900 students attend Ridgewood Junior High School. 4% of students bring their lunch to school everyday. How many students brought their lunch to school on Thursday?

Answers

Answer 1
The answer would be x= 36.
1. Write out the problem
4/100 ?/900

2. Start to multiply the numbers
4 x 900 = 3,600

3. Divide the number by 100
3,600 divided by 100 equals 36.

Your answer is 36. So 36 students brought their lunch to school on Thursday.

I hope this helps.
900 Students Attend Ridgewood Junior High School. 4% Of Students Bring Their Lunch To School Everyday.

Related Questions

Simplify completely:
(c^-6 d^4)^1/2

Answers

Answer:

d^2/c^3

Step-by-step explanation:

write problem with negative exponent rule

(1/c^6 d^4)^1/2

combine 1/c^6 & d^4

(d^4/c^6)^1/2

use exponent rules to finish simplifying

d^2/c^3

Opposite sides are congruent.
Diagonals are perpendicular.
Exactly one pair of opposite angles are
congruent.
Diagonals are congruent.
Diagonals bisect opposite interior angles.
Consecutive interior angles are
supplementary.

Answers

Answer:

Diagonals linse

Step-by-step explanation:

A car can be rented for ​$95 per week plus ​$0.20 per mile. How many miles can be driven if you have at most ​$370 to spend for weekly​ transportation?

Answers

Answer:

1375 miles

Step-by-step explanation:

0.20x+95=370

0.20x=275

x=1375

Find the midpoint of the given line segment with the given endpoints
(-3, 8) and (2, -4)

Answers

The midpoint of the given line segment with the given endpoints

(-3, 8) and (2, -4) is (-0.5, 2)

Midpoint of coordinates

The formula for calculating the midpoint of coordinate is expressed as;

M(x, y) = (x₁+x₂/2, y₁+y₋/2 )

Given the coordinate points( -3, 8) and (2, -4)

Substitute

M(x, y) = (-3+2/2, 8-4/2)

M(x, y)= (-1/2, 4/2)

M(x, y) =(-0.5, 2)

Hence the midpoint of the given line segment with the given endpoints

(-3, 8) and (2, -4) is (-0.5, 2)

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Write the name of the metric system prefix associated with each mathematical factor. Do not use any hyphens in your answers and do not abbreviate the prefixes. Spelling counts.

Answers

The name of the metric system prefix are :  10^-6: micro , 1/100: centi , 0.001: milli, 1000: kilo

In mathematical exponents, prefixes are referred to as the alphabetic names related to the mathematical factors, such as 10⁻⁹:  it nano ,10⁻¹²: Pico and so on.In order to identify the prefixes of the metric system, we first convert from factor to exponent form.

such :

10^-6  is micro  

1/100 = 0.01x 10^2: centi

0.001 = 1x 10 ^-3 : milli

1000 =  1x 10^3 : kilo

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Write the name of the metric system prefix associated with each mathematical factor. Do not use any hyphens in your answers and do not abbreviate the prefixes. Spelling counts.

10^-6 ______________

1/100 ______________

0.001 _____________

1000 ______________

The common difference of an arithmetic series is 5 and its tenth term is 98,find its first term​

Answers

Answer:

First term = 53,

Step-by-step explanation:

a10 = a1 + (10 - 1)d so:

98 = a1 + 9*5

a1 = 98 - 45

    = 53,

A farmer uses five bushels of strawberries to make a large batch of jam. the jam is poured into 20-ounce jars. to transport the jam to the market for sale, the farmer uses crates that hold 16 jars. if a bushel is equivalent to 64 pints, how many crates will the farmer need for this batch of jam?

Answers

4 crates
64 pints = 1024 ounces
1024/20 = 51.2 so the farmer needs 52 jars to transport that much jam
52/16=3.25 so the farmer needs at least 4 crates to carry the 52 jars

What's the product of 8 and the sum of a number and 5?

