Answer:
[tex]\frac{-8}{27}[/tex]
Step-by-step explanation:
[tex]\frac{-5}{9}[/tex] - [tex]\frac{-7}{27}[/tex] Subtracting a negative is the same as adding a positive. So I would change the form to addition.
[tex]\frac{-5}{9}[/tex] + [tex]\frac{7}{27}[/tex] Now to add, we need a common denominator. Let's us 27
[tex]\frac{-5}{9}[/tex] = [tex]\frac{-15}{27}[/tex] We multiple the numerator and denominator (top and bottom) by 3 to make an equivalent fraction.
[tex]\frac{-15}{27}[/tex] + [tex]\frac{7}{27}[/tex] the bottom number stays the same and we add the top numbers
-15 + 7 = -8
[tex]\frac{-8}{27}[/tex]
Answer: -8/27
Step-by-step explanation:
[tex]\displaystyle\\-\frac{5}{9} -(-\frac{7}{27} )=\\\\-\frac{5*3}{9*3} +\frac{7}{27} =\\\\\frac{-15}{27}+\frac{7}{27}=\\\\ \frac{-15+7}{27}=\\\\ \frac{-8}{27} =\\\\-\frac{8}{27}[/tex]
Describe two methods for assessing whether or not a distribution is approximately normal.
The two most frequent normality tests for assessing a normal distribution are Shapiro-test Wilk's and Kolmogorov-Smirnov test.
What is a normal distribution?
A probability distribution that is symmetric around the mean is referred regarded as having a "normal distribution." In certain instances, it is also referred to as the "Gaussian distribution." This demonstrates that data that are near to the mean are more common than data that are far from the mean.
The two most popular normality tests are the Kolmogorov-Smirnov test and the Shapiro-test Wilk's test.
Shapiro-Wilk test: This test looks at how normal the sample data are. To do this, the sample is organized and standardized (standardizing is the conversion of data).Kolmogorov-Smirnov test: The Kolmogorov-Smirnov test is used to assess if a sample comes from a population with a specific distribution.Therefore, Shapiro-and Wilk's Kolmogorov-Smirnov tests are the two normality tests used the most frequently to evaluate a normal distribution.
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3.
A Dutch company built a submarine that can hold 10 passengers and 1
pilot. The submarine has a safety feature that will automatically raise the
submarine if it goes below the certified depth of -650 feet. To show this
feature to a buyer the submarine dove to a depth of -872 feet. The
automatic feature then raised the submarine 50 feet per minute.
5
12
5
How much time, in minutes, does it take for the submarine to reach the
certified depth? Round your answer to the nearest tenth of a minute.
Show your steps for partial credit.
12
A. 4.4 minutes
B. 12.8 minutes
C. 30.1 minutes
D. 50.6 minutes
2
Answer:
I believe the answer is C
Step-by-step explanation:
I think this because I gathered the info of -650, -872, and 50
The water level in a swimming pool decreases from 60 inches to 58.25 inches in one week. Assuming that the water level changes at a constant rate, how much did the water level decrease each day? O 0.25 in. O 0.35 in. O 1.25 in. 1.75 in.
The water level decrease each day is A. 0.25 in.
How to calculate the value?From the information, the water level in a swimming pool decreases from 60 inches to 58.25 inches in one week.
There are 7 days in a week.
Therefore, the rate if decrease per day will be:
= (60 - 58.25)/7
= 1.75 / 7
= 0.25
Therefore, the correct option is A.
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Janet weights 20 pounds more than anna if the sum of their weights is 250 lb how much does each girl weigh
Anna's weight is 115 pounds and Janet's weight is 135 pounds.
What is weight?The weight of the object is the force acting on it due to gravity in science and engineering. Weight is defined as a vector quantity in some standard textbooks, as the force of gravity acting on the object. Others define weight as just a scalar quantity, the magnitude of gravity.To find the wight of Anna and Janet:
It is assumed:
Janet is 20 pounds heavier than Anna.This means that if Anna weighs x pounds,Janet's age is then (x+20) pounds.Also,
Their combined weight is 250 pounds.So,
x+x+20 = 2502x+20=250Subtraction of both sides by 20 yields:
2x = 250-202x = 230By dividing both sides by 2, we get:
x = 115So, Anna's weight is 115 pounds and Janet's weight is 115+20=135 pounds.
