A blue ball is thrown upward with an initial speed of 22.8 m/s, from a height of 0.7 meters above the ground. 2.8 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 9.9 m/s from a height of 29.5 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2.
1) What is the speed of the blue ball when it reaches its maximum height?
0
m/s
2) How long does it take the blue ball to reach its maximum height?
2.35
s
3) What is the maximum height the blue ball reaches?
27.22242
m
4) What is the height of the red ball 3.64 seconds after the blue ball is thrown?
17.7290323
m
5) How long after the blue ball is thrown are the two balls in the air at the same height?
4
s
[Delayed Feedback]
6) Which plot correctly shows the velocity of the two balls as a function of time?Three plots of velocity vs time for the red and blue balls
A
B
C
[Delayed Feedback]
7) Which statement is true about the blue ball after it has reached its maximum height and is falling back down?
The acceleration is positive and it is speeding up
The acceleration is negative and it is speeding up
The acceleration is positive and it is slowing down
The acceleration is negative and it is slowing down

The power of Speaker can be calculated by

[tex]P=V.i\\P=(12).(3)\\P=36W[/tex]

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The magnitude of the acceleration of the car before the collision is  4.23[tex]\frac{m}{ (s ^ 2)}[/tex] and the magnitude of the average acceleration of the car during the collision is -16 [tex]\frac{m}{ (s ^ 2)}[/tex] and the magnitude of the average acceleration of the car during the entire test, from when the car first begins moving until the collision is over is 2.46[tex]\frac{m}{ (s ^ 2)}[/tex].

Velocity of car before collision is [tex]v_{1}[/tex] = 120km / h

Velocity of car after collision is, [tex]v_{2}[/tex] = 76.5km / h .

Time taken by a car before collision is, t =7.88:

Acceleration of car before collision is calculated as;

a = [tex]\frac{v-u}{t}[/tex]

a =[tex]\frac{120\times \frac{5}{18}-0 }{7.88}[/tex]

a = 4.23[tex]\frac{m}{ (s ^ 2)}[/tex]

Therefore magnitude of acceleration of a car before collision a = 4.23  [tex]\frac{m}{ (s ^ 2)}[/tex]

The average vehicle acceleration at the time of impact is computed as;

[tex]a_{avg}[/tex] = [tex]\frac{v-u}{t}[/tex]

[tex]a_{avg}[/tex] =[tex](120-76.5)\times \frac{5}{18}[/tex]

[tex]a_{avg}[/tex] =0.755 s

[tex]a_{avg}[/tex] =-16 [tex]\frac{m}{ (s ^ 2)}[/tex]

Here, a negative sign shows that the average acceleration is moving in the opposite direction from where the car is travelling.

[tex]a_{avg}[/tex] = [tex]\frac{v-u}{t}[/tex]

[tex]a_{avg}[/tex] =[tex]\frac{ (120-76.5)\times \frac{5}{18}}{0.755}[/tex]

[tex]a_{avg}[/tex] =-16[tex]\frac{m}{ (s ^ 2)}[/tex]

Here, the negative sign denotes that the average acceleration is occurring in the opposite direction to the motion of the car.

Therefore, the average acceleration of a car during collision is [tex]a_{avg}[/tex] =16 [tex]\frac{m}{ (s ^ 2)}[/tex]

and in direction opposite to the direction of car.

The average acceleration of the car during the test is calculated.

as,

[tex]a_{2}[/tex]=[tex]\frac{v-u}{t}[/tex] =[tex]76.5\times a_{2}[/tex]= [tex]\frac{76.5\times\frac{5}{18} }{7.88-0.75}[/tex]

[tex]a_{2}[/tex]=2.46[tex]\frac{m}{ (s ^ 2)}[/tex]

Therefore, the average acceleration of a car during entire test is a_{2} = 2.46[tex]\frac{m}{ (s ^ 2)}[/tex]

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As long as the force and time are the same, all vehicles experience the same change in momentum, regardless of their mass.