Answers

Answer:

8(n+5)=5-n

Step-by-step explanation:

First it says "the product of". A product is formed when you multiply two numbers or expressions. The word "and" is used to divide the two items being multiplied. So "The product of 8 and ---" means that you are multiplying 8 and what ever follows the "and" in the problem, in this case it is "the sum of a number and 5". Since what follows the "and" is another expression, it would be written in parentheses. To this point we have: 8 * ( ?? ), where the ?? replaces the expression.

The words "the sum" means that we are adding two numbers or expressions. As with multiplication, "and" separates the two addends. The first addend in the sum is "a number" - thus we know it isn't another expression and that we need to use a variable, because we aren't told the number. You can choose any letter or figure for your variable name, so lets call it "n". The part following the "and" is the number 5. Putting it together results in (n + 5), which will now be combined with the 8 * in the product, resulting in 8 * (n + 5).

The next thing that comes in your problem is "results in". This means "is equal to" and may also be written "is". Mathematical replacement is "=". Following the "=" is another expression: "the difference between 5 and the number". A difference is subtraction and, again, the "and" represents the break between the two values. The first number is 5 the second number is "the number" meaning the same number as before, so we use the same variable. The "difference between 5 and the number" is written: 5 - n

Putting it all together: "The product of 8 and the sum of a number and 5results in the difference of 5 and the number." Translates into math as:

What is 8-6= for the sum

Answers

The value and the summation expression are 2 and -6 + 8

How to determine the value and the summation expression?

The expression is given as:

8 - 6

When expressed as a sum, the expression can be rewritten as

-6 + 8

When the expression is evaluated, we have

-6 + 8 = 2

Hence, the value and the summation expression are 2 and -6 + 8

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If (m-1÷m)=3 , find the value of m^3 - 1÷m^3​

Answers

The value of given equation i.e. [tex]m^{3} -\frac{1}{m^{3} }[/tex] is [tex]\frac{63}{8}[/tex]

Given a equation i.e.[tex]\frac{m-1}{m}[/tex]=3 and asked  to calculate the value of the equation  [tex]m^{3} -\frac{1}{m^{3} }[/tex]

To calculate the value of   [tex]m^{3} -\frac{1}{m^{3} }[/tex] , Need to use various operations like subtraction and division)

Given .[tex]\frac{m-1}{m}[/tex]=3

⇒m-1=3m ( cross multiplies 3 and m)

⇒2m=-1( subtraction is used)

⇒m=-[tex]\frac{1}{2}[/tex]( division is used)

Thefore the value of m in the given equation i.e.[tex]\frac{m-1}{m}[/tex]=3 is -[tex]\frac{1}{2}[/tex]

⇒ [tex]m^{3} -\frac{1}{m^{3} }[/tex]

Here the value of m =-[tex]\frac{1}{2}[/tex]

Substituting the value of m in the given equation

⇒[tex](\frac{-1}{2} )^{3}[/tex]-[tex](-2)^{3}[/tex]

⇒[tex]\frac{-1}{8}[/tex]+8(addition is used)

⇒[tex]\frac{64-1}{8}[/tex]

⇒[tex]\frac{63}{8}[/tex]

Therefore, the value of the given equation i.e.  [tex]m^{3} -\frac{1}{m^{3} }[/tex] is [tex]\frac{63}{8}[/tex]

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19.6 is 24.5% of what number?
- For 11 points ​

Answers

Answer:

80

Step-by-step explanation:

[tex]\frac{24.5}{100} *x = 19.6\\x = 19.6 *\frac{100}{24.5} \\x = 80[/tex]

19.6 is 24.5% of 80

Answer:

24.5% of 80= 19.6

Step-by-step explanation:

24.5% of what number is equal to 19.6

24.5

____ x = 19.6

100 100

x = 19.6 x ____

24.5

= x =80

HOPE IT HELPS

Which graph represents the equation 12 = 3x + 4y? Explain how you know.

Answers

Answer:

Graph A

Step-by-step explanation:

First, isolate the y variable and simplify

12 = 3x + 4y

-3x+12=4y

-(3/4)x+3=y

From here, you can tell that your graph has a negative slope and a y-intercept at 3.

Graph A is the only graph with a negative slope.

Find the output (y) of the function y
20x + 38 if the input (2) is -9.

