4. Liness and t are parallel. Find the value of x.

The numbers in Set A = {5, 9, 12, 14, 18} that are elements of both Set B and Set C, shown below Set B = {even numbers} Set C = {multiples of 3} will be 12 and 18.

It should be noted that even numbers can be divided by 2.

The multiple of 3 in the numbers are 12 and 18 that can be divided by 2 as well.

Therefore, the numbers in Set A = {5, 9, 12, 14, 18} that are elements of both Set B and Set C, shown below Set B = {even numbers} Set C = {multiples of 3} will be 12 and 18.

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Step-by-step explanation:

if you did not leave anything out, all we can do is

T = CB - 6

T + 6 = CB

C = (T + 6)/B

The expression for the area within the circle but outside the triangle as a function of the length 3x of the side of the triangle is [tex]\frac{88r^2}{7}-\frac{9\sqrt{3} }{2}x^2[/tex].

It is given that:-

Radius of circle = 2r

Length of side of equilateral triangle = 3x

We have to find the expression for the area within the circle but outside the triangle as a function of the length 3x of the side of the triangle.

We know that,

Area of circle = [tex]\pi R^2[/tex]

Where R is the radius of the circle.

We have R = 2r

Area of an equilateral triangle = [tex]\frac{\sqrt{3} }{2}a^2[/tex]

Where, a is the length of side of equilateral triangle.

a = 3x

Hence,

Expression = [tex]\pi R^2-\frac{\sqrt{3} }{2}a^2[/tex]

Expression = [tex]\frac{22}{7}*(2r)^2-\frac{\sqrt{3} }{2}*(3x)^2 = \frac{88r^2}{7}-\frac{9\sqrt{3} }{2}x^2[/tex].

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The homogeneous linear ODE

[tex]y^{(4)} + y''' + y'' = 0[/tex]

has characteristic equation

[tex]r^4 + r^3 + r^2 = r^2 (r^2 + r + 1) = 0[/tex]

with a double root at [tex]r=0[/tex] and two complex roots

[tex]r^2 + r + 1 = 0 \implies r = -\dfrac{1 \pm i\,\sqrt3}2[/tex]

Hence the characteristic solution is

[tex]y = C_1 e^{0x} + C_2x e^{0x} + C_3 e^{((-1/2)-i(\sqrt3/2))x} + C_4 e^{((-1/2)+i(\sqrt3/2))x}[/tex]

[tex]y = C_1 + C_2x \\\\ ~~~~~~~~~~ + C_3 e^{-x/2} \left(\cos\left(\dfrac{\sqrt3}2x\right) - i\, \sin\left(\dfrac{\sqrt3}2x\right)\right) \\\\ ~~~~~~~~~~ + C_4 e^{-x/2} \left(\cos\left(\dfrac{\sqrt3}2x\right) + i\,\sin\left(\dfrac{\sqrt3}2x\right)\right)[/tex]

[tex]y = C_1 + C_2x + C_3 e^{-x/2} \cos\left(\dfrac{\sqrt3}2x\right) + C_4 e^{-x/2} \sin\left(\dfrac{\sqrt3}2x\right)[/tex]

Answer:

-(4/3) is ans by using slope formula

Answer:

e = 40h

After eleven hours, she will earn $440.00

Step-by-step explanation:

Let e = earnings

Let h = hours

e = 40h  She earns 40 for every hours that she tutors.  If she tutors for 11 hours, you would substitute aa for h to calculate her earnings.

e = 40(11)

e = 440

The solution of the expression ( 9y² - 4x )( 9y ² + 4x) will be 81y⁴ - 16x².

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given expression ( 9y² - 4x )( 9y ² + 4x) will be solved as below:-

Use the formula:- ( a + b ) ( a - b ) = a² - b²

a = 9y²

b = 4x

( 9y² - 4x )( 9y ² + 4x ) = ( 9y² )² - ( 4x )²

Therefore, solution of the expression ( 9y² - 4x )( 9y ² + 4x) will be 81y⁴ - 16x².

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Mr. Drew needs woods of a total length of 32 feet to make the sides of the sandbox.

So,

Therefore, Mr. Drew needs woods of a total length of 32 feet to make the sides of the sandbox.

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Answer:

A person will pay $5.37

Step-by-step explanation:

6.8 pounds of bananas x $0.79 per pound = $5.37.

