4. Computer programmers in the 1970s thought 8 kilobytes was a lot of memory and the
computers fit the space of about 10 textbooks. Some cell phones today can store 128
Gigabytes. How many 1970 computers would it take to match the memory of a cell
phone today?

4.89g of solid magnesium nitrate (148.3 g/mol) should be added to 500 ml of 0.118 m of sodium nitrate in order to produce an aqueous 0.25 m solution of nitrate ions.

From the given info, we know that there is already the presence of nitrate already mixed in the solution. then we have to find out how more is required to be added to it.

first, we find moles of NaNO3

0.500L x 0.118 M = 0.059 moles NaNO3

this means there are 0.059 moles of[tex]NO^{-} _{3}[/tex]

Here volume is not changing, so amount of moles needed to make this concentration = 0.25M x 0.5L = 0.125 moles

0.125 - 0.059 moles = 0.066 moles of [tex]NO^{-} _{3}[/tex] required to be added in the solution.

for every 1 mole of Mg[tex](NO^{-} _{3} )_ {2}[/tex], there are 2 moles of [tex]NO^{-} _{3}[/tex].

so, we will only need half of the total moles of magnesium nitrate.

converting moles to grams,

0.033 moles Mg[tex](NO^{-} _{3} )_ {2}[/tex] x 148.3 g/mol = 4.89g Mg[tex](NO^{-} _{3} )_ {2}[/tex]

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The car which accelerates from 5.0 m/s to 21 m/s at a rate of 3.0 m/s2 travels 69.33 m

The formula for Uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:

x = (vf²-vi²)/ (2a)

Where:

Information about the problem:

Applying the distance formula, we have:

x = (vf²-vi²)/ (2a)

x = [(21 m/s)²- (5.0 m/s)²]/ (2 * 3.0 m/s²)

x = (441 m²/s²- 25 m²/s²)/ 6 m/s²

x = 416 m²/s²/ 6 m/s²

x = 69.33 m

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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Answer:

No.

Explanation:

A sceintific law cannot be changed or modified. It has been proved multiple times.

Answer:

No.

Explanation:

Scientific laws can only be changed if proven wrong. Scientists don't vote on knowledge, they use evidence to prove or disprove theories and laws.

The correct answer is option A. Water is not a state/ phase of matter

States are those phases that describe its physical attributes as well as how its constituent particles are arranged. Solid, liquid, gas, and plasma are the four main states of matter that can exist.

When something melts, it transitions from a solid to a liquid condition.

Water has a freezing point of 0°C.The melting point of flour is around 220 degrees Celsius, which is greater than that of salt and sugar. Sublimation is the process by which a solid transforms into a gaseous state, as in the case of camphor. Examples of changes in the states of matter include the melting of ice, the freezing of water, the burning of camphor, the melting of wax, and the production of precipitates.

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No, the bullet is not likely to be manufactured by Winchester.

Given:

X = 936

S=10\ss=10

We are unable to use the empirical rule since we do not know if the distribution is symmetric or skewed.

According to Chebyshev’s rule, which states that at least 89% of the data values are contained within 3 standard deviations of the mean, can be used to help us.

Overline x 3s=936 3(10) = 906 x 3s = 936 3(10) = 906

Overline x +2x = 936 + 3 (10), which becomes x +2x = 936

Thus, between 906 and 966 is the range for at least 89% of the velocities.

Empirical principle approximately 68.3 percent of the values in a data set with a symmetric distribution will be within one standard deviation of the mean, approximately 95.4 percent will be within two standard deviations of the mean, and approximately 99.7 percent will be within three standard deviations of the mean.

Usual values fall within 3 standard deviations of any mean and 1000 does not come within 3 standard deviations of the mean, thus it is unlikely that the bullet with velocity 1000 feet per second was manufactured by Winchester.

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[tex]9 m/s^{2}[/tex] is the distance traveled by the car in the 8.5 s

U = 0 (rest)

V= 76.5 m/s

t= 8.5 second

a=?

