A 120.0 l weather balloon filled with 4.90 mol of helium has a small leak. if the helium leaks at a rate of 10.0 mmol/hr, what is the volume of the balloon after 67.0 hours?

Planck find the correct curve for the specturm of light emitted by a hot object by vibrational energies of the atomic resonators were quantized.

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To increase the electric force between two charged particles by a factor of 16, we D. Increase one particle's charge by a factor of 16.

Electric force is the force of attraction between two charged particles.

The magnitude of the electric force is given by F = kq₁q₂/r² where

Given that we have two charged particles q₁ and q₂ separated by a distance r, the electric force betwen them is given by F = kq₁q₂/r²

Now, if we want to increase the force by a factor 16, we have the new force F' = 16F

F' = 16kq₁q₂/r²

F' = k16q₁q₂/r²

F = k(16q₁)q₂/r² or kq₁(16q₂)/r²

This implies that either one of the charged particles q₁ or q₂ is increased by a factor of 16

So, to increase the electric force between two charged particles by a factor of 16, we D. Increase one particle's charge by a factor of 16.

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Answer:

I = Q / t = N e / t

I = 21,847E18 * 1.60E-19 Coul / 12 sec = 2.18E22 * 1.60E-19 / 12 sec

I = 2.18 * 1.60 * 10^3 / 12 amps = 291 amps

Rinse chemicals from your hands and arms with water in the sink

In the chemistry lab we use to work with chemical solutions, because of that we must learn what is the best way to manipulate the chemicals with we are going to work, so an proper way to maintain our hands and arms clean is using the lab's sink in order to wash our hands and arms with enough water

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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According to Stefan’s law, a hotter body radiates 68 times more energy per unit area per second

As per Stefan’s law, Fhotter/Fcooler = 68

The Stefan law or the Stefan-Boltzmann law, states that the total radiant heat power that is emitted from a surface per unit area at the absolute temperature is directly proportional to the fourth power of its temperature.

The unit used in Stefan’s law is σ which equals to Wattm−2k−4

This law was formulated by Josef Stefan in 1879 through his experimental studies and again by Ludwig Boltzmann in 1844 from thermodynamic considerations.

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Answer:

The distance the electron travelled before coming to a stop is 195.19 x 10-13m

Explanation:

Flux in an electric field is given by;

Fe = qE

E= 12000 n/c.

q= 1.602x10-19 (charge of an electron)

Fe = 1.602x10-19c x 12000 n/c.

Fe= 1.92x10-17 N

Since F=ma

M = mass of an electron = 9.11x 10-31

a=?

1.92x10-17 N = 9.11x 10-31 x a

a = 1.92x10-17 N/9.11x 10-31

a = 2.11 x 1013

Given

V2= u2 +2as

Since v= 0 (final velocity is zero)

- u2 = 2as

(28.7)2 = -2 x (2.11 x 1013) x s

823.69 = -4.22 x 1013xs

S = 823.69/ -4.22 x 1013

S = 195.19 x 10-13m

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The colors that fall directly between a secondary and a primary on Newton's color wheel are referred to as intermediate colors

Isaac Newton revisited this same white sunlight's rainbow-colored dispersion when he was 23 years old. He noticed that the white sunshine was divided into red, orange, yellow, green, cyan, and blue light when he held a prism of glass in the direction of a beam of sunlight streaming through a hole in the blind of his darkened chamber. He found that the red, green, and blue areas of his rainbow's three distinct colors could be merged to create white light using prisms and mirrors. These are the fundamental hues, as he put it. Secondary hues were created when any two of these were blended. He noticed cyan-colored light when he blended blue and green light.

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Answer:

1.8 seconds

Explanation:

Ignoring air friction

d = 1/2 at^2

15    = 1/2 (9.81) t^2    shows  t = 1.75 = 1.8 seconds

To find the electron and hole concentrations and fermi levels in silicon at 300 k for boron, fermi level is 9.3 x [tex]10^4 cm^-3[/tex].