Answers

A function assigns the values. The output(y) of the function y=20x + 38 if the input is -9 is -142.

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

Given the function y=20x+38, therefore, if the input of the function is -9, then the output can be calculated by substituting the value of x as -9. Therefore, we can write the function as,

y = 20x + 38

y = 20(-9) + 38

y = -180 + 38

y = -142

Hence, the output(y) of the function y=20x + 38 if the input is -9 is -142.

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5x - 8x - 7=-3x+5-7 won’t pull an answer to check my answer

Answers

combine like terms
3x-7=-3x+5-7
subtract numbers
3x-7=-3x-2
add 7 to both sides
3x=-3x+5
combine like terms
0=-3x+5+3x
0=5
there is no solution to this problem since you can’t get x on its own

a3 = 125 solve (Type integers or simplified fractions.)

Answers

Answer:

41.666 =~41.67

Step-by-step explanation:

3a=125

a=125÷3

a=41.67

Answer:

41.667

Step-by-step explanation:

3a=125

a= 125/3

a=41.667

Please help! Need answers fast

Answers

The answer is 4 because it’s an acute angle

Is the sum of –8 + 3 negative? How do you know?

Answers

Answer:

The sum is negative because the number with the greatest value is negative.

Step-by-step explanation:

If the it's the same sign add, if not subtract.

8-3=5

keep the sign of the bigger number.

-5

Hope It Helps

Sorry If I'm Wrong

Answer: Yes

Step-by-step explanation:

The answer is negative. That is because you are adding three to negative 8.

Think about it. 8 is greater than three, right?

-8 + 3 = -5

You are bringing -8 closer to 0:

-8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5...

Bring -8 three spaces closer to 0. You get -5.

Hope this helps.

solve 12n + 7p - 6n = 25p for n

Answers

Answer:

n = 3p

Step-by-step explanation:

12n + 7p - 6n = 25p

12n - 6n +7p = 25p

12n - 6n = 25p - 7p

6n = 18p

[tex]n=\frac{18p}{6}[/tex]

n = 3p

The water level in Colorado river is 2.55 m below average. a large rainfall caused The water level to rise 0.8 m. what is the water level after the rainfall?

Answers

The water level after the rainfall is 3.05m

How to calculate the measurement of the water level after the rainfall ?

The water level in colorado river is 2.55m below average

A larger rainfall happened and the water level rose by 0.8m

Therefore the water level after the rainfall can be calculated by adding the previous water level which is 2.55 by the new increase which is 0.8

= 2.55 + 0.8

= 3.05

Hence the water level after the rainfall is 3.05 m

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It took 5 hours to drive to Durham to Birmingham. The average speed was 48mph. What was the distance from Durham to Birmingham?

I need the explanation

Answers

Answer:

240 miles

Step-by-step explanation:

Because it took 5 hours going 48 miles per hour, therefore 5 x 48 =240

240 miles

Because it took 5 hours going 48 miles
per hour, therefore 5 x 48 =240

if p=(3,1) and Q=(-3,-7), find the equation of the circle that has segment PQ as the diameter (x-{?})^2+(y-{?})^2={?}

Answers

Answer:

x² + (y + 3)² = 25

Step-by-step explanation:

the centre (C) of the circle is at the midpoint of the diameter.

using the midpoint formula

midpoint = ( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

with (x₁, y₁ ) = P (3, 1 ) and (x₂, y₂ ) = Q (- 3, - 7 )

C = ( [tex]\frac{3-3}{2}[/tex] , [tex]\frac{1-7}{2}[/tex] ) = ( [tex]\frac{0}{2}[/tex] , [tex]\frac{-6}{2}[/tex] ) = (0, - 3 )

the radius r is the distance from the centre to either P or Q

using the distance formula

r = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = C (0, - 3 ) and (x₂, y₂ ) = P (3, 1 )

r = [tex]\sqrt{(3-0)^2+(1-(-3)^2}[/tex]  

 = [tex]\sqrt{3^2+(1+3)^2}[/tex]

 = [tex]\sqrt{3^2+4^2}[/tex]

 = [tex]\sqrt{9+16}[/tex]

 = [tex]\sqrt{25}[/tex]

 = 5

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

here (h, k ) = (0, - 3 ) and r = 5 , then

(x - 0 )² + (y - (- 3) )² = 5² , that is

x² + (y + 3)² = 25

 

Find the derivative of the function using the definition of derivative. g(t) = 3 t

Answers

The derivative of the function using the definition of derivative is 3.