Given the time interval force applied on cart = 2s

The mass of cart in trail 1 = m

The mass of cart in trail 2 = 3m

The mass of cart in trail 3 = 5m

From Newtons laws of motion: F = ma where F is the force applied and a is the acceleration and v = v0 + at where v0 is the initial velocity.

So, v = v0 + (F/m)t

We know that momentum is defined as mass x velocity such that:

p = mv then the change in momentum is seen as: Δp = mv - mv0

Δp = m(v0 + Ft/m) - mv0

Δp = Ft

Since the force and time are the same for all vehicles, we can see that the change in momentum is independent of the mass of the vehicles.

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complete question: A student conducts an experiment in which a cart is pulled by a variable applied force during a 2sec time interval. In trial 1, the student exerts the force on a cart of mass M. In trial 2, the student exerts the force on a cart of mass 3M. In trial 3, the student exerts the force on a cart of 5M. In which trial will the cart experience the greatest change in momentum from 0 sec to 2 sec?

A satellite of mass 2,000 kg is in an elliptical orbit about the Earth. When the satellite reaches point A, which is the closest point to the Earth, its orbital radius is 1.2x10'm and its orbital velocity is 7.1x 103 m/s. (Me = 6x1024 kg and Re = 6.4x10 m). So, the total mechanical energy of the satellite at point A is -0.6x10^13 J, assuming that the gravitational potential energy is zero at an infinite distance from the Earth.

The total mechanical energy (E) of an object in orbit is given by the equation E = kinetic energy (K) + potential energy (U).

At point A, the kinetic energy (K) is given by the equation K = (1/2)mv^2, where m is the mass of the satellite (2,000 kg) and v is its velocity (7.1x10^3 m/s).

The potential energy (U) is given by the equation U = -GMe/r, where G is the gravitational constant (6.67x10^-11 Nm^2/kg^2), Me is the mass of the Earth (6x10^24 kg), and r is the distance of the satellite from the Earth (1.2x10^6 m).

Substituting the values into the equations and solving, we get:

K = (1/2)(2,000 kg)(7.1x10^3 m/s)^2 = 3.0x10^13 J

U = -(6.67x10^-11 Nm^2/kg^2)(6x10^24 kg)/(1.2x10^6 m) = -3.6x10^13 J

E = K + U = 3.0x10^13 J + (-3.6x10^13 J) = -0.6x10^13 J

So, the total mechanical energy of the satellite at point A is -0.6x10^13 J, assuming that the gravitational potential energy is zero at an infinite distance from the Earth.

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Answer:

Below

Explanation:

If you can't overcome the force of friction....the crate will not move

so friction force = 145 N

Coeff of friction =  Ff / Normal force = 145 / (31.2 * 9.81) = .47

After Thomson's work showed that atoms contain smaller charged particles called electrons, Millikan conducted experiments on charged oil droplets. From these experiments, Millikan precisely determined the mass-to-charge ratio of an electron.

In 1897, J. J. Thomson replаced the mаgnetic field with аn electric field in а cаthode rаy tube with аn improved vаcuum, аnd he showed thаt the cаthode rаys were аttrаcted to the positive plаte аnd repelled by the negаtive plаte. This confirmed thаt the cаthode rаys were composed of negаtively chаrged pаrticles. Thomson cаlled these pаrticles corpuscles, but they hаve come to be cаlled electrons, а nаme suggested by George Johnstone Stoney in 1891.

Thomson wаs аble to cаlculаte the mаss to chаrge rаtio, аnd the results of his experiments аnd cаlculаtions suggested thаt electrons were аbout 1/1000 the mаss of hydrogen аtoms, suggesting thаt аtoms аre composed of pаrticles smаller thаn the аtoms itself. Becаuse the results of his experiments were independent of the gаs in the tube, he concluded thаt аll substаnces contаin these sаme electrons.