I hope this helps and have a blessed day! :)

Answer:

Ok so "X" will ALWAYS be the first number in a ordered pair so in this case 3 WILL be the "X" value 5 will be the "Y" value. "X" is the Horizontal line on the graph you will always start with "X" so you will go over 3 times and up 5  I'm making this complicated but pretty much all you need to know is that "X" is 3

Note: I hope you have a good day and I hoped this helped! :))

The complementary solution is Ус = C₁е¯ + C₂е¯ -6x

Consider the differential equation

=y" + 7y' + 6y = 30...(1)

Rewrite the equation,(D² + 7D + 6)y = 30 where

d /D = dx

Auxiliary equation is,

f(m) = 0

3 m³ +7m+6=0

m² + 6m+m+6=0

m(m+6) +1(m+6) = 0

(m +6)(m + 1) = 0

m = −1, −6 -6

Hence,

The complementary solution is Ус = C₁е¯ + C₂е¯ -6x

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Answer: b) 9

Step-by-step explanation: if you take 3 * 9 it = 27 take that minus 6 that = 21

The values of the functions are:

a. When x =-4 then f(x) =  -x+4

b. When x = -2 then f(x) =  -x+4

c. When x = -1 then f(x) =  -x+4

d. When x=1/2 then f(x) = 3

e. When x = 2 then f(x) =  2x-5

Given, g(x) = {-x+4 , if x≤-1

                      3 ,   if -1≤x<2

                      2x-5, if x≥2 }

a. when x = -4, f(x) = ?

-4 comes under the condition x≤-1.

therefore, when x=-4 ⇒ f(x) = -x+4

f(-4) = -4+4 = 0

b. when x=-2, f(x)= ?

Again -2 comes under the condition if x≤-1

therefore when x=-2 ⇒ f(x) = -x+4

f(-2) = -2+4 = 2

c. when x=-1, f(x) = ?

-1 comes under the condition if x≤-1

therefore, when x=-1 then f(x) = -x+4

f(-1) = -1+4 = 3

d. when x=1/2 , f(x) = ?

1/2 comes under the condition, if -1≤x<2

therefore, when x=1/2 then f(x) = 3.

e. when x=2, f(x) = ?

2 comes under the condition, if x≥2

therefore, when x=2 then f(x)= 2x-5.

hence we get the required results of the given functions.

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Answer:

x = - 1 and x = 5

Step-by-step explanation:

the zeros are the values of x where the graph crosses the x- axis

the graph crosses the x- axis at x = - 1 and x = 5 , then the zeros are

x = - 1 and x = 5

A surveyor asks a friend her opinion and then asks for the names of five friends for obtain additional opinions. This is an example of convenience sampling.

Sampling is the process of choosing the group from which you will actually collect data for your study. For instance, you could interview a sample of 100 students if you were examining the viewpoints of students at your university. With the help of sampling, you can test a statistical hypothesis on the features of a population.

An elementary illustration of a convenience sampling technique is when businesses hand out their marketing materials and conduct interviews with randomly chosen participants at a mall or on a busy street.

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Answer:

1647

Step-by-step explanation:

Given the following information:

Length of traffic = 8 miles

Average Length of vehicles on the road :

Cars = 14.5 feets

Trucks = 21 feets

18 Wheeler tractor = 73 Feets

% distribution of the different vehicles :

Cars = 70% = 0.7

Trucks = 20% = 0.2

18 wheeler tractor = 10% = 0.1

Distance between vehicles = 4feets

Number of vehicles stuck in the traffic :

Let number of vehicles = v

Summation of (number of vehicles * length of each vehicle) + distance between each vehicle = Length of traffic

Total distance between each vehicle = 4(v-1)

(0.7v * 14.5) + (0.2v * 21) + (0.1v * 73) + 4(v - 1) = 8 miles

1 mile = 5280

8 miles = (5280 * 8) = 42,240

10.15v + 4.2v + 7.3v + 4v - 4 = 42240

25.65v = 42240 + 4

25.65v = 42244

v =42244 / 25.65

v = 1646.939

v = 1647.

Answer:

Step-by-step explanation:

2x+18=6y

2x=6y−18

(2x)/2=(6y−18)/2

x=3y−9

Answer:

Step-by-step explanation:

2x  +  18+− 18=6y  +  −18

2x  =  6y − 18

2x / 2= 6y −18 / 2

x  =  3y −9

The vertical asymptote of the function = ln(x-6) + 5 is option C: x = 6.