We are related

V=u+at

76.5 m/s = 0+a×8.5

⟹a= 76.5/8.5 = [tex]9 m/s^{2}[/tex]

Hence, the car's acceleration [tex]9 m/s^{2}[/tex]

The route taken by a body to travel from a starting point to an ending location in a predetermined amount of time and at a predetermined speed is known as the distance travelled. Considering a constant velocity:

Distance is calculated as time multiplied by velocity.

The formula is denoted as d = v×t.

D is the distance, as stated.

V is the speed.

t is the time.

The formula for calculating distance traveled can be used to calculate how far driving a car or swimming laps in a pool will take you.

The distance and speed while driving an automobile are measured in kilometers per hour, respectively.

The distance swim will be measured in terms of laps while doing laps in a pool.

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Heat required to evaporate the water to steam is 5342 KJ

We know that,

[tex]Q_{t}[/tex] = c * m * ( [tex]T_{f}[/tex] - [tex]T_{i}[/tex] )

where,

[tex]Q_{t}[/tex] = Heat required to raise the temperature

c = Specific heat capacity

m = Mass

[tex]T_{f}[/tex] = Final temperature

[tex]T_{i}[/tex]  = Initial temperature

Given that,

m = 230 lb = 104.33 kg

[tex]T_{i}[/tex]  = 190 F = 87.78 °C

[tex]T_{f}[/tex]  = 100 °C (Because water boils at 100 °C to turn into steam)

c = 4190 J / kg °C

[tex]Q_{t}[/tex] = c * m * ( [tex]T_{f}[/tex] - [tex]T_{i}[/tex] )

    = 4190 * 104.33 * 12.22

[tex]Q_{t}[/tex] = 5341883.79 J = 5342 KJ

Heat is the amount of energy transferred between two bodies

Therefore, Heat required to evaporate the water to steam is 5342 KJ

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Option D: John will express his brightness unit in candela.

Power, or the rate at which energy is utilized or produced over time, is measured in watts. Energy providers utilize watts to calculate the amount of electricity we use in Kilowatts per Hour (kWh), which is equivalent to 1,000 watts used for one hour.

A fundamental unit of measurement for the amount of visible light that a light source emits is called a lumen (lm), also known as luminous flux.

Simply put, to assess the power of a lamp inside a lighting fixture, look for the total number of Lumens.

In addition to the light itself, a number of other elements must be considered when estimating the amount of light that is emitted. Most lamps are housed in a light fixture that is composed of diffusers and reflectors, among other parts.

These variables, along with others like the shape and number of lights, will affect the luminaire’s brightness and light dispersion.

Luminaire efficacy considers these factors to give a more accurate estimation of the lumens generated by the entire luminaire once it is fully constructed.

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The vernal equinox in the year AD 10000 will lie in the constellation Scorpio.

Once every 25800 years a full cycle of precession is completed. There are 12 constellations which means it takes 25800 / 12 = 2150 years to move from one constellation to the next one. The order in which the vernal equinox moves from Aquarius is Capricorn, Sagittarius, Scorpio, Libra etc.

Now the year is 2022 AD where the vernal equinox just entered constellation Aquarius. In 4172 AD it would have entered constellation Capricorn, then constellation  Sagittarius in 6322 AD, then constellation  Scorpio in 8472 AD and then constellation  Libra in 10622 AD. This means that in 10000 AD it is still in constellation  Scorpio and yet to enter constellation  Libra.

Therefore, In the year 10000 AD, the vernal equinox will lie in the constellation Scorpio.

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The cardboard box will collapse when you jumped up in the air.

When they are standing over the cardboard. Cardboard is supporting our weight which results in the whole system is in equilibrium position.

In the equilibrium condition the box will not collapse. But as soon as you want to jump in the upward direction then a force has to be applied. in the upward direction there will be an acceleration according to the Newton second law.

As we know, Newton's third law states that every action has an equal and opposite reaction.

So to push the body upward, we will push the cardboard in the downward direction. With equal force by which we have to make a jump.

Due to this jump the systems equilibrium will not maintained and the box will collapse.

The cardboard box will collapse when you jumped up in the air.