In 1909, Robert Millikаn аnd Hаrvey Fletcher observed chаrged oil droplets fаlling between two electricаlly chаrged plаtes. Millikаn аssumed thаt this wаs the chаrge of аn electron, аnd from the mаss to chаrge rаtio determined by Thomson, the mаss of the electron wаs found to be аbout 1/1836 the mаss of а hydrogen аtom, confirming thаt аtoms аre composed of pаrticles much smаller thаn even the smаllest аtom.

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The laplace transform of u(t) for cos3wt, then [tex]y(t) = (1/6) [e^(3it) + e^(-3it)]u(t).[/tex]

Let Y(s) represent y's Laplace transform (t).

Since [tex]y(t) = u(t)cos3wt[/tex], we can write:

[tex]Y(s) = U(s) * [s/(s^2 + 9)][/tex]

Using the magnitude and phase formula discussed in class, we can express y(t) as:

[tex]y(t) = (1/6) [e^(3it) + e^(-3it)]u(t)[/tex]

The Laplace transform is a mathematical transformation used to solve differential equations. It takes a function of time, f(t), and transforms it into a function of a complex variable, F(s), which is known as the Laplace transform of f(t). This transform is useful for analyzing linear, time-invariant systems, and is used in many engineering fields to solve differential equations, such as in electrical, mechanical and control engineering.

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In part b of the drawing, the bucket of water is being pulled up from the well at a constant velocity. In this situation, the tension in the rope must provide the force necessary to balance the weight of the bucket and any friction forces.

The force required to lift the bucket is equal to the weight of the bucket plus the force of friction. If the tension in the rope is less than the force required to lift the bucket, the bucket will not move. If the tension in the rope is greater than the force required to lift the bucket, the bucket will accelerate upward.

Since the bucket is being lifted at a constant velocity, this means that the tension in the rope must equal the force required to lift the bucket. Therefore, the tension in the rope in part b of the drawing is equal to the weight of the bucket plus the force of friction. If this value is not given, it cannot be determined without additional information.

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The combination of analysis models that correctly describes one of the spheres in this situation and will be most useful for solving the problem depends on the specific details and requirements of the problem at hand.

Some commonly used models for analyzing charged spheres include the electric field generated by a point charge, Coulomb's law, and the method of images. The choice of the most appropriate model will depend on the specific conditions and requirements of the problem, such as the distribution of charge on the spheres and the distance between them. Charge is a fundamental property of matter that refers to the amount of electrical energy in a system. It is measured in units of Coulombs and can be positive, negative or neutral. Charge can interact with other charges through the electric force, which is described by Coulomb's Law. This interaction can result in a number of phenomena, including attraction, repulsion, and the transfer of electrical energy from one object to another. Understanding charge and its interactions is crucial for many fields, including physics, engineering, and chemistry, and has many practical applications, such as in electronics, power generation and storage, and in medical imaging technologies

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The general antiderivative of the rate of change function "the rate of change of DVD orders is given by s(m) = 600m + 5DVDs per month" is "DVD orders = 300m^2 + 5m + c", where c is the constant of integration.

The antiderivative of a function is the original function whose derivative is equal to the given rate of change function. To find the antiderivative of the rate of change function "the rate of change of DVD orders is given by s(m) = 600m + 5 DVDs per month", we need to integrate the function with respect to the independent variable m.

The antiderivative of the function s(m) = 600m is 300m^2 and the antiderivative of the constant 5 is 5m. Adding these two antiderivatives, we get the general antiderivative of the rate of change function:

DVD orders = 300m^2 + 5m + c

where c is the constant of integration and represents the arbitrary offset from the original function. To find the value of c, additional information or boundary conditions are required. This antiderivative represents the total number of DVD orders as a function of the number of months since the beginning of the year.

Complete question:

Write the general antiderivative of the given rate of change function.

DVD Orders The rate of change of DVD orders is given by

s(m) = 600m + 5DVDs per month

where m is the number of months since the beginning of the year.

