9. Use the following data. 15, 24, 32, 46, 46, 58. Match the measures on the left with the values on the right.
1. median
2. mode
3. mean
4. range
​

Answer:

0.2

Step-by-step explanation:

Answer: 2000

Step-by-step explanation:

The pattern is multiplying by 10. Therefore, 200 x 10= 2000

Answer:

Step-by-step explanation:

400,000

The solution to the given inequality (-4 < 16 - 4x) is x < 5.

Hence, option B) x < 5  is the correct answer.

Given the in equality in the question;

-4 < 16 - 4x

First, rewrite the inequality such that x is on the left side.

-4x + 16 > -4

Subtract 16 from both sides

-4x + 16 - 16 > -4 - 16

-4x > -20

Divide both sides by -4

Note that when dividing both sides of an inequality by a negative value, the inequality sign flips direction.

-4x/-4 < -20/4

x < -20/-4

x < 5

The solution to the given inequality (-4 < 16 - 4x) is x < 5.

Hence, option B) x < 5  is the correct answer.

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Answer:

3 : 2 : 1

Step-by-step explanation:

Simplest ratio

6oz : 4oz : 2 oz

Divide each by 2

6oz/2 : 4oz/2 : 2 oz/2

3 oz:  2 oz:  1 oz

3 : 2 : 1

Answer:

5

Step-by-step explanation:

PEMDAS

14-8+6+4-11

14-8=6

6+6=12

12+4=16

16-11=5

Answer:Not there yet

Step-by-step explanation: Think about it your close 2/9 = nothing why do numbers determine our grades so don't answer if anything flunk out of school

Answer:

160

Step-by-step explanation:

If 80% of the frogs in a pond are spring peppers, and there are 200 frogs in the pond, to find how many spring peppers are in the pond, find 80% of 200.

[tex]\begin{aligned} \sf \implies 80\% \textsf{ of }200 & = \sf 80\% \times 200\\\\& = \sf \dfrac{80}{100} \times 200\\\\& = \sf \dfrac{80}{100} \times \dfrac{200}{1}\\\\& = \sf \dfrac{80 \times 200}{100 \times 1}\\\\& = \sf \dfrac{16000}{100}\\\\& = \sf 160\end{aligned}[/tex]

Therefore, there are 160 spring peppers in the pond.

The solution by substitution of values to 4 ) is ( - 8 ) / 14 and 6 ) is - 213 .

4 ) Using substituition

By replacing values of c and d in given equation

( 5 [tex]c^{2}[/tex] - [tex]d^{2}[/tex] + 3 ) / ( 2 c - 4 d )

c = - 1 and d = - 4

( 5 [tex]( - 1 )^{2}[/tex] - [tex]( - 4 )^{2}[/tex] + 3 ) / ( 2 ( - 1 ) - 4 ( - 4 ) )

= ( 5 - 16 + 3 )  / ( - 2 + 16 )

= ( - 8 ) / 14

6 ) Using substituition

By replacing values of x and y in given equation

3 [tex]| x + y |^{2}[/tex] - [tex]( x y )^{2}[/tex]

x = 3 and y = - 5

3 [tex]| 3 + ( - 5 ) |^{2}[/tex] - [tex]( 3 * ( - 5 ) )^{2}[/tex]

( 3 * 4 ) - 225

= - 213

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Answer:

d I'm leaning towards d

Step-by-step explanation:

a doesn't make sense B can't be because we went adding d is phrased wrong

Answer:

the Answer is c yo I know it bro

Answer: C

Step-by-step explanation:

x^2 + 6x + 8 = (x + 2 )(x + 4 )

The rounding off a number of 493 is 490 and The rounding off a number of 917 is 920.

Rounding off number:

1)Round the number up if 5, 6, 7, 8, or 9 follow the number you are rounding.

2)Round the number down if the rounded number is followed by a 0, 1, 2, 3, or 4.

The given numbers are 493 and 917

The rounding-off number of 493 is

⇒493, The last number is 3, need to decrease and round off⇒490

The rounding-off number of 917 is

⇒917, The last numberis 7, need to increase and round off⇒920

Therefore, The rounding off a number of 493 is 490 and The rounding off a number of 917 is 920.

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Answer:

25 and 32

Step-by-step explanation:

32 - 25 = 7

32 x 25 = 800

Answer: its not equal.