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Aristotle and Ptolemy said that earth is in the center and all other planets move in a circular motion around Earth.

Aristotle from Classic Greece and Ptolemy from Roman Egypt agreed on three facts:

This model of the solar system with Earth in the center is called as Geocentric model.

Therefore, Aristotle and Ptolemy said that earth is in the center and all other planets move in a circular motion around Earth.

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The  empirical   formula  is KClO₃

Empirical formula - The simplest whole no. combination of element in that compound.

The  empirical  formula of the  compound is  calculated :

sample of compound (mass) ,M = 23.23g

potassium, k, = 7.41 g

 chlorine, cl,=  6.72

 oxygen, o, = ?

  [tex]M = k_{m} + Cl_{n} + o_{p}[/tex]

23.23g = 7.41g + 6.72g + o

o = 9.1g

the  moles  of  each  element,  (moles)  = mass/  molar  mass

moles of   K  =  7.41g/39 g/mol(molar  mass  of K)  =  0.18  moles

moles  of Cl = 6.72g/35.5 g/mol(molar  mass  of Cl) =  0.18 moles

moles of  O  =  9.1g/ 16g/mol(molar  mass of  O) = 0.57 moles

then  calculate e  mole ratio by  dividing  each  mole  by  the  smallest  number  of  moles  (  0.18 moles)

K= 0.18/0.18= 1

Cl=0.18/0.18=1

O=  0.56/0.18=3

Hence  the  empirical   formula  = KClO₃

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The initial velocity of the player, given it landed on the ground after 3.2 s is 15.68 m/s

We'll beging by obataining the time taken for the player to reach the maximum height. This can be obtannnned as follow:

T = 2t

3.2 = 2t

Divide both sides by 2

t = 3.2 / 2

t = 1.6 s

The initial velocity of the player can be obtained as follow:

v = u + gt

0 = u + (-9.8 × 1.6)

0 = u - 15.68

Collect like terms

u = 0 + 15.68

u = 15.68 m/s

Thus, we can conclude that the initial velocity of the player is 15.68 m/s

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A seismograph is a device called that uses special weights and magnetic fields to measure the movement of the ground.

A seismograph is a particular device that records seismic waves caused by an earthquake, explosion, or other earth-shaking events. Seismographs have electromagnetic sensors that convert ground motions into electrical changes that are processed and recorded by the instrument's analog or digital circuits.

The terms "seismograph" and "seismometer" are frequently used interchangeably; however, while both devices can detect and measure seismic waves, only a seismograph can record them. A seismogram is a record produced by a seismograph on a display screen or paper printout.

 Although originally designed to detect natural earthquakes, seismographs have a wide range of applications, including petroleum exploration, research into the Earth's crust and lower layers, and monitoring volcanic activity.

Seismographs are devices that record the movement of the ground during an earthquake. They are installed on the ground as part of a seismographic network all over the world. 

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It is true that when graphically adding vectors in two dimensions, each vector arrow begins at the origin and proceeds in the direction of the vector for a distance proportional to the magnitude of the vector.

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The dielectric strength of a dielectric substance is equal to the greatest magnitude of the external electric field that does not cause electrical breakdown. When an electric field is applied to a dielectric, the dielectric will transform into a conductor at a point known as electrical break down.

Given that

A parallel plate capacitor consists:

Capacitance Co

Plates of Area A

Separation distance between the plates d

Voltage of a battery Vo

Magnitude of charge Qo

Dielectric constant K=3

the capacitance of parallel plate capacitor when there is free space between the plates is given by

Co = εoA/d

Where εo is permittivity of free space.

If the battery is connected to the parallel plate capacitor, the gap between the plates is filled with dielectric constant. The capacitance of the parallel plate capacitor for the medium will then be determined.

a) C=KεoA/d

=3εoA /d

=3 Co

Now, the potential difference between the plates will be

b) Vo =QC

Vo=QC

Hence, the magnitude of charge by adding dielectric medium will be

c) Q= CVo

=3εoA Vo /d

=3 Co Vo

=3 Qo

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A wireless NIC performs the same functions as a wired NIC except that an antenna or sensor is used instead of wired connection.

