A 50-cm-long spring is suspended from the ceiling. A 210 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 16 cm before coming to rest at its lowest point. It then continues to oscillate vertically.

The average speed you must run is 7.97 mph.

The average speed of an object is the ratio of total distance traveled by the object to

Average speed = total distance / total time of motion

Total time of motion = total distance / average speed

total time = (18.5 + 5.5) / (14.5)

total time = 1.66 hours

t1 = 18.5 / 19.1

t1 = 0.97 hour

t2 = 1.66 hr - 0.97 hr

t2 = 0.69 hr

v = 5.5 miles /0.69 hr

v = 7.97 mph

Thus, the average speed you must run is 7.97 mph.

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(a)In the next 15.0s, she traveled 101.250 m.

(b) 4.50 m/s is the runner's final speed.

Given:- initial velocity = 9m/s , deacceleration = 0.3 m/s2

distana(d), she moves in time (t)=15 s,

and we must determine this using the second equation of motion.

S = ut + 1/2 at2,

where s = the distance

u = initial velocity

t = time

a=-d = 0.300m/s

t=15.0

By putting all values in the formula above,

we have

d = (9.00)x(15.0)-1/2 (0.300) (15.0)²

d= 101.250 m.

In the next 15.0s, she traveled 101.250 m.

final speed  (v) =?

from 1 Equation of Motion : v = u+at.

To solve, v=?

u=9.00 m/s

a= -d= 0.300 m/s²

t=15.0

v=u+at

v= 9 - 0.300 X15.0

= 4.50 m/s

4.50 m/s is the runner's final speed.

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Explanation:

f=ma

a=f/m

a=80/20 = 4m/s

The velocity of the car moving in the circular path is determined as 1.67 m/s.

Linear velocity is the measure of the rate of change of displacement with respect to time when the object moves along a straight path.

v = d/t

where;

v = (6 x 1000 m) / (1 x 3600 s)

v = 1.67 m/s

Thus, the velocity of the car moving in the circular path is determined as 1.67 m/s.

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The correct answer is option ( A) the ratio of their average speeds (bird 1/bird 2) is 1.0

velocity = distance / Time

Let us assume distance covered by Bird 1 = d

case 1 (Bird 1) :-

time = 6 hours

velocity(Bird1) = d/6 = 0.167*d

case 2 (Bird 2) :-

time = 12 hours

distance is twice of Bird 1 = 2d

velocity(Bird2) = 2d/12 = 0.167*d

now, velocity of Bird1/Bird2 =  (0.167*d)/(0.167*d) = 1.0

So,velocity of (Bird1/Bird2) is  1.0 .

Average velocity / Average speed = Total displacement / Total distance. Remember that the numerator is less than or equal to the denominator. As a result, the ratio is always equal to or less than one. Distance traveled divided by time taken is the most commonly used formula for calculating average speed. The other formula is to add the initial and final speeds together and divide by two.

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The acceleration of the object be if the force is doubled and the mass is doubled is equal to 9m/s².

let the initial mass of the object be m₁.

given:

initial acceleration (a₁) = 9m/s²

initial constant force (F₁) = constant (k)

therefore,

F₁=  m₁×a₁    -------------------------------  equation 1

now,

according to the the question the force is doubled

i.e.

new force (F)  = 2×F₁

and the mass too is doubled,

i.e.

new mass of the object(m)=2×m₁

new equation for force and acceleration:

F= m ×a      

2F=2m₁×a --------------------------equation 2

dividing equation 2 by equation 1

we get,

[tex]\frac{2F}{F}=\frac{2m₁×a}{m₁×a₁ }[/tex]

a = a₁

a=9m/s²

the acceleration of the object be if the force is doubled and the mass is doubled is equal to 9m/s².

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The distance traveled by by the dolphin is determined as 11.1 m.

The distance traveled by an object is the product of speed and time of motion of the object. It measures the total path covered by the object.

The distance traveled by by the dolphin is calculated as follows;

Distance = speed x time of motion

Distance = 1.85 m/s x 6 s

Distance = 11.1 m

Thus, the distance traveled by by the dolphin is determined as 11.1 m.

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The correct answer is :

P = ρgh yields the hydrostatic pressure, which is accurate.

The pressure a liquid applies to nearby bodies when it is at rest is known as hydrostatic pressure.

Water at rest exerts a force known as hydrostatic pressure. It is caused by the water's continual pressure on the basement walls.

The force that blood applies to blood channel walls is a typical illustration of hydrostatic pressure.

Depending on the liquid's density ('ρ'), the height of the water column ('h'), and the acceleration caused by gravity ('g'), the hydrostatic pressure is indicated by the letter "P" of a liquid column.

Because of this, the parameters and the supplied equation P = gh are both accurate.