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In this case it will be equal to the flux of electric field through the Gaussian surface B as Flux through S(A) = Flux through S (B ) =  Charge inside/ ∈₀

Gauss's law states that the net total electric charge inside a Gaussian surface equals the total electric flux. The electric flux will remain constant even if the Gaussian surface is three times bigger if both surfaces have an equal amount of total electric charge.

Now that we have an arbitrary charge distribution, we can determine the electric flux through any closed surface. We discovered that any electric field lines entering the surface at one point must necessarily exit at another point of the surface if a closed surface lacks any charge inside where an electric field line can terminate. Therefore, the electric flux will not exist if a closed surface has no charges inside the enclosed volume.

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When a 95-kg halfback moving at 4.1 m/s is tackled from behind by an 85-kg cornerback running at 5.5 m/s in the same direction, their mutual speed immediately after the tackle is 1.96 m/s.

The mutual velocity of two colliding bodies is the velocity of the center of mass of the system after the collision. In an inelastic collision, the total momentum of the system is conserved, but the kinetic energy is decreased. The final velocity of the system can be calculated by dividing the total momentum by the total mass of the system.

In this case, the mutual velocity after the tackle is equal to the velocity of the center of mass of the system formed by the halfback and the cornerback. By using the equation for the center of mass velocity, the mutual velocity after the tackle can be calculated as follows:

v_cm = (m1 × v1 + m2 × v2) / (m1 + m2)

where v_cm is velocity of the center of mass (mutual velocity or mutual speed),  m1 is the mass of the halfback, v1 is the initial velocity of the halfback, m2 is the mass of the cornerback, and v2 is the initial velocity of the cornerback.

v_cm = (95 kg × 4.1 m/s + 85 kg × 5.5 m/s) / (95 kg + 85 kg)

v_cm = 1.96 m/s

So the mutual speed immediately after the tackle was 1.96 m/s.

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Your question seems missing, but I suppose the question was:

"A 95-kg halfback moving at 4.1 m/s on an apparent breakaway for a touchdown is tackled from behind. When he was tackled by an 85-kg cornerback running at 5.5 m/s in the same direction, what was their mutual speed immediately after the tackle?"

The average velocity for the time period beginning when t = 2s and lasting 0.5s is 39.625ft/s, 0.1s is 15.6ft/s, 0.05s is 14.8ft/s, 0.01s is 16ft/s

Given the initial velocity of the ball (u) = 50ft/s

The motion is given as: [tex]y = 50t - 16t^2[/tex] where y is the height of the ball.

We can see that it is similar to [tex]y = ut + 1/2at^2[/tex] such that 1/2a = 16 then a = 32m/s2

The initial time when the ball is thrown in air (t1) = 2s

The total distance a particle has travelled divided by the total amount of time it has taken to travel that distance is the definition of an object's average velocity. So, let the height h1 be covered in t1s and h2 be covered in t2s such that average velocity (v) = h2-h1/t2-t2

(a) Initially, t1 = 2s and t2 = 2+0.5s = 2.5s where [tex]y = 50t - 16t^2[/tex]

Then h1 = 50 x 2 - 16 x 2x2 = 36ft

h2 = 50 x 2.5 - 16 x (2.5)x2.5 = 115.25

V = 115.25 - 36/2.5-2 = 79.25/2 = 39.625ft/s

(b) Let t2 = 0.1 + 2 = 2.1s then,

h2 = 50 x 2.1 - 16 x (2.1)x2.1 = 34.44ft

V = 34.44 - 36/0.1 = -1.56/0.1 = -15.6ft/s

(c) Let t2 = 0.05 + 2 = 2.05s then,

h2 =  50 x 2.05 - 16 x (2.05)x2.05 = 35.26ft

V = 35.26 - 36/ 0.05 = -0.74/0.05 = -14.8ft/s

(d) Let t2 = 0.01 + 2 = 2.01s then,

h2 =  50 x 2.01 - 16 x (2.01)x2.01 = 35.84ft

V = 35.84 - 36/ 0.01 = -0.16 /0.01 = -16ft/s

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The resultant resistance of the resistor combination   is 10 Ω.