NIC in known as network interface. Traditionally NIC is done using wiring from source to receiver. As technology advanced we started using wireless NIC.

In an wireless NIC, antennas or sensors will be present to receive and send signals. The signals are send and received as electromagnetic waves also called as EM waves.

Therefore, a wireless NIC performs the same functions as a wired NIC except that an antenna is used instead of wired connection.

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Answer:

D. The slope is 4, and the y-intercept is 12.

Explanation:

Use slope formula.

y2-y1/x2-x1

Points are (-3, 0) and (-2, 4)

4-0/-2+3=

=4/1=4

Slope is 4.

Use point slope formula.

y-y1=m(x-x1)

y-0=4(x+3)

y=4x+12

The y-intercept is 12.

D. The slope is 4, and the y-intercept is 12.

Hope this helps!

Please mark as brainliest if correct!

The velocity, acceleration and speed are -

v(t) = - 7sin t [tex]i[/tex] + 6cos t [tex]j[/tex]

a(t) =  - 7cos t [tex]i[/tex] - 6sin t [tex]j[/tex]

s(t) =  [tex]\sqrt{(7cos\;t) ^{2} +(6sin\;t)^{2} }[/tex]

We have the position vector → r(t) = 7cos(t) i +  6sin(t) j

We have to determine the velocity, acceleration and speed of particle.

The instantaneous velocity and acceleration can be calculated using -

v = [tex]$\frac{dx}{dt}[/tex]

a = [tex]$\frac{dv}{dt}[/tex]

According to the question, we have -

r(t) = 7cos(t) i +  6sin(t) j

The velocity can be calculated using -

v(t) = [tex]$\frac{dr(t)}{dt} = \frac{d}{dt}\;(7 cos\;t \;i + 6 sin\;t\;j)[/tex] = - 7sin t [tex]i[/tex] + 6cos t [tex]j[/tex]

The acceleration can be calculated using -

a(t) = [tex]$\frac{dv(t)}{dt} = \frac{d}{dt}\;(-7 sin\;t \;i + 6 cos\;t\;j)[/tex] = - 7cos t [tex]i[/tex] - 6sin t [tex]j[/tex]

The speed at time t can be found out as follows -

|r(t)| = [tex]\sqrt{(7cos\;t) ^{2} +(6sin\;t)^{2} }[/tex]

Hence, the velocity, acceleration and speed are -

v(t) = - 7sin t [tex]i[/tex] + 6cos t [tex]j[/tex]

a(t) =  - 7cos t [tex]i[/tex] - 6sin t [tex]j[/tex]

s(t) =  [tex]\sqrt{(7cos\;t) ^{2} +(6sin\;t)^{2} }[/tex]

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What Newton discovered is that  gravity extends throughout the universe.

The term gravity refers to the force that acts on a body in the universe. It is gravity that makes an object to fall when it is thrown up. The force of gravity acts on every object in the universe and it extends through the universe.

Humans have always known about gravity when they fall from a height and when they threw things up. However, human did not know that gravity extends throughout the universe.

Thus, what Newton discovered is that  gravity extends throughout the universe.

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Your body weight is the gravitational attraction between you and the Earth.

Gravity, which means "weight" in Latin, is a basic interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions. As a result, it has no appreciable impact on subatomic particle level phenomena. On Earth, gravity imparts weight to tangible items, and the Moon's gravity creates tides in the oceans. However, gravity is the most important interaction between objects at the macroscopic scale, determining the motion of planets, stars, galaxies, and even light.

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Newton's optics experiment observation and intervention. In order to make his observations, Newton used the theory of light passing through prisms and the rays that were sent by them. It was revealed that light has a variety of properties and features.

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I added an image of the answers/ Hope this helps! good luck on it.

The degree of the elevation is 3.3

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Assuming a perpetual inventory system and using the weighted average method, the weighted average unit is determined as $11.44 after the October 22 purchase.

The Weighted Average Cost (WAC) method of inventory valuation in accounting uses a weighted average to establish the COGS and inventory levels.