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Answer:

See below

Explanation:

Hypotenuse is snake length 10 m

   y coordinate = 10 sin 60 = 8.7 m

   x coordinate = 10 cos 60 =  5m

The substances that are altered and the chemicals on the right side of a chemical equation are the results of a chemical reaction. B and D are the appropriate choices.

Reactants are the substance(s) in a chemical equation to the left of the arrow. A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product. The creation of products from the reaction of two reactants is known as a chemical reaction. The compounds that result from a reaction are called products. The substances that are original materials are the reactants.

On the left side of the reaction are the reactants, and on the right are the products. B and D are the proper choices as a result.

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In a longitudinal wave, the particles of the medium have to and fro motion about their mean motion, along the direction of wave motion.

Longitudinal waves are waves in which the displacement of the medium is in the same (or the opposite) direction as the wave propagation and the medium vibration is parallel ("along") to the direction the wave travels. Because they create compression and rarefaction when passing through a material, mechanical longitudinal waves are also known as compressional or compression waves. A nice illustration is a wave down the length of a stretched Slinky toy, where the space between the coils grows and shrinks. Examples from the real world include seismic P-waves and sound waves (which are oscillations in pressure, a particle's displacement, and a particle's velocity) (created by earthquakes and explosions).

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The calculated velocity is 3.88 m/s

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value. The parameters of speed are time divided by distance. The most often used unit of speed in daily life is the kilometer per hour (km/h), or miles per hour in the US and the UK. The SI's unit of speed is the meter per second (m/s) (mph).

h = 0.5g*t² = 0.77 4.9t²

= 0.77\st²

= 0.1571

t = 0.396 seconds or fall.

Dx = Xo*t, or 5.15 meters.

Xo * 0.396 = 5.15

Break speed is X= 13 m/s.

V² = V² + 2g*h.

V² = 0 + 19.6*0.77

= 15.09

V = 3.88 m/s

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It is false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.

Work is a measure of energy expended in moving an object. It is most commonly calculated by multiplying the force by distance.

It is said that no work is done if the object does not move.

According to this question, if one pound of force acts through a distance of two feet, a work of one pound-two feet is done.

It is therefore, false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.

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Answer:

see below

Explanation:

a^3 = 125 m^3

b^2 = 8.41 s^2

c = 45 m/s           Plug these values into the equation

125 / ( 8.41 * 45)  = .33  m^2 / s

Answer:

See below

Explanation:

31 00 sh / min    /   60 s / min = 51 2/3 shakes per second

According to the given data initial volume =0.667 L

Boyle observed that the product of the pressure and volume are observed to be nearly constant. For a perfect gas, the result of volume and pressure is a precise constant. Boyle's Law is the name given to the relationship among pressure and volume in his honor.

Boyle was a modern chemical pioneer in the 17th century, best known for his law of gases. Robert Boyle (1627–1691) is credited with discovering the renowned Boyle's law, which states that a gas's volume decreases with rising pressure and vice versa

Since the change occurs at constant temperature (i.e. an isothermal change), Boyle's law applies,

i.e. p[tex]_1[/tex]V[tex]_1[/tex] = p[tex]_2[/tex]V[tex]_2[/tex]        where p[tex]_1[/tex] = 125 kPa,  p[tex]_2[/tex] = 200 kPa  and  V[tex]_2[/tex]=0 .5L

Hence,                 (150)V[tex]_1[/tex] = (200)(0.5)

from which,          volume V[tex]_1[/tex] = 200×0.5/150=0.6667L

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The electromagnetic force, the weak nuclear force, the strong nuclear force, and gravity.

The strong force, weak force, electromagnetic force, and gravitational force are the four fundamental forces operating in the universe. They each operate within different parameters and have unique strengths. Although gravity has an infinite range, it is the weakest force. Although it has an infinite range, the electromagnetic force is much stronger than gravity. The weak and strong forces are dominant only at the level of subatomic particles and are only effective over very small distances. Even though it has a weaker name than gravity, the weak force is actually the weakest of the three. The strongest of the four fundamental interactions is the strong force, as its name suggests.

Actually, out of the four fundamental forces, gravity is the weakest. The four forces are the electromagnetic force, gravity, the weak nuclear force, and the strong nuclear force, in that order.

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Answer:

Displacement

Explanation:

I think Sam's mom isn't worried with how far away he goes, but will be upset if he isn't home fast enough for dinner.

The average speed of round trip is 1192.8 m/s

Average speed of the round trip is

2*994*1491/(994+1491)

= 1192.8 m/s

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The change in the tension if the radii r changes from 4.0 cm to 4.1 cm, and R changed from 0.8 cm to 0.9 cm is negative, therefore, tension reduces.