Therefore, Anna's weight is 115 pounds and Janet's weight is 135 pounds.
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What does X=
And wat does angle ABD=
Answer:
What does x=
Solve for x
x=25
Answer:
Step-by-step explanation:
(5x+10)+(2x-5)= 180°
first we simplify as much as possible
so, we can add 5x + 2x to get 7x
then we do 10-5 which equals 5.
now we have
7x+5=180
subtract 5 from both sides
7x= 175
x=25
now we input x into <ABD
5x+10
5(25)+10
125+10
130
<ABD=130°
25 points plus brainliest
Answer:
1/2
Hope this helps with your question :)
Identify the vertex, axis of symmetry, and direction of the graph of each function. Compare the width of the graph to the width of the graph of f(x)=x^2
===================================================
Explanation:
Compare the equation
[tex]y = (x-2)^2 - 4[/tex]
to the vertex form
[tex]y = a(x-h)^2 + k[/tex]
we have:
a = 1h = 2k = -4The vertex is located at (h,k) = (2, -4). Nice job on getting the correct answer for the vertex.
The axis of symmetry is x = 2 since the axis of symmetry goes through the vertex. It's the vertical mirror line.
Because a = 1 is positive, the parabola opens upward. It forms a bowl shape. The vertex is the lowest point.
If a < 0, then the parabola would open downward and have a highest point.
Write these fractions as powers of ten:
1/1000 7/100 000 1/10000000 3/60000
The fractions represented as power of ten are:
a. 1×(10)⁻³
b. 7× (10)⁻⁵
c. 1 × (10)⁻⁶
d. 5 × (10)⁻⁵
Given :
a. 1/1000
we know that 1/(10)³
when we take the reciprocal, the sign changes from positive to negative.
that is, 1×(10)⁻³
b. 7/100000
we know that 7/(10)⁵
likewise, we get
that is, 1×(10)⁻⁵
c. 1/10000000
we know that 1/(10)⁷
reciprocate it, we get
1×(10)⁻⁷
d. 3/60000
rearrange it.
3/6×10000
divide it.
1/2×10000
divide and multiply by 10.
10/2×10000×10
multiply it.
5/100000
5 × (10)⁻⁵
Hence we calculated the given fractions as powers of ten.
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A woman went shopping and spent 2/3 of all the money she had. Then she lost 3/5 of what she had left after shopping. How much money did she have in the beginning if she now has $10.00.
The amount of money the women had in the beggining was $75.
Let the total amout of money the women had intially be x.
According to the questio.
A woman went shopping and spent 2/3 of all the money she had. Then she lost 3/5 of what she had left after shopping.
So, the amount of money she spent for shopping = (2/3)x = 2x/3
⇒ The amount of money she had after shopping
= x -2x/3
= 3x -2x/3
= x/3
Now, the amount of money she lost 3/5 × (x/3) = x/5
⇒ Amount of money she have after the lost of money
= x/3 - x/5
= 5x - 3x /15
= 2x/15
It is given that she have $10.
⇒ 2x/15 = 10
⇒ 2x = 150
⇒ x = 150/2
⇒ x = $75
Hence, the amount of money the women had in the beggining was $75.
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Learning Task 2. Factor the following completely.
1. x²+3x-18
2. 3x²-9x-12
3. 18x²+3x-15
4. 5x²+32x+12
5. 3x³+24
Step-by-step explanation:
13 is the answer that is need
WILL MARK BRAINLIST
Answer!!!
A horse eats 18 kg of corn in 12 days. How much does he eats in 9 days?
and also one more question
is this in
Inverse proportion
or
Direct proportion
The sum of two numbers is 72. The difference of the two numbers is 40. What are the two numbers.