The price of the products up for grabs is divided by the quantity of them in the weighted average cost technique.

The WAC technique is appropriate under both GAAP and IFRS accounting. Weighted Average Cost (WAC) Method Formula

Weighted Average Unit Costs = [360 units×$12 + (320-180) ×$10] / [360+(320-180)]units}

Weighted Average Unit Costs = $5720 / 500 units

Weighted Average Unit Costs = $11.44

Costs of goods that are offered for sale are calculated using beginning inventory value plus acquisitions.

Units available for sale are the number of units that can be sold by a company or the total number of units that are in its inventory.

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Use the fundamental theorem of calculus.

[tex]\displaystyle \vec v(t) = \vec v(0) + \int_0^t \vec a(u) \, du[/tex]

[tex]\displaystyle \vec v(t) = \vec k + \int_0^t (6\,\vec\imath+6\,\vec\jmath) \, du[/tex]

[tex]\boxed{\vec v(t) = 6t\,\vec\imath + 6t\,\vec\jmath + \vec k}[/tex]

[tex]\displaystyle \vec r(t) = \vec r(0) + \displaystyle \int_0^t \vec v(u) \, du[/tex]

[tex]\displaystyle \vec r(t) = \vec\imath + \displaystyle \int_0^t (6t\,\vec\imath + 6t\,\vec\jmath + \vec k) \, du[/tex]

[tex]\boxed{\vec r(t) = (3t^2 + 1)\,\vec\imath + 3t^2\,\vec\jmath + t\,\vec k}[/tex]

The velocity vector is v(t) = 6t i + 3t j + k, and the position vector is r(t) = [tex]\rm 3t^2 i + (3/2)t^2 j + kt + i.[/tex]

We have to integrate the specified acceleration vector to obtain the velocity vector of the particle before integrating the velocity vector to obtain the position vector of the particle.

So, the acceleration vector: a(t) = 6i + 3j

We will the find the velocity vector,

To find the velocity vector, we integrate the acceleration vector with respect to time 't':

∫a(t) dt = ∫(6i + 3j) dt

when we integrate with respect to time 't' that gives us:

v(t) = 6t i + 3t j + C

where 'C' is the constant of integration.

Using the initial velocity condition to find 'C':

Given initial velocity: v(0) = k

Substitute t = 0 into the velocity vector equation:

v(0) = 6(0) i + 3(0) j + C

k = C

So, C = k

We put the value of 'C' back into the velocity vector equation:

v(t) = 6t i + 3t j + k

Calculate the position vector r(t):

To find the position vector, we integrate the velocity vector with respect to time 't':

∫v(t) dt = ∫(6t i + 3t j + k) dt

Integrating with respect to time 't' gives us:

r(t) = [tex]\rm 3t^2 i + (3/2)t^2 j + kt + D[/tex]

where 'D' is the constant of integration.

We use the initial position condition to find 'D':

Given initial position: r(0) = i

Substitute t = 0 into the position vector equation:

r(0) = [tex]\rm 3(0)^2 i + (3/2)(0)^2 j[/tex]+ k(0) + D

i = D

So, D = i

when we put the value of 'D' back into the position vector equation:

r(t) = [tex]\rm 3t^2 i + (3/2)t^2 j + kt + i[/tex]

Therefore, the velocity vector is v(t) = 6t i + 3t j + k, and the position vector is r(t) = [tex]\rm 3t^2 i + (3/2)t^2 j + kt + i.[/tex]

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On mars the rock that fall from rest in 6.5 s with an acceleration due to gravity of 3.77 m/s² would far a distance of: 79.64125 m

The free fall formula and the procedure we will use is:

h = (g * t²)/2

Where:

Information of the problem:

Applying final height formula we get:

h = (g * t²)/2

h = (3.77 m/s² * (6.5 s)²)/2

h = (3.77 m/s² * 42.25 s²)/2

h = 159.2525 m/2

h = 79.64125 m

It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.

