11. A shopkeeper bought a sewing machine for 3,500, If he wants to earn a profit of 20% c
a discount of 20% to the customer, what should be the marked price?

Answer:

9 9 years 9999999999999

There are 5,000 nails in five boxes. The first and second boxes have 2,700 nails altogether. The second and third boxes have 2,000 nails altogether. The third and fourth boxes have 1,800 nails altogether. The fourth and fifth boxes have 1,700 nails altogether. How many nails are in each box

Purchases of both small and large boxes total:

two little boxes.

six huge boxes

Two equations must be created with the given data in order to answer the unknowns:

150X + 400Y = 2700 (the price of the boxes and the total number of nails, where X is the small boxes and Y the large boxes)

Y = 3X

Equation one is then changed to equation 2, and variable X is eliminated:

150X + 400 (3X) = 2700

150X + 1200X = 2700 1350X = 2700 X = 2700/1350 X = 2

In order to determine the number of big boxes, equation 2's value of X is finally changed:

Y = 3X

Y = 3

Y = 6

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The domain of the function is  (-∞,∞) and the simplified expression is x²-6x-40 .

A function's domain and range are its constituent parts. A function's  range is its potential output, whereas its domain is the set of all possible input values. Range, Domain, and Function. A is the domain and B is the co-domain if a function f: A B exists that maps every element of A to an element in B. 'b', where (a,b) R, provides the representation of an element 'a' under a relation R. The set of images is the function's range.

The given functions are

f(x)=6x+24

g(x)=x²-16

Now we have to find (g-f)(x) .

(g-f)(x)=x²-16-6x-24

or,(g-f)(x)=x²-6x-40

or,(g-f)(x)=x²-10x+4x-40

or,(g-f)(x)=x(x-10)+4(x-10)

or,(g-f)(x)=(x-10)(x+4)

So the domain of the function (g-f)(x) are the values for which the function exists. we can see that the function exists for all values of x.

Domain in set builder notation={x|x∈R}

Domain in interval notation=(-∞,∞)

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Answer:x/5 + 2b/5

Step-by-step explanation:

9a-2b=c+4a solve for a

9a-2b=c+4a

add -4a to both sides

9a-4a-2b=x+4a-4a

5a-2b=x

add 2b to both sides

5a-2b+2b=x+2b

5a= x+2b

divide by 5

5a/5 = x/5 +2b/5

a= x/5 + 2b/5

The solution to the given inequality (-4 < 16 - 4x) is x < 5.

Hence, option B) x < 5  is the correct answer.

Given the in equality in the question;

-4 < 16 - 4x

First, rewrite the inequality such that x is on the left side.

-4x + 16 > -4

Subtract 16 from both sides

-4x + 16 - 16 > -4 - 16

-4x > -20

Divide both sides by -4

Note that when dividing both sides of an inequality by a negative value, the inequality sign flips direction.

-4x/-4 < -20/4

x < -20/-4

x < 5

The solution to the given inequality (-4 < 16 - 4x) is x < 5.

Hence, option B) x < 5  is the correct answer.

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The first mistake in solving the given algebraic expression is; Line 3

We are given the algebraic expression as;

6(2y + 6) = 4(9 + 3y)

The first step would be to use distributive property of algebra to expand the bracket to get;

12y + 36 = 36 + 12y

The next step will be to use subtraction property of equality to subtract 36 from both sides to get;

12y = 12y

Now, since the coefficients of the variable is the same on both sides, then it means the equation has no solution and as such the conclusion is that the first mistake is in line 3.

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Answer:

0.2

Step-by-step explanation:

Answer: 2000

Step-by-step explanation:

The pattern is multiplying by 10. Therefore, 200 x 10= 2000

Answer:

5

Step-by-step explanation:

PEMDAS

14-8+6+4-11

14-8=6

6+6=12

12+4=16

16-11=5

Answer:

160

Step-by-step explanation:

If 80% of the frogs in a pond are spring peppers, and there are 200 frogs in the pond, to find how many spring peppers are in the pond, find 80% of 200.