Let
x
be the larger number and
y
be the smaller number.
Write an equation that expresses the information in the sentence "The sum of two numbers is 72."
Step-by-step explanation:
x + y = 72
x - y = 40
x = y + 40
so, the first equation is then
y + 40 + y = 72
2y + 40 = 72
2y = 32
y = 16
x = y + 40 = 16 + 40 = 56
I'd like 75% of my order to be 3 cupcakes and the rest cookies.
How many cookies do I get?
Answer:
1 cookie
Step-by-step explanation:
75% = 75/100
75 and 100 are both divisible by 25, therfore the simplified verision is 3/4
[tex]\frac{75}{100} /\frac{25}{25} =\frac{3}{4}[/tex]
in order to get 100% we would need to:
3/4 + num of cookies = 4/4
re-arranged by subtracting 3/4 on bith sides:
num of cookie = 4/4 - 3/4
num of cookie = 1/4
meaning 1/4 of her orders is cookies
Find the measure of each marked angle. Assume the lines are parallel.
x+4=
9x-34=
The angles are 19; 101
What are parallel lines?Parallel lines are lines in a plane that are always the same distance apart. Parallel lines never intersect.
Given:
x+4, 9x-34
As, the lines are parallel
x+4 + 9x -34 = 180
10x + 30 = 180
10x = 150
x= 150/10
x=15
Hence, the angles are x+4 = 19; 9x-34 = 135 - 34 = 101
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PLEASE HELP, URGENT, POINTS GIVEN
A sheet of paper contains a list of 5 double-digit prime numbers.
Their mean is 31, while their median and mode is 29.
The largest number is 41.
Show how you can discover the 5 prime numbers written on the sheet.
Answer:
19, 29, 29, 37, 41
Step-by-step explanation:
1. What we know: x y 29 z 41
(x+y+29+z+41)/5 =31
x y and z each >9 and prime
Possibile numbers: 11, 13, 17, 19, 23, 29, 31, 37, 41
2. (x+y+29+z+41)/5 =31
x+y+29+z+41 = (31×5)
x+y+z = (31×5) -29 -41
x+y+z = 85
z>=29
x<=29
y<=29
x and y can be 11, 13, 17, 19, 23, 29
z could be 29, 31, 37, 41
At least one if them must equal 29 because it's the mode.
So two of them must equal 56
11+29=40 so both numbers cannot be less than or equal to 40
This means y is 29 because x + z has to equal 56 and that wouldn't be possible if x equals 29.
Now we know x+z=56
Possible numbers: 19+37
I found these by doing 56- each possible number for x and seeing if that equaled a possible number for z. For example 56-11=45 but z cannot be 45 therefore x cannot be 11 and so on.
Then you just plug in the numbers!
19, 29, 29, 37, 41
This was so much fun to solve! I hope this is helpful, let me know if you have any questions! You got this :)
Use the graph to complete each statement. Drag tiles to complete the statements.
Answer: A=ellen B=Dion C=Corey D= Alex E= Corey F=Ellen
Step-by-step explanation:
Is the equation always, sometimes, or never true?
Answer:
never
Step-by-step explanation:
-1=0 is not possible
Which exponential function bests models the graph below?
A.
B.
C.
D.
D.
Option A. [tex]Y = 3(2)^{X}[/tex]
Here, looking at the graph we can see that when x = 0, the value of y will be 3. Thus, (0, 3) is a solution to the given function.
Putting x = 0 in the given options, we see that
A. y = 3(1) = 3 (as anything raised to the power is 1)
B. y = 2(1) = 2
C. y = 4(1) = 4
D. y = 3(1) = 3
Thus, we can eliminate option B and C as (0, 3) does not satisfy these equations.
Now, if we take x = 1, from the graph we can see that the value of y will be 6.
Substituting x = 1 in the remaining two options, we get
A. y = 3(2) = 6
D. y = 3(4) = 12
Thus, D is also eliminated.
Option A, y = 3(2)^x is the correct answer.