Step-by-step explanation:

-6y + 4 = 2 (-3y + 2)

|4y + 12| = 4 (y + 3)

Answer: option D

Step-by-step explanation:

Given equation:

P = 6 w + 8 [eq1]

l=2w+4 [where l is length]

using eq1 we have:

6w=P-8

w=(P-8)/6

hence  option D

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There are 5,000 nails in five boxes. The first and second boxes have 2,700 nails altogether. The second and third boxes have 2,000 nails altogether. The third and fourth boxes have 1,800 nails altogether. The fourth and fifth boxes have 1,700 nails altogether. How many nails are in each box

Purchases of both small and large boxes total:

two little boxes.

six huge boxes

Two equations must be created with the given data in order to answer the unknowns:

150X + 400Y = 2700 (the price of the boxes and the total number of nails, where X is the small boxes and Y the large boxes)

Y = 3X

Equation one is then changed to equation 2, and variable X is eliminated:

150X + 400 (3X) = 2700

150X + 1200X = 2700 1350X = 2700 X = 2700/1350 X = 2

In order to determine the number of big boxes, equation 2's value of X is finally changed:

Y = 3X

Y = 3

Y = 6

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The first mistake in solving the given algebraic expression is; Line 3

We are given the algebraic expression as;

6(2y + 6) = 4(9 + 3y)

The first step would be to use distributive property of algebra to expand the bracket to get;

12y + 36 = 36 + 12y

The next step will be to use subtraction property of equality to subtract 36 from both sides to get;

12y = 12y

Now, since the coefficients of the variable is the same on both sides, then it means the equation has no solution and as such the conclusion is that the first mistake is in line 3.

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The solution to the given inequality is -10 < x < 5.

To solve a compound inequality involving the and operation, we solve each inequality, then find the intersection of these solutions.

For this problem, the inequality is given by:

-12 < 0.5(4x + 16) < 18.

Multiplying all the terms by 2:

-24 < 4x + 16 < 36

Hence:

4x + 16 > -24

4x > -40

x > -10.

4x + 16 < 36

4x < 20

x < 5

The intersection of these two solutions is:

-10 < x < 5.

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The domain of the function is  (-∞,∞) and the simplified expression is x²-6x-40 .

A function's domain and range are its constituent parts. A function's  range is its potential output, whereas its domain is the set of all possible input values. Range, Domain, and Function. A is the domain and B is the co-domain if a function f: A B exists that maps every element of A to an element in B. 'b', where (a,b) R, provides the representation of an element 'a' under a relation R. The set of images is the function's range.

The given functions are

f(x)=6x+24

g(x)=x²-16

Now we have to find (g-f)(x) .

(g-f)(x)=x²-16-6x-24

or,(g-f)(x)=x²-6x-40

or,(g-f)(x)=x²-10x+4x-40

or,(g-f)(x)=x(x-10)+4(x-10)

or,(g-f)(x)=(x-10)(x+4)

So the domain of the function (g-f)(x) are the values for which the function exists. we can see that the function exists for all values of x.

Domain in set builder notation={x|x∈R}

Domain in interval notation=(-∞,∞)

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The measurement of the given angle is a 90 degree.

According to the statement

We have to find that the measurement of this angle.

So, For this purpose, we know that the

An angle is formed when two straight lines or rays meet at a common endpoint. The common point of contact is called the vertex of an angle.

From the given information:

In the given figure, the measurement of the angle we have to find.

A 90-degree angle is a right angle and it is exactly half of a straight angle. It always corresponds to a quarter turn.

And from the figure it is clearly visible that the line of the angle exactly matches with the 90 degree.

Then the angle is 90 degree.

So, The measurement of the given angle is a 90 degree.

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Answer: 309.73

Step-by-step explanation:

The height of the ball according to the function h(t) is 16 feet after 1.92 seconds and after 0.46 seconds.

A function is defined as a expression containing one or more variables.

Technically speaking, a function is a means of linking a set of inputs to a set of outputs.

The height of the ball  at any time t is given by the function:

[tex]h(t)=-16t^2+38t+2[/tex]

Now the required height of the ball(in feet) is 16 feet. We have to find the value of t for which h(t)=16.

Let us substitute the values:

[tex]\implies h(t)=-16t^2+38t+2\\\implies 16=-16t^2+38t+2\\\implies 16t^2-38t+14=0\\\implies 8t^2-19t+7=0[/tex]

This is in the form of a quadratic equation in t.