[tex]\begin{aligned} \sf \implies 80\% \textsf{ of }200 & = \sf 80\% \times 200\\\\& = \sf \dfrac{80}{100} \times 200\\\\& = \sf \dfrac{80}{100} \times \dfrac{200}{1}\\\\& = \sf \dfrac{80 \times 200}{100 \times 1}\\\\& = \sf \dfrac{16000}{100}\\\\& = \sf 160\end{aligned}[/tex]

Therefore, there are 160 spring peppers in the pond.

Answer: its not equal.

Step-by-step explanation:

-6y + 4 = 2 (-3y + 2)

|4y + 12| = 4 (y + 3)

Answer:

1

Step-by-step explanation:

the answer is 1.21576655000000000.

the unit of this no. is 1.

Answer:

(n ÷ 4) + 6 = 8

Step-by-step explanation:

Pretty sure I answered this before, but here you go.

Quotient means The answer when you divide' So we are working in the division.

n ÷ 4 is the division part

It says 'and' which can also mean addition. So we add 6. So far our equation is: (n ÷ 4) + 6 (Brackets are needed as we are dividing n by 4 and not dividing n by 4+6)

Lastly it says the answer must be 8 so we add that at the end. So the answer is:

(n ÷ 4) + 6 = 8

Answer:Not there yet

Step-by-step explanation: Think about it your close 2/9 = nothing why do numbers determine our grades so don't answer if anything flunk out of school

Answer:$49.50

Step-by-step explanation:

First you have to find what 10% of 55 is. So if you times 10% by 55 you come out with $5.5. So after that you must subtract 5.5 from 55 which comes out to $49.50.

Answer: -5,9

Step-by-step explanation:

The solution to the given inequality is -10 < x < 5.

To solve a compound inequality involving the and operation, we solve each inequality, then find the intersection of these solutions.

For this problem, the inequality is given by:

-12 < 0.5(4x + 16) < 18.

Multiplying all the terms by 2:

-24 < 4x + 16 < 36

Hence:

4x + 16 > -24

4x > -40

x > -10.

4x + 16 < 36

4x < 20

x < 5

The intersection of these two solutions is:

-10 < x < 5.

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Answer:

  17 bars

Step-by-step explanation:

Peter wants to compute the maximum number of bars he can load safely if the load limit of 1200 kg and the bar weight of 60 kg are each rounded to the number of significant digits those numbers have.

The error in a rounded number is assumed to be as much as half of the least significant digit of the number.

Peter's load limit may actually be as low as ...

  1200 kg - (1/2)(100 kg) = 1150 kg . . . . . . . 1200 is rounded to nearest 100

Peter's bar weight might be as high as ...

  60 kg + (1/2)(10 kg) = 65 kg . . . . . . . . . . . 60 is rounded to nearest 10

If Peter has maximum-weight bars and does not want to exceed the minimum his load limit might be, the number of bars he can load is ...

  (1150 kg) / (65 kg/bar) ≈ 17.7 bars

The greatest number of bars Peter can load safely is 17.

The measurement of the given angle is a 90 degree.

According to the statement

We have to find that the measurement of this angle.

So, For this purpose, we know that the

An angle is formed when two straight lines or rays meet at a common endpoint. The common point of contact is called the vertex of an angle.

From the given information:

In the given figure, the measurement of the angle we have to find.

A 90-degree angle is a right angle and it is exactly half of a straight angle. It always corresponds to a quarter turn.

And from the figure it is clearly visible that the line of the angle exactly matches with the 90 degree.

Then the angle is 90 degree.

So, The measurement of the given angle is a 90 degree.

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Answer:

Carl and Alex are wearing hats.

Step-by-step explanation:

If Bob doesn't isn't wearing a hat, then Carl is, so Carl clearly is wearing a hat.

Now let's look at Alex. If he wasn't wearing a hat, then Bob would be wearing one. (If Alex doesn't wear a hat, then Bob wears

a hat). The logical conclusion is that Alex must be wearing a hat as well.

Answer:

d I'm leaning towards d

Step-by-step explanation:

a doesn't make sense B can't be because we went adding d is phrased wrong

The height of the ball according to the function h(t) is 16 feet after 1.92 seconds and after 0.46 seconds.

A function is defined as a expression containing one or more variables.

Technically speaking, a function is a means of linking a set of inputs to a set of outputs.

The height of the ball  at any time t is given by the function:

[tex]h(t)=-16t^2+38t+2[/tex]

Now the required height of the ball(in feet) is 16 feet. We have to find the value of t for which h(t)=16.