A resistor is an electrical component that controls or restricts how much electrical current can pass across a circuit in an electronic device. A specified voltage can be supplied via resistors to an active device like a transistor.

Resistance of each resistor is = 20 Ω

The resistors are connected parallelly.

Hence, the resultant resistance of the resistor combination  = (20 ||20)  Ω

= (20 × 20) ÷ (20 + 20)  Ω

= 10  Ω.

Therefore, the resultant resistance of the resistor combination   is 10 Ω.

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After a collision, the center of mass velocity of this system of two balls with masses m1 and m2 and velocities v1 and v2 is ( m1 v1 + m2 v2 ) / ( m1 + m2 ).

Momentum is the force needed to stop an item moving at a certain speed in a given amount of time. It is calculated by multiplying an object's mass by its velocity. The sum of the individual momenta determines the overall momentum for any array of many objects.

p = m.v

p = Momentum

m = Mass

v = Velocity

For ball 1,

m = m1

v = v1

p1 = m1 v1

For ball 2,

m = m2

v = v2

p2 = m2 v2

Center of mass velocity = Total momentum / Total mass

Total momentum is = p1 + p2

Total mass is= m1 + m2

Center of mass velocity is= ( p1 + p2 ) / ( m1 + m2 )

Center of mass velocity is= ( m1 v1 + m2 v2 ) / ( m1 + m2 )

Therefore, center of mass velocity  of this system of two balls is

Center of mass velocity = ( m1 v1 + m2 v2 ) / ( m1 + m2 ).

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The correct option is D, the force of Earth's gravity on a spacecraft 2.00 Earth radii above the Earth's surface is 2610 N.

The force of Earth's gravity on a spacecraft can be calculated using the equation F = G * (m1 * m2) / r^2, Earth's surface is approximately 2 * 6,371,000 m = 12,742,000 m). Plugging in the values, we get:

F = 6.67 x 10^-11 Nm^2/kg^2 * (5.97 x 10^24 kg * 1700 kg) / (12,742,000 m)^2

F = 2610 N

Force is a term used in physics to describe the influence that causes an object to undergo a change in motion. It is a vector quantity, meaning it has both magnitude and direction. Force can cause an object to move, change its speed, or change its direction. It can also cause a stationary object to start moving. There are several types of forces, including gravitational forces, electrical forces, magnetic forces, and friction forces. Force can also be described as a push or a pull.

Force is an essential concept in physics as it helps us understand the behavior of objects and how they interact with each other. For example, the force of gravity keeps planets in orbit around the sun. The force of friction is what allows us to walk on the ground without slipping. The force of air resistance affects the motion of projectiles and affects the speed of vehicles.

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Answer: Convection causes the warmer air over land to expand and rise, which in turn causes low air pressure over the land. The cooler air over the ocean rushes in to replace the warm air that just rose over land. This causes a sea breeze.

Explanation:

hope this helped ;) ! -middle schooler

Answer:

convection

Explanation:

heat rises up

The x-component of the electric field at point P due to charge Q1 is 270 N/C.

The query asks what charge Q1 is responsible for the x component of the electric field vector at point P. In light of this, you disregard charge Q2's contribution.

Assume that point P contains a little positive charge. By definition, the strength of the electric field caused by charge Q1 at point P is:

E = [tex]\frac{kQ1}{d^{2} }[/tex] where k is the coulomb constant and d is the straight-line distance from Q1 to P.

The distance, d, is the hypotenuse of the triangle formed by the point P, charges Q1 and Q2. Therefore,

d = [tex]\sqrt{0.065^{2} } + \sqrt{0.075} ^{2}[/tex] = 0.099 m

Now, finding the electric field, we get:

E = 8.99 × [tex]10^{-9} Nm^{2} C^{-2}[/tex] × 0.45 × [tex]10^{-9}[/tex] / [tex]0.099^{2}[/tex] = 412 n/c

The x component of the electric field, [tex]E_{x}[/tex], would be:

412 × cos49° = 270 N/C.