Ionization energy for boron in Si, 0.045 eV

Fermi level in silicon,

300 K at [tex]10^{15} cm^{-3}[/tex] (Boron atoms)

All boron impurities are ionized, 300K

Electron, hole concentrations and Fermi levels is found out,

The value of Na = [tex]10^{15} cm^{-3}[/tex]

np = [tex]\frac{ni^2}{nA}[/tex]

np = [tex]\frac{(9.65 x 10^9)^2}{10^15}[/tex]

np= 9.3 x [tex]10^4 cm^-3[/tex]

Fermi level is calculated,

Ef - Ev = kT ln(NV/ND)

value of kT = 0.0259 eV (300° K)

So, substitution the values

Ef - Ev = kT ln(NV/ND)

Ef - Ev = 0.0259ln (2.66 x [tex]10^{19} / 10^{15}[/tex] )

Ef - Ev = 0.0259ln (26600)

Ef - Ev = 0.0259 x 10.18

Ef - Ev = 0.263 eV

What is ionization energy?

Ionization energy, also known as ionization energy (IE) or ionization energy (British English spelling), is the minimal amount of energy needed to free the most loosely bonded electron from an isolated gaseous atom, positive ion, or molecule in physics and chemistry.

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The device that is installed in a process or at a bench to continually measure and display quantities is a permanent test instrument.

A tool for measuring a physical quantity is a measuring instrument. Measurement, in the physical sciences, quality control, and engineering, is the process of gathering and contrasting the physical amounts of things that actually happen in the real world. As units, pre-defined standard things and occurrences are used, and the measuring procedure yields a number that connects the subject-matter under investigation to the used unit of measurement. These numerical relationships are attained through the employment of measuring devices and formal test methodologies that specify the device's use. The instrument error and measurement uncertainty that affect all measuring devices varies in severity. From basic tools like stopwatches and rulers to electron microscopes and particle accelerators, these instruments can be used for various purposes.

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The resultant internal loading acting on the cross section of C are Normal force of 0 N, Shear force of 233.33 N and Bending moment of 433.325 N.

We know that Moment = Force * Distance.

Given that,

Force along span C = 600 N / m

First chart a free body diagram as shown in Fig 1.

The distributed load along span c is replaced by a point load F at its midpoint.

Force at midpoint of span C = 600 * 2 N

Take moments about point A

Σ [tex]M_{A}[/tex] = 0

-600 * ( 2 ) * [ 1 + ( ( 1 + 1 ) / 2 ) ] + [tex]B_{y}[/tex] ( 4.5 ) - 900 ( 6 ) = 0

- 2400 + 4.5 [tex]B_{y}[/tex] - 5400 = 0

[tex]B_{y}[/tex] = 1733.33 N

Consider a section at Point C and draw a free body diagram as shown in Fig 2.

In fig 2,

[tex]V_{C}[/tex] = Shear force at point C

[tex]N_{C}[/tex] = Normal force at point C

[tex]M_{C}[/tex] = Bending moment at point C

Applying equilibrium condition to the system. Consider equilibrium of Forces along X direction

Σ [tex]F_{x}[/tex] = 0

[tex]N_{C}[/tex] = 0 N

Consider equilibrium of Forces along Y direction

Σ [tex]F_{y}[/tex] = 0

[tex]V_{C}[/tex] - 600 ( 1 ) + [tex]B_{y}[/tex] - 900 = 0

[tex]V_{C}[/tex] = 600 - 1733.33 + 900

[tex]V_{C}[/tex] = 233.33 N

Take moment about point C

Σ [tex]M_{C}[/tex] = 0

- [tex]M_{C}[/tex] - 600 ( 1 ) ( 1 / 2 * 1 ) +  [tex]B_{y}[/tex] ( 2.5 ) - 900 ( 4 ) = 0

- [tex]M_{C}[/tex] - 300 + 2.5 ( 1733.33 ) - 3600 = 0

[tex]M_{C}[/tex] = 433.325 N

The resultant internal loading acting on the cross section are Normal force, Shear force and Bending moment

Therefore, The resultant internal loading acting on the cross section of C are as follows

Normal force [tex]N_{C}[/tex] = 0 N

Shear force [tex]V_{C}[/tex] = 233.33 N

Bending moment [tex]M_{C}[/tex] = 433.325 N

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Answer:

a) [A⁻]/[HA] = 0.227b) [A⁻]/[HA] = 0.991c) [A⁻]/[HA] = 2.667Explanation:In the Henderson-Hasselbalch equation, HA stands from an acid an A⁻ stands from its conjugate base, as follows:CH₃CH₂CO₂H = HACH₃CH₂CO₂⁻ = A⁻pH = pka + Log [A⁻]/[HA]pH = 4.874 + Log[CH₃CH₂CO₂⁻]/[CH₃CH₂CO₂H](a) 4.23 = 4.874 + Log [A⁻]/[HA]-0.644 = Log [A⁻]/[HA] = [A⁻]/[HA]0.227 = [A⁻]/[HA](b) 4.87 = 4.874 + Log [A⁻]/[HA]-0.004 = Log [A⁻]/[HA] = [A⁻]/[HA]0.991 = [A⁻]/[HA](c) 5.30 = 4.874 + Log [A⁻]/[HA]0.426 = Log [A⁻]/[HA] = [A⁻]/[HA]2.667 = [A⁻]/[HA]

