79 tens X 27 tens with rounding

The Graph is not linear.

To graph f, we graph the equation y = f(x). To this end, we use the techniques outlined in Section 1.2.1. Specifically, we check for intercepts, test for symmetry, and plot additional points as needed. To find the x-intercepts, we set y = 0. Since y = f(x), this means f(x) = 0. f(x) = x2−x−6 0 = x2−x−6 0 = (x−3)(x+2) factor x−3=0 or x+2=0 x = −2,3 So we get (−2,0) and (3,0) as x-intercepts. To find the y-intercept, we set x = 0. Using function notation, this is the same as finding f(0) and f(0) = 02 − 0 − 6 = −6. Thus the y-intercept is (0, −6). As far as symmetry is concerned, we can tell from the intercepts that the graph possesses none of the three symmetries discussed thus far. (You should verify this.) We can make a table analogous to the ones we made in Section 1.2.1, plot the points and connect the dots in a somewhat pleasing fashion to get the graph below on the right. y x f(x) (x, f(x)) −3 6 (−3,6) −2 0 (−2,0) −1 −4 (−1,−4) 0 −6 (0, −6) 1 2 3 4 5 6 7 −3−2−11 2 3 4 1 −6 (1, −6) 2 −4 (2, −4) 3 0 (3, 0) 4 6 (4, 6)

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Answer:

You have a fixed cost ($20) and a variable cost ($2*number of hours you rent the bike)

Cost = Variable Cost + Fixed Cost

Let y = your Cost and x = the number of hours you rent the bike.  The fixed cost is $20.

y = ($2 per hour)*(x hours) + $20

y = 2x + 20

Answer:

110

Step-by-step explanation:

13x - 20 + 7x = 180

20x -20 = 180

20x = 200

x = 10

13(10) - 20

=110

Answer: 117.39%

Step-by-step explanation:

5 Litre x 1000 ml         (1 litre=1000ml)

=5000 ml

5000÷250

=20 glasses

20 x 25p = 500p (£1 = 100p)

£(500÷100)=£5.00

5.00-2.30/2.30 x 100%

=2.7/2.3 x 100%

≈117.39%

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The width and length of the field are 160ft and 200ft respectively

When both the given variables are related to each other, we are required to consider one variable as x and the other as a function of x to solve accordingly

Let the width of the football field be 'x' ft.

then according to given data,

length= 200 ft more than width= (x+200)ft

According to given,

Perimeter of the given field =2L+2W=1040

where L is length and W is the width

Now putting the values of length and width earlier derived, we get:

2(x)+2(x+200) =1040

2x+2x+400=1040

4x+400=1040

4x=1040-400

4x=640

x=160ft

Now, the width of the field= x=160ft

length of the field= x+200=160+200=360ft

Hence the length and the width of the field are 160ft and 360ft

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Answer:

$1.47 per yard

Step-by-step explanation:

3 feet = 1 yard

9 feet = 3 yards

set up a proportion

[tex]\frac{3}{4.41} = \frac{1}{x}[/tex]

cross multiply; 3x = 4.41 * 1

3x = 4.41

divide both sides by 3

x = 1.47

$1.47 per yard

Answer: [tex]-15x^6y^4[/tex]

Step-by-step explanation:

(-3x^2 y)(5x^4 y^3)=

-3x^2 *5x^4 *y*y^3=

-3*5*x^2 *x^4 *y^4=

-15*x^(2+4) *y^4=[tex]-15x^6y^4[/tex]

Answer:

Here in the picture is the prime factorisation of 13824

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In linear equation, -7 m - 2 is number makes the expression equivalent.

What in mathematics is a linear equation?

Given expression is  1/2 (-14m+ 4 )

To simplify this expression  1/2 (-14m+ 4 ) we get equivalent expression.

Multiply and Divide the expression by two.

⇒ -14m/2 + 4/2

To simplify the expression again, we get,

⇒ -7 m - 2

So, we found the coefficient of m is -7

The missing number is -7

Hence, –0.7 makes the expression equivalent.

Therefore,1/2 (-14m+4) = -7 m - 2

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No, It is not possible that f is continuous on [ 4 , 5 ] is non-constant, and takes on only integer values.

Here,

A function f defined on [ 4 , 5 ].

We have to find, is it possible to f is continuous on [ 4 , 5 ], is non-constant, and takes on only integer values.

What is Intermediate value theorem?