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Daniel makes $2,365 a month plus some money by commission. He gets 5% of everything he sells. If he sold $13,600 worth of items this month, what is his salary for the month?
Subtract:
-2 - 6 =
Submit
A
You have two rectangles. Each has sides of length 9 and 7. You place them together side-by-side to form a larger rectangle. Which statement about the larger rectangle cannot be true?
The correct option is B: The larger rectangle can have the length of 7, width 9+9 and the area 7×9 + 7×9.
What is defined as the rectangle?A rectangle is a confined two-dimensional shape with four sides, four corners, and four right angles (90°). A rectangle's opposite sides are equal but also parallel.The two rectangle are given with the same dimensions.
The length are given as 9 and 7.
The, both rectangle are placed such that they forms the larger rectangle;
The placing is such that side with the length of 9 units are joined together.
Thus, the new width of the rectangle will be; 7 + 7.
The length of rectangle will remain same of 9 units.
The area of rectangle = length x breadth
area of larger rectangles = 7×9 + 7×9.
Therefore, the option which correctly points the condition is option B.
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The parties to a sales contract have stipulated that a specific sum be paid by any party breaching said contract, this sum is called?
This type of sum is Liquidated damages.
What is Liquidated damages?Liquidated damages are presented in certain legal contracts as an estimate of otherwise intangible or hard-to-define losses to one of the parties.
As per the given situation we have
parties to a sales contract have stipulated that a specific sum be paid by any party
Liquidated damages occur in such a situation.
The amount of damages that the parties estimate and agree upon at the time of the contract for a breach of the agreement by either party is referred to as liquidated damages.
Regardless of the actual cost of any potential damages due to the breach of the contract, this amount becomes due immediately.
According to Section 74 of the Indian Contract Act, 1972, if parties agree a sum to be paid as damages or a penalty to be imposed for a breach, the harmed party is only entitled to that sum or penalty and no other higher or lesser sum.
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Determine whether the system is consistent. x1 x2 x3 = 7 x1 - x2 2x3 = 7 2x1 3x3 = 15
The given system is not consistent.
Given system of equations are:
[tex]x_1+x_2+x_3=7\\x_1-x_2+2x_3=7\\2x_1+3x_3=15[/tex]
Here the indeterminants are [tex]x_1,x_2,x_3[/tex]. A system of equations is consistent if it has at least one set of solution values for the indeterminants.
So we try to solve the above system of equations.
Subtracting the first two solutions, we get,
[tex](x_1+x_2+x_3)-(x_1-x_2+2x_3)= 0[/tex]
⇒ [tex]2x_2-x_3=0[/tex]
⇒ [tex]x_3=2x_2[/tex]
Rewriting all the three equations using this substitution,
[tex]x_1+x_2+2x_2=7\\x_1-x_2+4x_2=7\\2x_1+6x_2=15[/tex]
This implies,
[tex]x_1+3x_2=7\\x_1+3x_2=7\\2x_1+6x_2=15[/tex]
Since the first two equations are same, we need to solve the equations,
[tex]x_1+3x_2=7\\2x_1+6x_2=15[/tex]
Multiplying the first equation by 2 and then subtracting, we get,
0 = -1, which is impossible.
So the system has no solutions.
Hence the system is inconsistent.
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Evaluate the expression
so you write 16 but i don't speak English very good i want help you 2(6+3)-2 ok you you going multiplying 2×6=12+6=18-2=16 so 16
If a person with an hourly pay of $9.50 per hour gets a 20$ raise, what is the new hourly pay?
Percent formula, show your work
======================================================
Work Shown:
20% of $9.50 = 0.20*9.50 = 1.90
You earn an extra $1.90 on top of the $9.50 already there. So the new wage is 9.50 + 1.90 = 11.40 dollars per hour
-----------
Shortcut:
1.20*9.50 = 11.40
Think of 1.20 as 100% + 20% = 1 + 0.20 = 1.20, and this represents an increase of 20%
Liv earns $9.50 for every two bracelets she sells. the equation y = 4 . 75 x can be used to represent this situation. what is the constant of proportionality?