Explanation:

The highest precision for determining a particle's position will rise as the maximum accuracy for determining its velocity will fall.

The pace at which an object's position changes as perceived from a particular point of view and as measured by a particular unit of time (for example, 60 km/h northbound) is defined as its velocity. Velocity is a fundamental concept in kinematics, the branch of classical mechanics that deals with the motion of bodies.

In order to be defined, the physical vector quantity known as velocity needs to have both a magnitude and a direction. In the SI, speed is expressed in meters per second (m/s or m/s1), a coherently derived unit (metric system). Speed is the magnitude of a scalar absolute value of velocity.

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The design factor or multiplier of the wire rope is 5.

Design factor means the ratio of the ultimate failure strength of a member or piece of material or equipment to the actual working stress or intended safe load.

The design factor or multiplier of the wire rope is calculated as follows;

D.F = maximum strength / load

D.F = 10,000 / 2000

D.F = 5

Thus, the design factor or multiplier of the wire rope is 5.

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Answer:

d = 2.70 g/mL

Explanation:

search the next one up on go ogle it will give you an answer i promise

The volume of the solid is [tex]V=128\frac{r^{3} }{3}[/tex]

What do you understand by Volume ?

A liquid, solid, or gas's volume is the amount of three-dimensional space it occupies. Although there are many different units that can be used to indicate volume, the most common ones are liters, cubic meters, gallons, milliliters, teaspoons, and ounces.

base is x2+y2=(2r)2

==>y=-√(4r2-x2) ,√(4r2-x2)

So each cross section parallel has base = √(4r2-x2) - -(√(4r2-x2)) = 2√(4r2-x2) and height = base

So area of each cross section is 2√(4r2-x2)*2√(4r2-x2)= 4(4r2-x2)

Now we integrate from left side of circle to right side of circle (-2r to 2r)

V = 4 ∫[ -2r to 2r] (4r2-x2)dx

V = 4 (4r2x - x3/3) [ -2r to 2r]

V = 4 [(4r2(2r) - (2r)3/3) - (4r2(-2r) - (-2r)3/3)]

V = 4 [ (8r3 - 8r3/3) - (-8r3 + 8r3/3)]

V = 4 (16r3 - 16r3/3)

V = 4 (32r3/3)

V = 128r3/3

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The correct option is (b) 1.25

The CPI of the project is 1.25. Earned Value (EV) is divided by Actual Cost (AC) to determine CPI.

CPI is calculated as follows: EV / AC. In this case, 250 / 200 = 1.25.

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The work done is 51.3 lb ft.

f = 19 lbs

moves a chair from x = 1.9 to x = 4.6 ft

W = [tex]\int\limits^b_aF {x} \, dx[/tex]

W = 51.3 lb ft

The work done is 51.3 lb ft.

Every time a force pushes something over a distance, work is done.

By multiplying the force by the distance moved in the force's direction, you may determine the energy transferred, or work done.

Energy transmitted equals work done, which is force times the distance travelled in the force's direction.

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When listening to this issue, add 10.5% by mass glucose solution. We must ascertain the density, modularity, and morality of the answer. Given currently 10.5% by mass glucose solution, 1.3 milliliters.

Molarity = 54.50 M

Explanation:

Thus, a 100 g solution would contain 10.5 g of glucose. Therefore, the solvent in this instance has a huge mass and is a solution. That is 100 g less the solute’s mass.

Molarity is defined as the number of moles of a solute in 1 liter of solution. It has mol/l unit.