The given function is g(t) = 3t.

We have to find the derivative of the function using the definition of derivative.

We know that,

Definition of derivative:-

The derivative of a function is the rate of change of the function's output relative to its input value.

Here,

Input value = t

Output value = g(t)

Given y = g(t), the derivative of g(t), denoted g'(t) (or dg(t)/dt), is defined by the following limit:

[tex]g'(t)= \lim_{h \to 0} \frac{g(t+h)-g(t)}{h}[/tex]

We have the function:-

g(t) = 3t

Hence, according to the data given in the question, we can write,

g'(t) =

[tex]\lim_{h \to 0} \frac{g(t+h)-g(t)}{h} \\\\ \lim_{h \to 0} \frac{3(t+h)-3(t)}{h}\\\\ \lim_{h \to 0} \frac{3t+3h-3t}{h}\\\\ \lim_{h \to 0} \frac{3h}{h}\\\\\lim_{h \to 0} 3[/tex]

g'(t) = 3

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Kareem says that the ratio 4:1 is equivalent to the ratio 12:9 because 4+8=12 and 1+8=9 is kareem correct? explain how you know.

Answers

No, Kareem is not correct because the ratio of 4:1 can never be equal to the ratio of 12:9.

Here,

Kareem says that the ratio 4:1 is equivalent to the ratio 12:9.

Because 4+8=12 and 1+8=9.

We have to find that Kareem is correct or not.

What is a ratio?

Ratios are used to determine the relationship between two numbers it indicates how many times is one number to another number.

Now,

Kareem says that the ratio 4:1 is equivalent to the ratio 12:9.

Calculate the ratio as;

12 / 9 = ( 3 x 4 ) / ( 3 x 3 ) = 4/3

So,

12 / 9 = 4 / 3

Hence, Kareem is incorrect because the ratio of 4:1 can never be equal to the ratio of 12:9.

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The cost of having a package delivered has a base fee of $9.10. every pound over 5 lbs costs an additional $0.42 per pound. write an equation that expresses the cost c in terms of w, the total weight in pounds of a package weighing over 5 lbs.

Answers

The expression c = 9.10 + 0.42(w-5) ; w > 5 will represent the cost c in terms of w, the total weight in pounds of a package weighing over 5 lbs.

How to form an equation?

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Total cost below 5 lbs = base fee

Total cost over 5 lbs = base fee + additional 0.42/pound

Let's say the total cost is c and the total pounds is w

Then,

c = 9.10 + 0.42(w-5) ; w > 5

Here for w = 6 it will gives w - 5 = 6 - 5 = 1 lbs.

Hence "The expression c = 9.10 + 0.42(w) ; w > 5 will represent the cost c in terms of w".

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Find the indicated measure(part 3)
I will give brainliest to the right answer with solution​

Answers

Answer:

VU = 120° , WX = 100°

Step-by-step explanation:

(7)

An inscribed angle is half the measure of its intercepted arc , or

the intercepted arc is twice its inscribed angle, then

arc TV = 2 × 30° = 60°

the diameter is TU then arc TU = 180°

the sum of the arcs in the circle = 360° , so

VU + TV + TU = 360°

VU + 60°  + 180° = 360°

VU + 240° = 360° ( subtract 240° from both sides )

VU = 120°

(8)

WY = 2 × 75° = 150°

WX + WY + YX = 360°

WX + 150° + 110° = 360°

WX + 260° = 360° ( subtract 260° from both sides )

WX = 100°

       

Find all the zeros of the quadratic function.


y=x^2+ 8x + 12

If there is more than one zero, separate them with commas.

If there are no zeros, click on "None".