The given function is f(x) = ln(x - 6) + 5.

A vertical asymptote is a vertical line that a function approaches but never crosses as it approaches infinity or negative infinity. For a logarithmic function like ln(x), the domain of the function is restricted to positive values only since the natural logarithm is undefined for non-positive arguments.

In the given function, we have f(x) = ln(x - 6) + 5. To find the vertical asymptote, we need to identify the value of x that would make the argument of the natural logarithm equal to zero.

Let's set the argument of the natural logarithm to zero:

x - 6 = 0

Now, solve for x:

x = 6

Thus, the value of x that would make the argument of the natural logarithm zero is x = 6.

So, the correct answer is option C: x = 6.

This means that the vertical asymptote of the function f(x) = ln(x - 6) + 5 is the vertical line x = 6. As x approaches 6 from either side (but never equaling 6), the function's values approach infinity. Similarly, as x approaches negative infinity, the function's values also approach infinity. The function never crosses the vertical line x = 6.

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Answer:

nothing there

Step-by-step explanation:

The value of the function f(x) = 2x/(2x + 3).

A function is defined as a relationship between a set of inputs that each have one output.

Now, as per the question, the functions are give as;

h(x) = (2x + 3)/x

g(x) = 2/x

And, g(f (x) ) = h(x) =  (2x + 3)/x  ......(equation 1)

To estimate the value of f (x); Substitute x for f(x)

g(f (x) ) = 2/f (x)     ......(equation 2)

Equation (equation 1 and 2).

2/f (x) =  (2x + 3)/x

f (x) = 2x/ (2x + 3)

Thus, the value of the function f (x) = 2x/ (2x + 3).

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The correct question is-

The function h (x) = StartFraction 2 (x + 3) Over x EndFraction is a result of the composition (g compose f) (x). If g (x) = StartFraction 2 over x EndFraction, what is f(x)?

The correct option is (b) sample size.

In the formula for calculating the standard deviation, the letter n represent  sample size.

What is standard deviation?

Standard deviation is a statistical standard measure in finance that, when applied to an investment's annual rate of return, sheds light on its historical volatility.

Some key features regarding the standard deviation are-

A square root of a value deduced from correlating data points to a population's collective mean is used to calculate standard deviation. The formula is:

Standard Deviation = [tex]\sqrt{\frac{summation n to i=1 (x_{i}-bar x )}{n-1} }[/tex]

Where,

[tex]x_{i}[/tex]= value of the i th point the the given data set.

[tex]barx[/tex]= mean value

n = total number of data points.

Thus, the standard deviation, on the other hand, determines all ambiguity as risk, even when it is in the investor's favor, like above-average returns.

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Answer:

Step-by-step explanation:

1. a. coordinates of polygon B: (-2, 1), (-4, 1), (-2, 3), (-4, 4)

b. coordinates of polygon C: (-2, -1), (-4, -1), (-2, -3), (-4, -4)

c. coordinates of polygon D: (-2, 1), (-4, 1), (-2, 3), (-4, 4) -> same as polygon B because you after reflecting B to C, they are asking you basically reflect it back to B

2. C (-2, -1)

The price of a banana is 0.71 (after round off) USD per pound.

Here the price of a banana in Mexico was 34 pesos per kilogram.

price of a banana in Mexico = 34 pesos per kilogram

We are provided with the following information,

1 kg = 2.205 pounds,

and 1 Peso = 0.04574USD

We have to find the price in USD per pound,

So we have,

=(34 × 0.04574 )÷ 2.205

= 0.7105 USD per pound

= 0.71 USD per pound   (after round off)

Therefore the price of a banana in UDS per pound is 0.71 ( after round off) .

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The remarkable thing that was made by the Mound Builders is (C) large cities

In the Ohio River Valley, Native American tribes constructed mounds and enclosures for burial, religious, and even defense purposes. For dramatic effect, they frequently constructed their mounds on or near tall cliffs or bluffs, as well as in rich river valleys.

Mound Builders were not one particular group of people; rather, they were pre-Columbian tribal groups that erected massive earthen constructions known as mounds throughout North America. These mounds were used as houses, burial grounds, and ceremonial hubs, among other things.

