kg

Therefore, weight of sweets and candy is 1.6kg

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1012, a record is declared as follows: the first letter in the first name is stored in location 1000. Each letter takes one location and an integer takes two locations.

Multiplication and Division of Integers: the merchandise of a positive integer and a negative integer is negative: the merchandise of two positive integers is positive. The product of two negative integers is positive.

They are important because they assist to facilitate certain calculations by including integer negative numbers. In addition, they also include all negative and positive numbers without a percentage point.

The whole numbers are real numbers that don't have fractions, decimals, and negative numbers. It's neither positive integer nor negative. Zero obeys the rule of whole numbers. Positive numbers are greater than 0 and located to the proper of 0 on the variety line.

Negative numbers are but 0 and located to the left of 0 on the variety line. The quantity zero is neither positive nor negative. Zero is neither positive nor negative. It's the sole number with such characteristics.

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The charge will the potential be 100 V =  1.112 x10⁻¹² C

distance is 4.994 × 10⁻⁵m

v = 100V

K = 8.988 x 10⁹ NM²/C²

r = 1.00 μC

charge may be defined as physical quantity which experience force when placed in an electromagnetic field.

It is measured in coulomb (C)

It is represented by the symbol q.

The formula to find how far from a 1.00 μC point charge will the potential be 100V.

V = kq / r     ........1

q = rV/ K

Where

V = Electric potential

q = charge

r = distance

k = Coulomb's constant.

Charge = (1.00 x 10⁻⁶m)(100)/ 8.988 x 10⁹ NM²/C²

q = 1.112 x10⁻¹² C

So, The charge will the potential be 100 V =  q = 1.112x 10⁻¹² C

distance at which it will be 2.00 x 10^2 is given by

using equation 1

V = kq / r  

r = kq/V

using above values we have

r =8.988 x 10⁹ NM²/C² x 1.112x 10⁻¹² C /2.00 x 10²

r = 4.994 × 10⁻⁵m

distance is 4.994 × 10⁻⁵m

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The motion of the rocket labeled a is an example of motion with uniform (i.e., constant) velocity and non- zero acceleration.

A body when covers an equal distance with an equal interval of time, this condition of the velocity is known as uniform velocity. Or, we can say that when the direction and magnitude of speed of a body do not change with time, then the body is said to be at uniform velocity.

Having a non-zero acceleration means having any amount of acceleration whatsoever. This could be either positive acceleration or negative acceleration (a.k.a. deceleration).

An object experiences a non-zero acceleration when it is speeding up, slowing down, or remaining at the same speed while changing direction. Any of these three scenarios would result in an object's velocity changing since velocity is the change in an object's position over time, and a change in velocity means the object is experiencing acceleration.

Conversely, an object has zero acceleration when it either remains stationary or moving at a constant speed in a straight line. In both of these scenarios, the velocity of the object is constant, so there is no acceleration.

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The angular wave number and (b) the speed of the wave is 522.66 m/s.

Precise wavenumber is an amount in hypothetical material science that is characterized as the quantity of radians per unit distance. Precise recurrence is the rakish dislodging of any component of the wave per unit time. Likewise, in wave wording for a sinusoidal wave, the rakish recurrence alludes to the precise dislodging of any component of the wave per unit time. It is addressed by A recurrence is a rate, thus, the elements of this amount are radians per unit time. Precise hubs are level planes (or cones) where the likelihood of finding an electron is zero. This implies we can't at any point track down an electron in a rakish (or some other) hub. While outspread hubs are situated at fixed radii, precise hubs are situated at fixed points.

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Answer:

See below

Explanation:

It will be 1 PM distance (27km)  + 2 1/2 hrs of 98 km/hr

   =     27   +      2 1/2 * 98 = 272 km west of school

Ernest rutherford was a prominent scientist who contributed significantly to the theory of atomic structure.  Yes, the following statement is true.

Ernest Rutherford is considered one of the greatest scientists and experimentalists who worked on the atomic model and is also known for his contribution to nuclear physics.

he discovered that an atom is composed of three fundamental particles i.e. electrons, protons, and neutrons.

Most of the spaces are empty in an atom while its all mass is confined in a dense positively charged area called the nucleus.

Moreover, he also discovered alpha and beta radiations emitting from uranium.

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The new moon, if it were visible, when eastern horizon starts at 6 am.

The first bilingual (Chinese and English) community radio show to be broadcast to a local audience in the United Kingdom is called Eastern Horizon. In recent years, it was primarily carried live on Saturdays between midnight and one in the morning on BBC Radio Manchester in Manchester.

The center of the horizon on the front of the planisphere points in the direction of North (0º azimuth). The eastern horizon is on the horizon's right side (90º azimuth), and the western horizon is on the horizon's left (270º azimuth).

The new moon, if it were visible, when eastern horizon starts at 6 am.

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