Let us substitute the values:

[tex]\implies h(t)=-16t^2+38t+2\\\implies 16=-16t^2+38t+2\\\implies 16t^2-38t+14=0\\\implies 8t^2-19t+7=0[/tex]

This is in the form of a quadratic equation in t.

Solving by using the quadratic formula:

We know that for a quadratic equation [tex]ax^2+bx+c=0[/tex]

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

Therefore for the above quadratic equation:

[tex]t=\frac{-(-19)\pm \sqrt{(-19)^2-4(8)(7)}}{2(8)}\\t=\frac{19+\sqrt{137}}{8},t=\frac{19-\sqrt{137}}{8}\\t=1.919...,t=0.455...[/tex]

Therefore the ball reaches the height of 16 feet at times 1.92 seconds and at 0.46 seconds.

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Answer:

25 and 32

Step-by-step explanation:

32 - 25 = 7

32 x 25 = 800

Answer:

3 : 2 : 1

Step-by-step explanation:

Simplest ratio

6oz : 4oz : 2 oz

Divide each by 2

6oz/2 : 4oz/2 : 2 oz/2

3 oz:  2 oz:  1 oz

3 : 2 : 1

Answer: option D

Step-by-step explanation:

Given equation:

P = 6 w + 8 [eq1]

l=2w+4 [where l is length]

using eq1 we have:

6w=P-8

w=(P-8)/6

hence  option D

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Suppose [tex]x>0[/tex]; then the curves meet when

[tex]x^2 + \dfrac5{12} = 2 - \dfrac83 x \implies x^2 + \dfrac83 x - \dfrac{19}{12} = \left(x + \dfrac{19}6\right) \left(x - \dfrac12\right) = 0 \\\\ \implies x = \dfrac12[/tex]

By symmetry, they intersect at [tex]x=\pm\frac12[/tex].

We also see that [tex]\min\left\{f(x):|x|\le\frac34\right\} = \frac5{12}[/tex] and [tex]\max\left\{g(x):|x|\le\frac34\right\} = 2[/tex] at [tex]x=0[/tex]. [tex]f[/tex] and [tex]g[/tex] are continuous, so it follows that

[tex]\min\left\{f(x),g(x) :|x|\le\frac34\right\} = \begin{cases} f(x) & \text{if } |x| < \frac12 \\ g(x) & \text{if } |x| > \frac12 \\ f\left(\pm\frac12\right) = g\left(\pm\frac12\right) = \frac23 & \text{if } x = \pm\frac12 \end{cases}[/tex]

Compute the area [tex]\alpha[/tex]. Taking advantage of symmetry again, we have

[tex]\alpha = \displaystyle 2 \int_0^{1/2} \int_0^{f(x)} dy\,dx + 2 \int_{1/2}^{3/4} \int_0^{g(x)} dy \, dx \\\\ ~~~~ = 2 \int_0^{1/2} f(x) \, dx + 2 \int_{1/2}^{3/4} g(x) \, dx \\\\ ~~~~ = \left. 2 \left(\frac{x^3}3 + \frac{5x}{12}\right) \right\vert_0^{1/2} + \left. 2 \left(2x - \frac{8x^2}6\right) \right\vert_{1/2}^{3/4} \\\\ ~~~~ = \left(\frac12 - 0\right) + \left(\frac32 - \frac43\right) = \frac23[/tex]

and it follows that [tex]9\alpha = \boxed{6}[/tex].

Perimeter = 18 units; Area = 9 sq. units

GH = √(-4-4)²+(1-1)² = 8 units

HI = √(4-0)²+(1+2)² = 5 units

IG = √(0+4)²+(-2-1)² = 5 units

Perimeter of the given triangle = 8+5+5=18 units

Semi-perimeter of triangle = 18÷2=9 units

Using Heron's formula; √[s(s-a)(s-b)(s-c)]=Area of triangle;

A= √(9)(9-8)(9-5)(9-5)

  = √(9)(3)(3)

  = 9 sq. units

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Answer:

B

Step-by-step explanation:

I am not sure what kind of help you need here. the answer is kind of obvious, already revealed by the names of the lines (AB and CB). they meet or intersect at their joined point B.