Molar mass of glucose, C6H12O6 = (6*12) + (1*12) + (16*6)

= 72 + 12 + 96 = 180g/mol

Density of glucose solution = 1.03g/ml

Density in g/l = 1.03g/ml * 1ml/10^-3l

= 1030g/l

10.5% mass of glucose = 10.5/100 * 180

= 18.9g/mol

Molarity = density (g/l)/molar mass (g/mol)

= 1030/18.9

= 54.50 M

Therefore, we arrive at the solution of 54.50M

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Two locomotives with a speed of 150 km/h each, reach the other in: 1.9 min

The formula of reach time and procedure we will use to solve this problem is:

Tr = x/(v2+v1)

Where:

Information about the problem:

Applying the reach time formula we get:

Tr = x/(v2+v1)

Tr =  9.5 km/(150 km/h + 150 km/h)

Tr = 9.5 km/(300 km/h)

Tr = 0.032 h

By converting the time units from (h) to (min) we have:

0.032 h * (60 min / 1h) = 1.9 min

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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A cyclist starts from rest and accelerates at 4.0 m/s^2 for 3.0 s. After that, the biker travels for 20 seconds at a steady speed. The cyclist travels 258 meters.

This kind of motion is described as the motion of an item traveling in a straight line while maintaining a constant speed along that path while it traverses equal distances in similar amounts of the time, regardless of the length of the time.

A body's acceleration must be zero if it is moving rectilinearly and is doing so consistently.

When an object is travelling uniformly, its speed remains constant. When an item moves uniformly, its displacement is given by the formula x=vt, where v stands for constant velocity and t for the motion's time interval.

Given by, is the displacement of a motion with constant acceleration.

v is constant velocity

t is time interval of the motion.

Given by, is the displacement of a motion with constant acceleration.

[tex]x=v_{i}t+\frac{1}{2}at^{2}[/tex], where

It has a constant acceleration of a

[tex]v_{i}[/tex] is the motion's time interval, and t is the beginning velocity.

Answer and justification

Given: The cyclist's starting speed is,

[tex]v_{i}[/tex]=0

The cyclist's initial acceleration is 4 m/s2.

The span of time during which motion has a constant acceleration is,

[tex]t_{1}[/tex]=3s

The cyclist's displacement in 3 seconds will be,

[tex]x_{1}= v_{i}t_{1}+\frac{1}{2}at_{1}^{2}=0(3)+\frac{1}{2}(4)(3)^{2}=18m[/tex]

After 3 seconds, the cyclist's final speed will be,

[tex]v_{f}= v_{i}+at_{1}=0+4(3)=12m/s[/tex]

t2=20s is the time interval for a cyclist traveling at a steady speed.

The biker will move x2 in the following 20 seconds at a constant speed,

x2=[tex]v_{f}t^{2}[/tex]=(1/2)(20)=240m

The biker will have covered a total distance of

x=x1+x2=18+240=258m.

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On hoods where sashes open vertically, work with the hood sash in the lowest position.

In the event of a fire, the fume hood sash offers a containment space. It functions as a blast barrier. The sash itself, together with the bypass grill above the sash, controls the fume hood's airflow properties. The sash's position does regulate the air velocity traveling through the fume hood, even if it has no effect on the amount of air passing through the fume hood. Air velocity is another element that affects chemical vapor capture. Raising the sash reduces the capture velocity, allowing vapors to start flowing over the sill and into the room's air.

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The average acceleration of the baseball is 9417.8 m/s².

To find the average acceleration, the given values are,

Initial velocity = 0

Final velocity = 43.4 m/s

Distance = 0.1 meters.

Acceleration formula can be written as,

        Acceleration,  a = (v - u ) / t m/s²

where, a - acceleration

v - Final velocity

u - Initial velocity

T - Time

Acceleration can be found by,

v² = v₀² + 2a ( x - x₀)

Rearranging the equation,

43.4² = 0 + 2a ( 0.1 m)

1883.56 = 0.2 a

a = 1883.56 / 0.2

a = 9417.8 m/s².

The acceleration of the baseball is 9417.8 m/s².

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The average speed of a horse that gallops a distance of 10 km in a time of 30 min is: b. 20km/h.

The formula and procedure we will use to solve this problem is:

v = x/t

Where:

Information about the problem:

By converting the time units from (min) to (h) we have:

t = 30 min * 1 h/60 min

t= 0.5 h

Applying the velocity  formula we get:

v = x/t

v = 10 km/0.5 h

v = 20 km/h

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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The statement is incorrect as the Speed of anything cannot be negative.