Answers

Answer:

x=-2, -6

Step-by-step explanation:

factor the expression

y=x^2+ 8x + 12

y= (x+2)(x+6)

set the equation equal to 0, since you are finding zeros, or solutions

0=(x+2)(x+6)

split the equation into two parts

0=(x+2) and 0=(x+6)

solve the equations

you should get 2 zeros

x=-2, -6

what is 3-5b=-32 in algebra

Answers

B = 7
Because well it is

Answer:

b=7

Step-by-step explanation:

3-5b=-32

-5b=-32-3

-5b=-35

Divide both sides by -5

b=7

( I also had trouble with these kind of expressions)

Which of the following sentences contains a dangling modifier?

A. Exhausted and thirsty, Jack ran off the football field for a drink of water.
B. Embarrassed and humiliated, the singer ran off stage after forgetting the lyrics.
C. Heroically, the firefighter rescued the small child from the burning building.
D. Searching frantically, the homework was finally found and turned in.

Answers

Answer:

I'm pretty sure the answer is D

Step-by-step explanation:

I took the test

The sentence that contains a dangling modifier is D. Searching frantically, the homework was finally found and turned in.

What is a dangling modifier?

A word or phrase that modifies a term that is not explicitly expressed in the sentence is known as a dangling modifier. A modifier provides a concept's definition, clarification, or more information.

A grammatical modifier that could be mistakenly understood as being connected to a word other than the one intended is known as a hanging modifier. A hanging modifier, which usually refers to a participle, has no subject.

Therefore, the sentence that contains a dangling modifier is Searching frantically, the homework was finally found and turned in.

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NEED NOW what is (-3, 0) (0, -3) in slope-intercept form​

Answers

Answer:

y=-x-3

Step-by-step explanation:

Write in slope-intercept form, the equation is y=mx+b .

y=−x−3

Calculus Derivative Question

Answers

(a) Differentiate [tex]s(t)[/tex] to get the velocity.

[tex]s(t) = \cos(t^2 - 1)[/tex]

Use the chain rule.

[tex]u = t^2 - 1 \implies \dfrac{du}{dt} = 2t[/tex]

[tex]s(u) = \cos(u) \implies \dfrac{ds}{du} = -\sin(u)[/tex]

[tex]\implies \dfrac{ds}{dt} = \dfrac{ds}{du} \dfrac{du}{dt} = \boxed{-2t\sin(t^2-1)}[/tex]

(b) Evaluate the derivative from (a) at [tex]t=0[/tex].

[tex]\dfrac{ds}{dt}\bigg|_{t=0} = -2\cdot0\cdot\sin(0^2-1) = \boxed{0}[/tex]

(c) The object is stationary when the derivative is zero. This happens for

[tex]-2t \sin(t^2 - 1) = 0[/tex]

[tex]-2t = 0 \text{ or } \sin(t^2 - 1) = 0[/tex]

[tex]t = 0 \text{ or } t^2 - 1 = n\pi[/tex]

(where [tex]n[/tex] is any integer)

[tex]t = 0 \text{ or } t = \pm\sqrt{n\pi + 1}[/tex]

We omit the first case. In the second case, we must have [tex]n\ge0[/tex] for the square root to be defined. Then in the given interval, we have two solutions when [tex]n=\in\{0,1\}[/tex], so the times are

[tex]t_1 = \sqrt{1} = \boxed{1}[/tex]

[tex]t_2 = \boxed{\sqrt{\pi + 1}} \approx 2.035[/tex]

(d) A picture is worth a thousand words. See the attached plot. If you're looking for a verbal description, you can list as many features of the plot as are relevant, such as

• intercepts (solve [tex]s(t)=0[/tex] to find [tex]t[/tex]-intercepts and evaluate [tex]s(0)[/tex] to find the [tex]s[/tex]-intercept)

• intervals where [tex]s(t)[/tex] is increasing or decreasing (first derivative test)

• intervals where [tex]s(t)[/tex] is concave upward or concave downward (second derivative test; at the same time you can determine any local extrema of [tex]s(t)[/tex], which you can see in the plot agrees with the critical points found in (c))

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