In conclusion, the remarkable thing that was made by the Mound Builders is large cities.

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Answer:

[tex]\dfrac{5x^2+20x+16}{x(x+1)^2} & \equiv \dfrac{16}{x}-\dfrac{11}{(x+1)}-\dfrac{1}{(x+1)^2}[/tex]

Step-by-step explanation:

When writing an algebraic fraction as an identity, if its denominator has repeated linear factors, the power of the repeated factor indicates how many times that factor should appear in the partial fractions.

Write out the fraction as an identity:

[tex]\begin{aligned}\dfrac{5x^2+20x+16}{x(x+1)^2} & \equiv \dfrac{A}{x}+\dfrac{B}{(x+1)}+\dfrac{C}{(x+1)^2}\\\\\implies \dfrac{5x^2+20x+16}{x(x+1)^2} & \equiv \dfrac{A(x+1)^2}{x(x+1)^2}+\dfrac{Bx(x+1)}{x(x+1)^2}+\dfrac{Cx}{x(x+1)^2}\\\\\implies 5x^2+20x+16 & \equiv A(x+1)^2+Bx(x+1)+Cx\end{aligned}[/tex]

Calculate the values of A and C using substitution:

[tex]\begin{aligned}\textsf{When }x=0 \implies 16 & =A(1)+B(0)+C(0) \implies A=16\\\\\textsf{When }x=-1 \implies 1 & =A(0)+B(0)+C(-1) \implies C=-1\end{aligned}[/tex]

Substitute the found values of A and C and expand the identity:

[tex]\begin{aligned}\implies 5x^2+20x+16 & \equiv 16(x+1)^2+Bx(x+1)-x\\& \equiv 16x^2+32x+16+Bx^2+Bx-x\\& \equiv (16+B)x^2+(31+B)x+16\\\end{aligned}[/tex]

Compare the coefficients of the x² term to find B:

[tex]x^2 \textsf{ term } \implies 16+B =5\implies B & =-11[/tex]

Replace the found values of A, B and C in the original identity:

[tex]\dfrac{5x^2+20x+16}{x(x+1)^2} & \equiv \dfrac{16}{x}-\dfrac{11}{(x+1)}-\dfrac{1}{(x+1)^2}[/tex]

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Answer:

Step-by-step explanation:

11+(19+6)= (11+19)+6 so it's the associative property

Answer: The converse of this theorem is also true; that is, if two lines n and m are cut by a transversal so that the alternate interior angles are congruent, then n║m.

Step-by-step explanation:

What does it mean converse in geometry?

The converse of a statement is formed by switching the hypothesis and the conclusion. The converse of "If two lines don't intersect, then they are parallel" is "If two lines are parallel, then they don't intersect." The converse of "if p, then q" is "if q, then p."

So, in the figure below, if we can choose n║m, then ∠1≅∠2

Since  n║m , by the corresponding Angles Postulate,

∠1≅∠2.

Therefore, by the definition of congruent angles,

m∠1=m∠2

Since ∠1 and ∠2 form a linear pair, they are supplementary, so

m∠1+m∠2=180°.

Therefore, the converse of this theorem is also true; that is, if two lines n and m are cut by a transversal so that the alternate interior angles are congruent, then n║m.

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The volume required for a 5% solution is 5.7 L, while a 40% solution requires 4.3 L for the experiment.

A percentage is a fraction of a whole represented as a number ranging from 0 and 100.

The equation should be as follows:

If 'x' is the volume of a 40% solution, then the volume of a 5% solution is:

10 L = 40% solution volume + 5% solution volume

10 L = x + 5% volume of solution

10 L - x = 5% solution volume

The volume would then be calculated as follows:

(volume 20% × concentration 20%) = (volume 40% × concentration 40%)           + (volume 5% × concentration 5%)

10 litre × 20% = x litre × 40% + (10- x) litre × 5%

10 L ×  20% = x litre  × 35% + 10 litre × 5%

x litre × 35 = 10 L × 20 - 10 L × 5

                 = 10 L × 15

x litre = 10 L × 15/35

x litre = 4.28 L

x litre = 4.3 L

40% solution volume = 4.3 L

The volume of 5% solution is equal to 10 L - 4.3 L = 5.7 L.

Thus, the volume of 5% solution  requires is 5.7 L and volume of 40% solution required is 4.3 L.

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