The Electric field points away from positive charges (q > 0) and towards negative charges. In Maxwell's equations, the E-field is always a vector field with three dimensions. This indicates that it consists of three parts: an x, y, and z component that respectively determine the x, y, and z directions of the electric field.

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This potential energy is known as gravitational potential energy. It is the gravitational field's potential energy that is released when two objects fall in close proximity to one another.

The term "potential energy" refers to the energy that is conserved or stored in a material or object. The location, configuration, or status of the substance or object determines the stored energy.

Energy that has been stored is called potential energy. A battery, a stretched spring, and lifting an object are some examples. There are two major categories of energy: potential and kinetic.

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The radius the star Rigel, a bright blue star in the constellation Orion that radiates energy at a rate of 2.7 × 10³¹ W and has a surface temperature of 11,000 K. (Assume that the star is spherical) = 5,422.17 km

To determine the radius of the star, we can apply the Stefan-Boltzmann law to determine the star output power.

Rigel emits radiation at a rate of 2.7 x 10²³ Watts

The power per unit area, according to the Stefan-equation, Boltzmann's is:

j = σT⁴

Where,

σ = (2[tex]\pi[/tex]⁵K⁴) / 15c²h³

T = temperature

σ = 5.670 x 10⁻⁸ Wm⁻²K⁻⁴

Hence,

The surface area of the star:

A = P / j

P = power ⇒ 2.7 × 10³¹

A = ( 2.7 × 10³¹) / (5.670 x 10⁻⁸) (11.000⁴)

= 3.52 x 10²³

The area = 4[tex]\pi[/tex]r²

3.52 x 10²³ = 4[tex]\pi[/tex]r²

r² = 2.58 x 10²²

r = 5,422.17 km

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When the sound source is moving towards the stationary listener at one-half the speed of sound, the frequency heard by the listener will be 1.40 kHz.

When the source is stationary and the listener moves towards the source at one-half the speed of sound, the frequency heard by the listener will be 1.80 kHz. This is because the Doppler effect causes the frequency of a sound wave to increase as the source moves towards the listener and decrease as the source moves away from the listener.

Frequency is a measure of how often a wave or signal repeats itself over a given period of time. Frequency is usually measured in hertz (Hz), which means the number of cycles per second. Frequency is an important concept in physics, as it is used to describe waveforms such as sound, light, and radio signals.

Frequency is also used to describe the properties of an object or system, such as its resonant frequency.

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The geocentric model is a solar system model that places the Earth at the center and explains the motion of the planets through circular paths. The heliocentric model, on the other hand, places the Sun at the center and explains the motion of the planets through orbit around the Sun. The changing brightness of the planets is explained by their varying distances from either the Earth (geocentric model) or the Sun (heliocentric model).

True, two competing models were created to explain the motions and changing brightness of the planets. These were Ptolemy's geocentric model and Copernicus' heliocentric model. The geocentric model, as its name suggests, places the Earth at the center of the solar system and the planets, including the Sun, orbit around it. The heliocentric model, on the other hand, places the Sun at the center of the solar system and the planets, including Earth, orbit around it.

In the geocentric model, the planets move in circular paths called epicycles, which are superimposed on larger circular paths called deferents. The changing brightness of the planets is explained by their varying distances from the Earth.

The heliocentric model explains the motion of the planets as the result of their orbit around the Sun. The changing brightness of the planets is also explained by their varying distances from the Sun.

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Therefore, no acceleration will occur until the frictional force exceeds the Driving Force (F), which in this case is gravity. The equation would then indicate a negative acceleration, which would not actually occur. Friction is a reactive force rather than an active one.