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The best strategy for teaching a toddler or pre-schooler to throw is to simply play lots of throwing games with them without providing instruction. This will enable children to learn the fundamentals of throwing as their muscle coordination gradually improves over time.

Throw me a ball is an expression used to launch a ball through the air To abruptly place in a particular state or situation Please don't throw rubbish on the ground. He was thrown in jail to cause to tumble .The horse hurled its rider to put on or take off in a fast Let me throw on a coat.

Overhand, underhand, and throws made with both hands are among the different kinds. Underhand throws are typically made below the shoulder, whereas overhand throws are typically made above.

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Particle dislodgement in the filtration process is generally undesirable, except during high pressure jets of water applied to filter media during a backwash.

Filtration is a physical separation procedure that uses a filter medium with a complicated structure that only allows fluid to pass through it to separate solid particles and liquid from a combination. Filtrate is the term for the liquid that passes through the filter medium and is used to describe solid particles that are too large to pass. Larger-than-average particles have the potential to blind the filter by blocking the filter lattice and forming a filter cake on top of the filter. The term "effective pore size" refers to the size of the biggest particles that may successfully pass through a filter.

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Answer:

New concentration of A =3 [A] Put the values we get new rate of reaction. − dtd[R]=k[3A] 2[B] Hence, the rate of reaction will increase by 9 times. (iii) Given that. New concentrations of A=2[A] New concentration of B=2[B] Plug the values we get.

Explanation:

The rate using the rate constant and the given concentrations [tex]\( \text{rate} = 2.1897 \text{ mol/L.s} \)[/tex].

The rate law for the reaction is given as: [tex]\rm \[ \text{rate} = k \times [a]^2 \times [b] \][/tex]

where:

[tex]\[ [a] = 4.11 \text{ mol/L} \]\\\ [b] = 3.71 \text{ mol/L} \][/tex]

[tex]\rm \[ k \][/tex] is the rate constant (to be determined)

To find the rate, we need to calculate the rate constant [tex](\( k \))[/tex] and then substitute the given concentrations of [tex]\( [a] \)[/tex] and [tex]\( [b] \)[/tex] into the rate law.

Step 1: Calculate the rate constant [tex](\( k \))[/tex] using the provided rate value and concentrations.

[tex]\[ \text{rate} = 2.1897 \text{ mol/L.s} \]\\\[k = \frac{\text{rate}}{[a]^2 \times [b]} \]\[k = \frac{2.1897 \text{ mol/L.s}}{(4.11 \text{ mol/L})^2 \times 3.71 \text{ mol/L}} \][/tex]

Step 2: Calculate the rate using the rate constant and the given concentrations.

[tex]\[ \text{rate} = k \times [a]^2 \times [b] \]\[ \text{rate} = \left(\frac{2.1897 \text{ mol/L.s}}{(4.11 \text{ mol/L})^2 \times 3.71 \text{ mol/L}}\right) \times (4.11 \text{ mol/L})^2 \times 3.71 \text{ mol/L} \]\[ \text{rate} = 2.1897 \text{ mol/L.s} \][/tex]

The correct result is [tex]\( \text{rate} = 2.1897 \text{ mol/L.s} \)[/tex].

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A worker at the top of a 459-m-tall television transmitting tower accidentally drops a heavy tool. If air resistance is negligible, how fast (in m/s) is the tool going just before it hits the ground?

The rule of conservation of energy (the heavy tool’s potential energy at a height of 551 meters above the ground becomes its kinetic energy at ground level) allows us to determine the speed of the object when it hits the ground:

PE=KE

Since mgh=1/2mv2, the mass can cancel out.

In the case where g=9.81m/s2, gh=1/2v2

V=√2gh

=√2*9.81m/s2*459

=3 m/s

It’s possible for an object to have both kinetic and potential energy at once. For instance, a falling object that has not yet hit the ground has both kinetic and potential energy because it is traveling downward and has the capacity to go still further.

The mechanical energy of an object is the total of its potential and kinetic energies.

A falling object loses potential energy while gaining kinetic energy. The difference between the increase in kinetic energy and the decrease in potential energy is exact.

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