Solving by using the quadratic formula:

We know that for a quadratic equation [tex]ax^2+bx+c=0[/tex]

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

Therefore for the above quadratic equation:

[tex]t=\frac{-(-19)\pm \sqrt{(-19)^2-4(8)(7)}}{2(8)}\\t=\frac{19+\sqrt{137}}{8},t=\frac{19-\sqrt{137}}{8}\\t=1.919...,t=0.455...[/tex]

Therefore the ball reaches the height of 16 feet at times 1.92 seconds and at 0.46 seconds.

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Answer:

5 days.

Step-by-step explanation:

The food will last her 5 days.
[tex]3\frac{1}{2}-\frac{5}{8}-\frac{5}{8}-\frac{5}{8}-\frac{5}{8}-\frac{5}{8}[/tex]
[tex]=1\frac{5}{8}-\frac{5}{8}-\frac{5}{8}[/tex]
[tex]=1-\frac{5}{8}[/tex][tex]=\frac{3}{8}[/tex]

Answer:

(n ÷ 4) + 6 = 8

Step-by-step explanation:

Pretty sure I answered this before, but here you go.

Quotient means The answer when you divide' So we are working in the division.

n ÷ 4 is the division part

It says 'and' which can also mean addition. So we add 6. So far our equation is: (n ÷ 4) + 6 (Brackets are needed as we are dividing n by 4 and not dividing n by 4+6)

Lastly it says the answer must be 8 so we add that at the end. So the answer is:

(n ÷ 4) + 6 = 8

Answer:

Carl and Alex are wearing hats.

Step-by-step explanation:

If Bob doesn't isn't wearing a hat, then Carl is, so Carl clearly is wearing a hat.

Now let's look at Alex. If he wasn't wearing a hat, then Bob would be wearing one. (If Alex doesn't wear a hat, then Bob wears

a hat). The logical conclusion is that Alex must be wearing a hat as well.

The width of each column is 3.375.

According to the statement

We have to find that the width of the each column.

So, For this purpose, we know that the

Width is the the horizontal measurement taken at right angles to the length.

In other words, It is the distance from one side to the other side which measures across a particular shape or object whose lengths are forming right angles with the sides as in the case of a rectangle.

From the given information:

A production assistant must divide a page of text into two columns. If the page is 6 3/4 inches wide.

Then

width of the page = 27/4 inches

And the number column is divided into page = 2

Then

The width of column = width of the page/ column in a page

The width of column = 27/4/ 2

The width of column = 6.75/ 2

The width of column = 3.375.

So, The width of each column is 3.375.

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Suppose [tex]x>0[/tex]; then the curves meet when

[tex]x^2 + \dfrac5{12} = 2 - \dfrac83 x \implies x^2 + \dfrac83 x - \dfrac{19}{12} = \left(x + \dfrac{19}6\right) \left(x - \dfrac12\right) = 0 \\\\ \implies x = \dfrac12[/tex]

By symmetry, they intersect at [tex]x=\pm\frac12[/tex].

We also see that [tex]\min\left\{f(x):|x|\le\frac34\right\} = \frac5{12}[/tex] and [tex]\max\left\{g(x):|x|\le\frac34\right\} = 2[/tex] at [tex]x=0[/tex]. [tex]f[/tex] and [tex]g[/tex] are continuous, so it follows that

[tex]\min\left\{f(x),g(x) :|x|\le\frac34\right\} = \begin{cases} f(x) & \text{if } |x| < \frac12 \\ g(x) & \text{if } |x| > \frac12 \\ f\left(\pm\frac12\right) = g\left(\pm\frac12\right) = \frac23 & \text{if } x = \pm\frac12 \end{cases}[/tex]

Compute the area [tex]\alpha[/tex]. Taking advantage of symmetry again, we have

[tex]\alpha = \displaystyle 2 \int_0^{1/2} \int_0^{f(x)} dy\,dx + 2 \int_{1/2}^{3/4} \int_0^{g(x)} dy \, dx \\\\ ~~~~ = 2 \int_0^{1/2} f(x) \, dx + 2 \int_{1/2}^{3/4} g(x) \, dx \\\\ ~~~~ = \left. 2 \left(\frac{x^3}3 + \frac{5x}{12}\right) \right\vert_0^{1/2} + \left. 2 \left(2x - \frac{8x^2}6\right) \right\vert_{1/2}^{3/4} \\\\ ~~~~ = \left(\frac12 - 0\right) + \left(\frac32 - \frac43\right) = \frac23[/tex]

and it follows that [tex]9\alpha = \boxed{6}[/tex].