The Constant of proportionality represented in equation is 4.75
The Constant of Proportionality defines the value which will remain constant in the whole system of equations. In the given equation, Liv earns $9.50 for selling every two bracelets. The equation represents the sale of Liv on the basis of its price and quantity and the Total amount that she gets. The equation is represented as y = 4.75x
Here, y is the total amount she gets, x is the number of pieces that she sold, and 4.75 is the constant of proportionality. In this case, the constant can be defined as the price of one bracelet that she sells.
This constant can be derived by simply dividing the total amount by the total number of pieces that she sells. It can be represented by :
=> y/x = c , where c is the constant
=> 9.5/2 = c => c = 4.75
Hence, the Constant of Proportionality is 4.75.
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TOWERS A lookout tower sits on a network of struts and posts. Leslie measured two angles on the tower. If m∠1=7x-7°, m∠2=4x+2°, and m∠3=2x+6°, what is m∠1?
please explain the answer i want to understand how this works.
Answer:The angles in a triangle add up to 180 degrees
Which of the expressions shown evaluate to negative rational numbers? Select all that apply. Multiple select question. cross out A) ( − 9 ) 4 cross out B) ( − 4 5 ) 3 cross out C) ( − 3 8 ) 2 cross out D) 3 5 − 10 4 cross out E) ( 9 . 8 ) 2 − 10 2
The negative rational numbers are -9/ 4, -20/ 3 . Option A and B
What are rational numbers?A rational number can be defined as a number that is expressed as a fraction where both the numerator and the denominator are integers.
Examples of rational numbers are;
-1/ 2, 3/ 5, 9/ 2 -3/ 5
Given the expressions;
(-9)/ 4 = -9/4(-4 5) /3 = - 20/ 3(-3 8 ) /2 = -24/ 2 = -12(3 5) - 10/ 4 = 15 - 10/ 4 = 5/ 4(9. 8)2 - 10(2) = 72(2) - 20 = 144 - 20 = 124The rational numbers are -9/4 , -20/ 3 , 5/4
Thus, the negative rational numbers are -9/ 4, -20/ 3 . Option A and B
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1. Which of the following shows the statement 4 less than 12?
a. 4 - 12
b. 12 + 4
c. 12 - 4
d. 4 + 12
Answer:
C is correct
Step-by-step explanation: please let me know if it was rong
Help me please translations hw
The locations of the vertices are shown below:
(- 5, 4), (- 4, 4), (- 5, 2)(- 4, 1), (- 1, 2), (0, - 1), (- 2, - 5)(2, 5), (3, 4), (1, 2)(3, - 5), (- 2, - 3), (0, - 1)What are the coordinates of the images resulting from a translation?Herein we find four representations of polygons on Cartesian plane and we must determine the coordinates of the images generated by translation, a kind of rigid transformations. Translation is described by the following operation:
P'(x, y) = P(x, y) + T(x, y)
Where:
P(x, y) - Original pointP'(x, y) - Resulting pointT(x, y) - Translation vectorCase 1 (K(x, y) = (3, - 3), X(x, y) = (4, - 3), R(x, y) = (3, - 5), T(x, y) = (- 8, 7))
K'(x, y) = (3, - 3) + (- 8, 7) = (- 5, 4)
X'(x, y) = (4, - 3) + (- 8, 7) = (- 4, 4)
R'(x, y) = (3, - 5) + (- 8, 7) = (- 5, 2)
Case 2 (E(x, y) = (0, 2), X(x, y) = (3, 3), V(x, y) = (4, 0), Z(x, y) = (2, - 4), T(x, y) = (- 4, - 1))
E'(x, y) = (0, 2) + (- 4, - 1) = (- 4, 1)
X'(x, y) = (3, 3) + (- 4, - 1) = (- 1, 2)
V'(x, y) = (4, 0) + (- 4, - 1) = (0, - 1)
Z'(x, y) = (2, - 4) + (- 4, - 1) = (- 2, - 5)
Case 3 (G(x, y) = (- 4, 5), J(x, y) = (- 3, 4), U(x, y) = (- 5, 2), T(x, y) = (6, 0))
G'(x, y) = (- 4, 5) + (6, 0) = (2, 5)
J'(x, y) = (- 3, 4) + (6, 0) = (3, 4)
U'(x, y) = (- 5, 2) + (6, 0) = (1, 2)
Case 4 (V(x, y) = (0, 0), Y(x, y) = (- 5, 2), F(x, y) = (- 3, 4), T(x, y) = (3, - 5))
V'(x, y) = (0, 0) + (3, - 5) = (3, - 5)
Y'(x, y) = (- 5, 2) + (3, - 5) = (- 2, - 3)
F'(x, y) = (- 3, 4) + (3, - 5) = (0, - 1)
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Answer:
See attachments.