Intermediate value theorem states that if “f” be a continuous function over a closed interval [a, b] with its domain having values f(a) and f(b) at the endpoints of the interval, then the function takes any value between the values f(a) and f(b) at a point inside the interval.

Now,

A function f defined on [ 4 , 5 ].

Assume that the function,

f :  [ 4 , 5 ] → Z is a non constant continuous function.

Then, f(4) and f(5) both are integers and not equal to each other.

By, Intermediate value theorem;

Function f takes all real numbers between f(4) and f(5) at least once.

These would contain all non integers rational and irrational number between f(4) and f(5), contradicting the assumption that function takes only integer values.

Hence, It is not possible that f is continuous on [ 4 , 5 ] is non-constant, and takes on only integer values.

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Answer:

-1

Step-by-step explanation:

[tex]\frac{4-2}{-7-(-5)}=\frac{2}{-2}=-1[/tex]

The value of the function for f(5) is 15,651.

The given function is [tex]f(x)=x^{6}+x^{2} +1[/tex].

We need to find the value of f(5).

Functions are the fundamental part of calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x. Mapping or transformation is used to denote a function in math.

Now, put x=5 in the function [tex]f(x)=x^{6}+x^{2} +1[/tex] and simplify.

That is, f(5)=[tex]5^{6} +5^{2} +1[/tex]

=15,625+25+1

=15,651

Therefore, the value of the function for f(5) is 15,651.

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Answer: 13x

Step-by-step explanation: Multiply x to 11 and 2

11x+2x=13x

Answer:

6

Step-by-step explanation:

5*6 is 30 - 7 is 23

work backwards

The values a = 1/3 and b = 1/6.

Given function is, f(x) =  

                                       [tex]\frac{x^2-4}{x-2}\ \ \ if\ x < 2 \\ax^2-bx+3 \ \ \ if\ 2\leq x < 3\\2x-a+b\ \ \ if\ x\geq 3[/tex]

The interval in which the function is defined is broke down into three. They are: x<2, 2≤x<3 and x≥3.

Now the function [tex]\frac{x^2-4}{x-2}[/tex] is continuous except at x = 2. But this function is defined in the interval x>2. The other two function are defined as polynomial, so are continuous any way.

So for the whole function f(x) to  be continuous, we need to check the continuity at x = 2, x = 3.

When x = 2,  [tex]\frac{x^2-4}{x-2}[/tex] =[tex]\frac{(x+2)(x-2)}{x-2}=x+2 = 4[/tex]  and [tex]ax^2-bx+3[/tex] = 4a-2b+3

⇒  4a-2b+3 = 4

⇒4a- 2b-1 = 0, for the function to be continuous at x = 2.

When x = 3,  [tex]ax^2-bx+3[/tex] = 9a-3b+3 and 2x-a+b = 6-a+b

⇒ 9a-3b+3 = 6-a+b

⇒ 10a -2b-3 = 0, for the function to be continuous at x = 3.

On solving   4a-2b-1 = 0 and 10a -2b-3 = 0 by subtracting the two,

we get, -6a+2 = 0

⇒ a = 1/3 and therefore, b = 1/6

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Cordniate of c would be (-11,-1).

by a factor of one half the cornet of C would be what? So let's list the coordinates of A. B. C. D. First. So a is at -4 -2. And B is at negative to positive too. C is at 2:04 and D is at two negative two. Okay. So if I'm going to dilate by a scale factor of one half, that means I'm going to divide everything by two. So a prime would be negative two comma negative one. So negative two negative one. Oops. Would be a prime. You erased that at the dot that I did. And then be prime would be at negative one comma one. So be prime would be at negative one, comma one. See prime Would be at 1:02 one comma two.  And d prime would be at one comma negative 11 comma negative one

So therefore the cordinates of C would be (-11,-1)

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Answer:5

Step-by-step explanation: I used this website called step-by-step calculator and then typed in your question

The speed from slowest to the fastest is Julio; Elana; Kevin; Lorena.

Given that a table shows the distance traveled by 4 cyclists as shown in attached images.

Speed ​​is defined as . The rate at which an object changes position in any direction. Speed ​​is measured as the ratio between distance and time traveled.

Firstly, we will calculate the speed of Elena.

The given distance is 20(1/2) mi or it can be written as 41/2mi and the time is 2(1/4) hr or 9/4hr.

Now, substitute the values in speed formula that is

Speed=Distance/Time

Speed=(41/2)/(9/4)

Speed=(41/2)×(4/9)

Speed=82/9 mi/hr.