When you resolve, set your axes to be perpendicular and parallel to the surface rather than necessary vertical and horizontal axes.

As the item on the surface neither sinks into it nor accelerates away from it, the forces perpendicular to the surface will add up to zero.

The total of the forces acting parallel to the surface may be used to calculate the acceleration using the formula F=ma.

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The wavelength of the yellow light produced by a sodium lamp post is 589 m. What frequency does this light have. (Response: 5.093 x 10'/Sec)

What wavelength of electromagnetic radiation does sodium emit at 589.0 nm?

It is assumed that the radiation's wavelength is 589 nm. Therefore, option C is appropriate because the frequency of irradiation is 5.09 1014 s1.

When sodium's surface is exposed to electromagnetic radiation with a wavelength of 300 nm?

Electrons with a kinetic energy of 1.68 105 Jmol1 are released from the surface of sodium when electromagnetic radiation with a wavelength of 300 nm falls on it.

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The new volume of the cylinder will increase by a factor of 7.453.

The volume of a cylinder is calculated by applying the following equation as shown below.

V  = πr²h

where;

when the radius increases by a factor of 2.73, the new volume will become;

V = π(2.73r)²h

V = 7.453 πr²h

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As just a unit for one unit, both scales are connected. A change of one unit on the Kelvin scale corresponds to a change of one degree on the Celsius scale. The following equation relates the Kelvin scale to the Celsius scale: K Equals 0C - 273.15.

Water's freezing point is 0 degrees Celsius, or centigrade, and its boiling point is 100 degrees Celsius. Swedish Swedish scientist Anders Celsius created the Celsius scale in 1742; due to the 100-degree gap between the designated points, it is sometimes referred to as the centigrade scale.

As the acknowledged father of Swedish astronomy, Anders Celsius is most known for developing the Celsius temperature scale, often known as the centigrade scale, on which the boiling point of water is expressed as 100°C and the freezing point as 0°C.

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F=GmMr2=kM, where G is your weight and m is the primordial mass of the earth. Where k=Gmr2 k = G m r 2, F = G m M r 2 Equals k M.

Did you realize that the weight of the planet Earth is decreasing daily? In spite of the 40,000 tons of space dust that reach the surface of our planet every year, it is really becoming 50,000 tonnes lighter.

The University of Guelph's Joanna O'Meara, a lecturer and associate head in the faculty of physics, argues why meteor showers actually cause the Earth to grow heavier. According to her, space dust, which includes meteor and asteroid debris, adds around 40,000 tonnes of weight to the earth each year.

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The first question has an answer: twice the voltage across a constant resistance circuit quadruples the power lost by that circuit (Option B). Sorry, but I require additional network information to solve for the ultimate potential difference across capacitor X in the second question.

Voltage is a quantitative measure of the potential difference in charge between two places in an electrical field. It is also known as electromotive force. Voltage is the force exerted by the power source of an electrical circuit to move charged electrons (current) through a conducting loop, allowing them to do work such as lighting a lamp. Voltage refers to the "pressure" exerted by electricity. Voltage is measured in units known as volts (V), and greater voltages cause more electricity to flow to an electrical equipment.

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The answer to the first question is that doubling the voltage across a constant resistance circuit doubles the power wasted by that circuit fourfold (Option B). Sorry, but I need more information about the network to solve for the ultimate potential difference across capacitor X in the second question.

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research questions about the time course of cognition are better addressed using methods like ERPs, whereas questions about the anatomy of cognition are better addressed using methods like fMRI.

The primary goal of an ERP system is to improve organisational efficiency by managing and improving how corporate resources are used.These systems are of three types, on-premises, cloud-based, and hybrid. It depends on the organization adopting ERP software to choose a suitable type for its business needs and operations to improve its productivity.

The fMRI magnet converts tissues into a visualizable state, and radio frequency pulses offer the signalling information required to distinguish them. The computer assembles the information from the radio frequency pulses into a manner that anyone who can read a weather map will recognise.

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