Step-by-step explanation:
A translation is a type of transformation that moves a figure left, right, up or down. Every point on the original figure is translated (moved) by the same distance in the same direction.
If a figure is to be moved left, subtract the number of units it is to be moved from the x-values.If a figure is to be moved right, add the number of units it is to be moved to the x-values.If a figure is to be moved up, add the number of units it is to be moved to the y-values.If a figure is to be moved down, subtract the number of units it is to be moved from the y-values.Question 1Coordinates of the given pre-image:
K = (3, -3)R = (3, -5)X = (4, -3)Given mapping rule:
[tex](x, y) \rightarrow (x-8, y+7)[/tex]
This tells us to subtract 8 from the x-values and add 7 to the y-values.
[tex]\sf \implies K(3,-3) \rightarrow K'(3-8, -3+7)=K'(-5,4)[/tex]
[tex]\sf \implies R(3,-5) \rightarrow R'(3-8, -5+7)=R'(-5,2)[/tex]
[tex]\sf \implies X(4,-3) \rightarrow X'(4-8, -3+7)=X'(-4,4)[/tex]
Question 2Coordinates of the given pre-image:
E = (0, 1)X = (3, 3)V = (4, 0)Z = (2, -4)Given mapping rule:
[tex](x, y) \rightarrow (x-4, y-1)[/tex]
This tells us to subtract 4 from the x-values and subtract 1 from the y-values.
[tex]\sf \implies E(0,1) \rightarrow E'(0-4, 1-1)=E'(-4,0)[/tex]
[tex]\sf \implies X(3,3) \rightarrow X'(3-4, 3-1)=X'(-1,2)[/tex]
[tex]\sf \implies V(4,0) \rightarrow V'(4-4, 0-1)=V'(0,-1)[/tex]
[tex]\sf \implies Z(2,-4) \rightarrow Z'(2-4, -4-1)=Z'(-2,-5)[/tex]
Question 3Coordinates of the given pre-image:
G = (-4, 5)J = (-3, 4)U = (-5, 2)Given mapping rule:
[tex](x, y) \rightarrow (x+6, y)[/tex]
This tells us to add 6 to the x-values and the y-values remain unchanged.
[tex]\sf \implies G(-4,5) \rightarrow G'(-4+6, 5)=G'(2,5)[/tex]
[tex]\sf \implies J(-3,4) \rightarrow J'(-3+6, 4)=J'(3,4)[/tex]
[tex]\sf \implies U(-5,2) \rightarrow U'(-5+6, 2)=U'(1,2)[/tex]
Question 4Coordinates of the given pre-image:
F = (-3, 4)V = (0, 0)Y = (-5, 2)Given mapping rule:
[tex](x, y) \rightarrow (x+3, y-5)[/tex]
This tells us to add 3 to the x-values and subtract 5 from the y-values.
[tex]\sf \implies F(-3,4) \rightarrow F'( -3+3, 4-5)=F'(0,-1)[/tex]
[tex]\sf \implies V(0,0) \rightarrow V'( 0+3, 0-5)=V'(3,-5)[/tex]
[tex]\sf \implies Y(-5,2) \rightarrow Y'( -5+3, 2-5)=Y'(-2,-3)[/tex]
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