Now, we will calculate its speed of Julio.

The given distance is 12(1/4) mi or it can be written as 49/4mi and the time is 1(1/2) hr or 3/2hr.

Now, substitute the values in speed formula that is

Speed=Distance/Time

Speed=(49/4)/(3/2)

Speed=(49/4)×(2/3)

Speed=49/6 mi/hr.

Further, we will calculate the speed of Kevin.

The given distance is 20(2/3) mi or it can be written as 62/3mi and the time is 1(2/3) hr or 5/3hr.

Now, substitute the values in speed formula that is

Speed=Distance/Time

Speed=(62/3)/(5/3)

Speed=(62/3)×(3/5)

Speed=62/5 mi/hr.

Furthermore, we will calculate the speed of Lorena.

The given distance is 33(1/4) mi or it can be written as 133/4mi and the time is 2(1/3) hr or 7/3hr.

Now, substitute the values in speed formula that is

Speed=Distance/Time

Speed=(133/4)/(7/3)

Speed=(133/4)×(3/7)

Speed=57/4 mi/hr.

Hence, the speeds from slowest to fastest from the given table is Julio; Elana; Kevin; Lorena.

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75% is percentage of undergraduate students are between 36 and 52 years old.

What is percentage and example?

This would be true if k=3, but k=2

because (36-44)/4 = -2 and (52-44)/4 = 2

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Answer: C

Step-by-step explanation:

A negative times a negative equals a positive.

Not sure what the question is, but both sides are equal to each other. -11=-11, so if the question is if both sides are equal, then it's true

Answer:

A. No; the input value x=3 pairs with two different output values.

Step-by-step explanation:

For this to be a function, each of the x values should have only one output value.

Hope this helps!

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Answer is 5:30.. Hope it Helps

Answer:

Area of Desert 1 = 12,000,000     Area of Desert 2 = 3,000,000

Step-by-step explanation:

x+y=15,000,000

x=4y

4y+y=15,000,000

5y=15,000,000

y=3,000,000

Answer:

Answer

Step-by-step explanation:

3 is the constant since there is no variable beside it, and 7 is the coefficient because there is a variable beside it.

The step in which Gwen made an error for the area of the shaded region in the circle is given by:

A. Step 5.

The circumference of a circle of radius r is given by:

C = 2π r.

For this problem, the circumference is of 6π units, hence the radius is given as follows:

6π = 2π r.

r = 6/2.

r = 3 units.

The area of a circle of radius r is given by pi multiplied by the radius squared, as follows:

A = πr².

The entire area of the circle englobes 360º, but we want only the area at an angle of 72º, hence it is given by:

A = (72/360) πr².

Which is where Gwen made an error, at Step 5, hence option A is correct.

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Answer:

Step-by-step explanation:

d)

[tex]\displaystyle\\\frac{h}{2h+5} +\frac{5}{6} =\\\\\frac{h*6+5*(2h+5)}{(2h+5)*6} =\\\\\frac{6h+2h(5)+5(5)}{2h(6)+5(6)} \\\\\frac{6h+10y+25}{12h+30} =\\\\\frac{16h+25}{12h+30}[/tex]

g)

[tex]\displaystyle\\\frac{3n}{(2n-1)^2} -\frac{5}{2n-1} =\\\\\frac{3n*1 -5*(2n-1)^}{(2n-1)^2}=\\\\\frac{3n(1)-2n(5)-1(-5)}{(2n-1)^2}=\\\\\frac{3n-10n+5}{(2n-1)^2} =\\\\\frac{-7n+5}{(2n-1)^2}[/tex]

Answer:

Top to bottom

1

30

9

45

Step-by-step explanation:

The function is a continuous random variable. The correct option is B.

Continuous random variables are those that have a large number of uncountable possible values. There are countless possible values. In this illustration, there is no limit to the range of possible values for the height of a giraffe in meters, such as 10.5m, 15.22m, 12.0m, etc. There are countless options.

Discrete Variables that have a finite number of possible outcomes are known as random variables. When a dice is rolled, for example, the outcomes could be 1, 2, 3, 4, 5, or 6. There are only six possible values, with nothing in between.

Therefore, the function is a continuous random variable. The correct option is B.

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154mm

we know that  1cm = 10 mm

 therefore      15cm= 10*15 mm

                               =  150 mm

and 4 mm

we get total mm= 15cm +4mm

                          = 150mm+4mm

                           = 154 mm                  

mm stands for millimeters and cm stand for centimeters

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