The speed of a body is a scalar quantity and the speed of anybody may be defined as the distance covered by the body per unit of time. the speed of anybody is represented in the form of Distance and time as:

Speed = Distance/time

As both Distance and time are quantities that can never have a negative value therefore the speed of a body also can never have a negative value. In this statement a student refers to a bird and says that its speed is - 7m/s which indicates that the speed is negative that is why this statement is wrong as speed can never have a negative value. The speed of a body is always positive or zero.

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The temperature when the pressure in the thermometer is 6.00 atm is T2= 30.933 K

As specified by the IUPAC since 1982, one mole of an ideal gas has a volume of 22.710947(13) litres at standard conditions of temperature and pressure (273.15 K and precisely 105 Pa).

continuous volume,

Constant = PT

P equals pressure.

temperature, or T

Then

TTtri=PPtri

PPtriTtr = 273.16 SoT

Water's triple point temperature is i.

We have provided

P =0.0630 atm

T =348 K

T = 273.16 is the triple point value.

P/Ptri

Ptri = 273.16 then.

PT= 273.16 × 0.0630/348

Ptri = 0.0494 atm.

P =0.00560 atm

Ideal gas is present here at constant volume.

Thus, PT = Constant

P2T2=P1T1

T2 = P2

T1P1=0.00560×348

=0.0630

T2= 30.933 K

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By using the power formula, the resistance of the bulb is 121 Ω.

We need to know about dissipated power to solve this problem. Power is energy dissipated to resistance as heat energy. It can be determined as

P = I . V

where P is power, I is current and V is voltage.

From Ohm's Law, we can substitute the current to

I = V / R

Hence, we can write the power equation to

P = (V/R) . V

P = V² / R

From the question above, we know that:

P = 100 watt

V = 110 volt

By substituting the following parameters, we get

P = V² / R

100 = 110² / R

R = 121 Ω

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Required wavelength is λ = 0.0119 nm

The Compton effect in physics is defined as the phenomenon that arises when a specific beam is dispersed on a specific particle with an increase in wavelength.

Given;

The campton scattering is k = 30 kev

The speed of light is c = 2.9979 X 10 ⁸ m/s

The planck's constant is h = 6.626 X 10⁻³⁴

The expression from Campton shift is given by,

λ' - λ = λc (1 - Cos∅)

Here,  ∅ is the angle of scattering whose value is 180° for maximum energy transfer and λc is the campton wavelength whose value is

λc = h/mc

substitute the values in the above expression

λ' - λ = λc (1 - Cos 180°)

λ' - λ = 2 (h/mc)

Here, m is the mass of electron

On rearing the above expression

λ' =  λ + 2 (h/mc)

The expression from conservation of energy is given by,

E - E' = k

(hc/λ) - (hc/λ') = k

hc((λ' - λ)/λλ') = k

hc ((λ' - λ)/k) = λλ'

Here E and E' are the initial and final energy of electron

substitute the values in the above equation

hc (2(h/mc)/k)) = λ (λ + 2 (h/mc))

λ² + (2h/mc)λ - 2h²/mk = 0

λ² + [tex]\frac{2(6.626X10^{-34}Js)}{(9.11X10^{-31}kg) (2.997X10^{8}m/s ) }[/tex] λ - [tex]\frac{2(6.626X10^{-34}Js)}{(9.11X10^{-31}kg) (30X10^{3}evX\frac{1.6X10^{-19} }{1ev} J) }[/tex] = 0

λ² + (4.85X10⁻¹²)λ - (2X10⁻²²) = 0

On solving the above expression

λ = 1.19 X 10⁻¹¹ m

λ = (1.19 X 10⁻¹¹ m X 10⁹ nm/1m)

λ = 0.0119 m

Thus, required wavelength is λ = 0.0119 nm

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The number of p - orbital electrons in cyclopentadienyl anion are

6 electrons.

We have Cyclopentadienyl anion.

We have to determine number of p - orbital electrons in it.

Atomic orbitals are the 3-dimensional spaces around the nucleus where the probability of finding an electron is maximum.

According to the question -

The Cyclopentadienyl Anion is planar and has a continuous overlap of 5 p-orbitals with 6 electrons. It is an aromatic system  which is highly stable and has a closed shell configuration. The deprotonated form of cyclopentadiene is represented as the cyclopentadienyl anion C5H5⁻.

Hence, the number of p - orbital electrons in cyclopentadienyl anion are

6 electrons.

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