Mass of the yoyo = 0.001 kg

Initial value of the spindle radius, R = 4 cm

Initial length of the radius of the yo–yo, r = 0.8 cm

The final values are;

R2 = 4.1 cm, r2 = 0.9 cm

Which gives;

[tex]T_{r \:R} = \frac{0.001 \cdot g \cdot R }{2 \cdot r^{2} + R^2} [/tex]

Which gives;

[tex]T_{{r _1 \:R _1 }} = \frac{0.001 \times 9.8 \times 0.04 }{2 \times 0.008^{2} + 0.04²} = \frac{49}{216} [/tex]

[tex]T_{{r _2 \:R _2 }} = \frac{0.001 \times 9.8 \times 0.041 }{2 \times 0.009^{2} + 0.041^2} = frac{2009}{9215} [/tex]

Therefore;

[tex] \Delta T_{{r \:R }} = frac{2009}{9215} - \frac{49}{216} = - \frac{17591}{1990440} [/tex]

Given that difference between the final and the initial states is negative, the the value of the tension decreases

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Answer:

Yes

Explanation:

acceleration is a change in velocity, so an object might be momentarily at rest but a split-second later have some speed, i.e. it can be changing its velocity even if it is momentarily at rest.

The velocity is 5.2 m/s

Force as per the Newton's second law of motion is defined as, for constant mass, mass times the acceleration

F= m x a

where m is the mass of the body in kilograms and a is the acceleration is m/s^2

Now we know that acceleration is nothing but rate of change of velocity

i.e. a= (v -u)/t

where v is the final velocity

u is the initial velocity

and t is the time frame in which change takes place

Now the data given to us is as follows:

Force F= 15 Newton

initial velocity u =1.2 m/s

t= 2 seconds

We are required to find the final velocity v

Now putting the values in the equation,

F= m (v-u)/t

15 = 7.5 (v-1.2)/2

30= 7.5v -9

7.5v=39

v=39/7.5= 5.2 m/s

Hence the velocity is 5.2m/s

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Answer:

1/2 m v^2 - G M m / R      escape velocity equal to energy at surface

v^2 = 2 G M / R = 2 * 6.67E-11 * 7.4E22 / 1.7E6

v^2 = 2 * 6.67 * 7.4 / 1.7 * 105 = 5.81E6

v = 2410 m/s = 2400 m/s

The student that gave the most precise measurement is student 2.

A precise measurement is one that is close together especially when we have a replicate measurement. The measurements that are close together are said to be presence. A measurement is accurate when the measurement is quite close to the true value. Precision ad accuracy are very important in a measurement.

In this case, let us consider the measurement of each student;

We can see that the student that gave the most precise measurement is student 2.

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Answer:30 km/hr2 is the exal

Explanation:

Answer:

It is water vapor.

Explanation:

When water boils, it is changing state from a liquid to a gas.

Answer: It is water vapor. When water boils, it is changing state from a liquid to a gas.

Explanation:

Object 1 and Object 2 will have a constant acceleration.

We know the expression for Displacement, Acceleration, and Time can be represented by the equation: S = ut + 1/2at². We will compare cases for each object at a given position and time and check if the object maintains a constant acceleration.  

=>  S = ut +1/2at², where S = Displacement/position of object, u = Initial velocity, t = time, a = acceleration.

For Object 1,

Case 1 : 0.44 = 0*0.3 + 1/2*a*(0.3)²

              a = 9.78

Case 2 : 3.14 = 0*0.08 + 1/2*a*(0.8)²

              a = 9.81

Acceleration is approximately constant for object 1.

For Object 2:

Case 1 : 0.06 = (0) (0.3) + ½ a (0.3)²

              a = 1.33

Case 2: 3.09 = (0) (2.1) + ½ a (2.1)²

              a = 1.40

Acceleration is approximately constant for object 2.

For Object 3:

Case 1 : 0.44 = (0) (0.3) + ½ a (0.3)²

             a = 9.78

Case 2: 3.09 = (0) (2.1) + ½ a (2.1)²

             a = 1.40

Acceleration has a lot of differences in both cases of Object 3 so it's not constant.

Hence, Object 1 and Object 2 have constant acceleration.

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A rope competition is played out between four participants. They both pull on the rope to the right while producing forces between 330 N and 380 N. The other two pull to the left with forces of 320 N and 410 N, respectively.

T2 = 250 and T1 = 250.57 [N] .57[N]

In order to create a free body diagram with all the forces acting on the body, we must first extract all the information they provide about the issue.

The free body diagram and associated forces are shown in the accompanying figure.

The T1 and T2 forces can be found by adding up the forces on the Y-axis; these forces are equal because they are a precondition for the problem. Therefore, this equation can be solved.

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